Which of the following compounds undergoes elimination more readily?

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Q: Which of the following compounds undergoes elimination more readily?

Solution: 3-bromopentane undergoes elimination more readily due to the stability of the tertiary carbocation formed during the reaction.

Steps: 6

Step 1: Understand what elimination means in chemistry. It is a reaction where two atoms or groups are removed from a molecule, forming a double bond.
Step 2: Identify the compounds being compared. In this case, we are looking at 3-bromopentane and another compound.
Step 3: Know that elimination reactions often involve the formation of a carbocation, which is a positively charged carbon atom.
Step 4: Determine the type of carbocation formed from 3-bromopentane. It forms a tertiary carbocation, which is more stable than primary or secondary carbocations.
Step 5: Remember that more stable carbocations lead to faster elimination reactions.
Step 6: Conclude that since 3-bromopentane forms a stable tertiary carbocation, it undergoes elimination more readily than compounds that form less stable carbocations.