Q. Which of the following compounds undergoes electrophilic substitution most readily?
A.
Toluene
B.
Benzene
C.
Nitrobenzene
D.
Chlorobenzene
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Solution
Toluene undergoes electrophilic substitution most readily due to the electron-donating effect of the methyl group, which activates the benzene ring.
Correct Answer: A — Toluene
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Q. Which of the following compounds undergoes elimination more readily?
A.
1-bromopropane
B.
2-bromobutane
C.
3-bromopentane
D.
1-bromo-2-methylpropane
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Solution
3-bromopentane undergoes elimination more readily due to the stability of the tertiary carbocation formed during the reaction.
Correct Answer: C — 3-bromopentane
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Q. Which of the following compounds undergoes elimination to form an alkene most readily?
A.
1-bromopropane
B.
2-bromopropane
C.
3-bromopropane
D.
1-bromo-2-methylpropane
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Solution
3-bromopropane undergoes elimination more readily due to the stability of the tertiary carbocation formed during the reaction.
Correct Answer: C — 3-bromopropane
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Q. Which of the following compounds undergoes elimination to form an alkene when treated with a strong base?
A.
1-bromobutane
B.
2-bromobutane
C.
1-bromo-2-methylpropane
D.
2-bromo-2-methylpropane
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Solution
2-bromobutane undergoes elimination (E2) to form an alkene, while 2-bromo-2-methylpropane does not due to steric hindrance.
Correct Answer: B — 2-bromobutane
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Q. Which of the following compounds undergoes elimination via an E2 mechanism?
A.
2-bromopentane
B.
2-bromo-2-methylpropane
C.
1-bromobutane
D.
3-bromopropanol
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Solution
2-bromopentane can undergo E2 elimination because it has a beta-hydrogen available for elimination, while the others either do not or favor different mechanisms.
Correct Answer: A — 2-bromopentane
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Q. Which of the following compounds will not undergo electrophilic substitution?
A.
Benzene
B.
Toluene
C.
Nitrobenzene
D.
Phenol
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Solution
Nitrobenzene will not undergo electrophilic substitution readily because the nitro group is a strong deactivator and meta-director.
Correct Answer: C — Nitrobenzene
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Q. Which of the following compounds will undergo electrophilic aromatic substitution most readily?
A.
Benzene
B.
Toluene
C.
Chlorobenzene
D.
Nitrobenzene
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Solution
Toluene will undergo electrophilic aromatic substitution most readily due to the electron-donating effect of the methyl group.
Correct Answer: B — Toluene
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Q. Which of the following compounds will undergo electrophilic substitution more readily than benzene?
A.
Phenol
B.
Benzaldehyde
C.
Benzonitrile
D.
Benzyl alcohol
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Solution
Phenol will undergo electrophilic substitution more readily than benzene due to the electron-donating effect of the hydroxyl group.
Correct Answer: A — Phenol
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Q. Which of the following compounds will undergo electrophilic substitution more readily?
A.
Benzene
B.
Toluene
C.
Chlorobenzene
D.
Nitrobenzene
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Solution
Toluene will undergo electrophilic substitution more readily than benzene due to the electron-donating effect of the methyl group.
Correct Answer: B — Toluene
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Q. Which of the following compounds will undergo electrophilic substitution the fastest?
A.
Benzene
B.
Ethylbenzene
C.
Chlorobenzene
D.
Nitrobenzene
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Solution
Ethylbenzene will undergo electrophilic substitution the fastest due to the electron-donating effect of the ethyl group.
Correct Answer: B — Ethylbenzene
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Q. Which of the following compounds would show optical isomerism?
A.
2-butanol
B.
Butane
C.
Hexane
D.
Cyclohexane
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Solution
2-butanol has a chiral center and can exist as two enantiomers, thus showing optical isomerism.
Correct Answer: A — 2-butanol
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Q. Which of the following compounds would you expect to absorb UV light?
A.
Alkanes
B.
Aromatic compounds
C.
Alcohols
D.
Carboxylic acids
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Solution
Aromatic compounds have delocalized π electrons that can absorb UV light, while alkanes and alcohols do not have such electronic transitions.
Correct Answer: B — Aromatic compounds
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Q. Which of the following compounds would you expect to show a strong absorption in the IR region due to O-H stretching?
A.
Ethanol
B.
Benzene
C.
Hexane
D.
Cyclohexane
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Solution
Ethanol would show a strong absorption in the IR region due to O-H stretching, characteristic of alcohols.
Correct Answer: A — Ethanol
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Q. Which of the following compounds would you expect to show strong absorption in the UV region?
A.
Alkanes
B.
Aromatic compounds
C.
Alcohols
D.
Carboxylic acids
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Solution
Aromatic compounds have delocalized π electrons that can absorb UV light, leading to strong absorption in the UV region, unlike alkanes which do not absorb UV light.
Correct Answer: B — Aromatic compounds
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Q. Which of the following conditions is most likely to cause a real gas to behave ideally?
A.
High pressure and low temperature
B.
