Which of the following compounds undergoes elimination to form an alkene most readily?

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Q: Which of the following compounds undergoes elimination to form an alkene most readily?

Solution: 3-bromopropane undergoes elimination more readily due to the stability of the tertiary carbocation formed during the reaction.

Steps: 6

Step 1: Understand what elimination means. Elimination is a chemical reaction where atoms or groups are removed from a molecule, often forming a double bond (alkene).
Step 2: Identify the compounds given in the question. We need to compare them to see which one can easily lose atoms/groups.
Step 3: Know about carbocations. A carbocation is a positively charged carbon atom. The stability of this carbocation affects how easily elimination can happen.
Step 4: Recognize that tertiary carbocations (where the carbon is connected to three other carbons) are more stable than secondary or primary carbocations.
Step 5: Determine which compound forms a tertiary carbocation upon elimination. In this case, 3-bromopropane forms a tertiary carbocation.
Step 6: Conclude that since 3-bromopropane forms a stable tertiary carbocation, it undergoes elimination to form an alkene more readily than the others.