Low pressure and high temperature
C.
High pressure and high temperature
D.
Low pressure and low temperature
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Solution
Real gases behave more ideally at low pressure and high temperature, where intermolecular forces and molecular volume become less significant.
Correct Answer: B — Low pressure and high temperature
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Q. Which of the following coordination compounds contains a bidentate ligand?
A.
[Cu(NH3)4]2+
B.
[Ni(C2O4)2]2-
C.
[Fe(CN)6]3-
D.
[Ag(NH3)2]+
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Solution
Oxalate (C2O4) is a bidentate ligand that can form two bonds with a metal center.
Correct Answer: B — [Ni(C2O4)2]2-
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Q. Which of the following coordination compounds is an example of a square planar complex?
A.
[Cu(NH3)4]2+
B.
[Ni(CN)4]2-
C.
[Co(H2O)6]3+
D.
[FeCl4]-
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Solution
[Ni(CN)4]2- is a square planar complex, while the others exhibit different geometries.
Correct Answer: B — [Ni(CN)4]2-
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Q. Which of the following coordination compounds is known for its ability to form stable complexes with transition metals?
A.
Ammonia
B.
Water
C.
Ethylenediamine
D.
Methanol
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Solution
Ethylenediamine is a bidentate ligand that can form stable chelate complexes with transition metals.
Correct Answer: C — Ethylenediamine
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Q. Which of the following coordination compounds is likely to be colored?
A.
[Cu(NH3)4]2+
B.
[Zn(NH3)4]2+
C.
[Ag(NH3)2]+
D.
[Ni(H2O)6]2+
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Solution
The complex [Cu(NH3)4]2+ contains a transition metal with d-electrons that can be excited, resulting in color.
Correct Answer: A — [Cu(NH3)4]2+
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Q. Which of the following coordination compounds is likely to exhibit geometric isomerism?
A.
[Cu(NH3)4]SO4
B.
[CoCl2(NH3)4]
C.
[Ag(CN)2]−
D.
[Fe(CO)6]
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Solution
The complex [CoCl2(NH3)4] can exhibit geometric isomerism due to the presence of two different types of ligands.
Correct Answer: B — [CoCl2(NH3)4]
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Q. Which of the following coordination numbers is NOT possible according to Werner's theory?
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Solution
Coordination numbers typically range from 2 to 6 in most coordination compounds, making 7 an unlikely coordination number.
Correct Answer: D — 7
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Q. Which of the following describes a primary battery?
A.
It can be recharged multiple times.
B.
It is designed for single-use only.
C.
It has a longer lifespan than secondary batteries.
D.
It operates at higher voltages.
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Solution
A primary battery is designed for single-use and cannot be recharged, unlike secondary batteries.
Correct Answer: B — It is designed for single-use only.
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Q. Which of the following describes the BET theory?
A.
Single layer adsorption
B.
Multi-layer adsorption
C.
Physical adsorption only
D.
Chemical adsorption only
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Solution
The BET theory describes multi-layer adsorption on porous surfaces, extending the Langmuir model to account for multiple layers.
Correct Answer: B — Multi-layer adsorption
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Q. Which of the following elements can form a coordinate covalent bond?
A.
Oxygen
B.
Nitrogen
C.
Carbon
D.
Boron
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Solution
Oxygen can donate a lone pair to form a coordinate covalent bond, as seen in compounds like H2O and H3O+.
Correct Answer: A — Oxygen
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Q. Which of the following elements can form an expanded octet?
A.
Carbon
B.
Nitrogen
C.
Oxygen
D.
Phosphorus
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Solution
Phosphorus can form an expanded octet because it has available d orbitals to accommodate more than eight electrons in its valence shell.
Correct Answer: D — Phosphorus
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Q. Which of the following elements has the largest atomic radius?
A.
Lithium
B.
Sodium
C.
Potassium
D.
Rubidium
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Solution
Rubidium has the largest atomic radius due to its position in Group 1 and being the lowest in the group.
Correct Answer: D — Rubidium
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Q. Which of the following elements has the lowest first ionization energy?
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Solution
Boron has a lower first ionization energy than Be, C, and N due to its position in the periodic table.
Correct Answer: B — B
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Q. Which of the following elements has the smallest ionization energy?
A.
Lithium
B.
Sodium
C.
Potassium
D.
Rubidium
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Solution
Ionization energy decreases down a group; rubidium has the smallest ionization energy among these.
Correct Answer: D — Rubidium
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Q. Which of the following elements is a common ligand in coordination chemistry?
A.
Sodium
B.
Chlorine
C.
Ammonia
D.
Calcium
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Solution
Ammonia (NH3) is a common ligand that can donate a pair of electrons to a metal center.
Correct Answer: C — Ammonia
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Q. Which of the following elements is a lanthanide?
A.
Zirconium
B.
Neodymium
C.
Tantalum
D.
Hafnium
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Solution
Neodymium is a lanthanide, which are the 15 elements from cerium (Ce) to lutetium (Lu) in the periodic table.
Correct Answer: B — Neodymium
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