Chemistry (School & UG)
Q. What is Le Chatelier's principle?
A.
A system at equilibrium will shift to counteract changes.
B.
The rate of a reaction is proportional to the concentration of reactants.
C.
Energy is conserved in chemical reactions.
D.
The entropy of a system always increases.
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Solution
Le Chatelier's principle states that if a system at equilibrium is subjected to a change, the system will adjust to counteract that change.
Correct Answer: A — A system at equilibrium will shift to counteract changes.
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Q. What is the Beer-Lambert Law equation?
A.
A = εcl
B.
A = c/εl
C.
A = l/εc
D.
A = cl/ε
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Solution
The Beer-Lambert Law is expressed as A = εcl, where A is absorbance, ε is molar absorptivity, c is concentration, and l is path length.
Correct Answer: A — A = εcl
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Q. What is the Beer-Lambert Law used for in UV-Vis spectroscopy?
A.
To calculate the wavelength of light
B.
To determine the concentration of a solution
C.
To measure the intensity of emitted light
D.
To analyze the molecular structure
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Solution
The Beer-Lambert Law relates the absorbance of light to the concentration of a solution, allowing for concentration determination.
Correct Answer: B — To determine the concentration of a solution
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Q. What is the bond angle in a water (H2O) molecule?
A.
90 degrees
B.
104.5 degrees
C.
120 degrees
D.
180 degrees
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Solution
The bond angle in water is approximately 104.5 degrees due to the repulsion of the two lone pairs.
Correct Answer: B — 104.5 degrees
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Q. What is the bond angle in the H2O molecule?
A.
90 degrees
B.
104.5 degrees
C.
120 degrees
D.
180 degrees
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Solution
The bond angle in H2O is approximately 104.5 degrees due to the bent shape of the molecule caused by the two lone pairs on the oxygen atom.
Correct Answer: B — 104.5 degrees
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Q. What is the bond order of a molecule with 10 electrons in a molecular orbital diagram?
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Solution
Bond order = (number of bonding electrons - number of antibonding electrons) / 2. For 10 electrons, if all are bonding, bond order = 10/2 = 5. If 2 are antibonding, bond order = (10-2)/2 = 4. The most stable configuration gives a bond order of 2.
Correct Answer: C — 2
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Q. What is the bond order of a molecule with 10 electrons in a molecular orbital diagram showing 5 bonding and 5 antibonding electrons?
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Solution
Bond order = (Number of bonding electrons - Number of antibonding electrons) / 2 = (5 - 5) / 2 = 0.
Correct Answer: A — 0
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Q. What is the bond order of a molecule with 10 electrons in bonding orbitals and 4 electrons in antibonding orbitals?
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Solution
Bond order = (Number of bonding electrons - Number of antibonding electrons) / 2 = (10 - 4) / 2 = 3.
Correct Answer: B — 2
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Q. What is the bond order of a molecule with 3 bonding electrons and 1 antibonding electron?
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Solution
Bond order = (Number of bonding electrons - Number of antibonding electrons) / 2 = (3 - 1) / 2 = 1.
Correct Answer: B — 1
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Q. What is the bond order of O2 if it has 12 electrons in bonding orbitals and 4 in antibonding orbitals?
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Solution
Bond order = (12 - 4) / 2 = 4. The bond order for O2 is actually 2, but this question is hypothetical.
Correct Answer: A — 2
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Q. What is the bond order of the molecule N2?
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Solution
N2 has 10 bonding electrons and 2 antibonding electrons, so bond order = (10 - 2) / 2 = 4 / 2 = 2.
Correct Answer: C — 3
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Q. What is the bond order of the molecule O2?
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Solution
O2 has 12 total valence electrons. The bond order is calculated as (number of bonding electrons - number of antibonding electrons) / 2 = (10 - 2) / 2 = 4 / 2 = 2.
Correct Answer: B — 2
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Q. What is the bond order of the O2 molecule?
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Solution
O2 has 12 total electrons, with 10 in bonding orbitals and 2 in antibonding orbitals. Bond order = (number of bonding electrons - number of antibonding electrons) / 2 = (10 - 2) / 2 = 4 / 2 = 2.
Correct Answer: B — 2
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Q. What is the change in enthalpy (ΔH) for an endothermic reaction?
A.
ΔH < 0
B.
ΔH = 0
C.
ΔH > 0
D.
ΔH = -RT
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Solution
In an endothermic reaction, heat is absorbed from the surroundings, resulting in a positive change in enthalpy (ΔH > 0).
Correct Answer: C — ΔH > 0
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Q. What is the change in enthalpy (ΔH) for an exothermic reaction?
A.
ΔH > 0
B.
ΔH < 0
C.
ΔH = 0
D.
ΔH is undefined
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Solution
In an exothermic reaction, heat is released, resulting in a negative change in enthalpy (ΔH < 0).
Correct Answer: B — ΔH < 0
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Q. What is the change in enthalpy (ΔH) for the reaction: 2H2(g) + O2(g) → 2H2O(g) if the bond enthalpies are: H-H = 436 kJ/mol, O=O = 498 kJ/mol, H-O = 463 kJ/mol?
A.
−484 kJ
B.
−572 kJ
C.
−572 kJ
D.
−484 kJ
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Solution
ΔH = Σ(bond enthalpies of reactants) - Σ(bond enthalpies of products) = [2(436) + 498] - [4(463)] = −572 kJ.
Correct Answer: B — −572 kJ
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Q. What is the change in enthalpy (ΔH) for the reaction: H2(g) + 1/2 O2(g) → H2O(l) if the standard enthalpy of formation of H2O(l) is -285.8 kJ/mol?
A.
-285.8 kJ/mol
B.
285.8 kJ/mol
C.
0 kJ/mol
D.
571.6 kJ/mol
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Solution
The change in enthalpy for the reaction is equal to the standard enthalpy of formation of H2O(l), which is -285.8 kJ/mol.
Correct Answer: A — -285.8 kJ/mol
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Q. What is the change in enthalpy (ΔH) for the reaction: H2(g) + 1/2 O2(g) → H2O(l) if the standard enthalpy of formation of H2O(l) is -285.83 kJ/mol?
A.
-285.83 kJ/mol
B.
285.83 kJ/mol
C.
0 kJ/mol
D.
571.66 kJ/mol
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Solution
The change in enthalpy for the reaction is equal to the standard enthalpy of formation of H2O(l), which is -285.83 kJ/mol.
Correct Answer: A — -285.83 kJ/mol
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Q. What is the change in enthalpy for the reaction at constant pressure?
A.
It is equal to the heat absorbed or released.
B.
It is equal to the work done on the system.
C.
It is always negative.
D.
It is independent of the path taken.
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Solution
At constant pressure, the change in enthalpy (ΔH) is defined as the heat absorbed or released by the system.
Correct Answer: A — It is equal to the heat absorbed or released.
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Q. What is the common name for 2-methylpropan-1-ol?
A.
Isobutanol
B.
Butanol
C.
Propanol
D.
Pentanol
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Solution
2-methylpropan-1-ol is commonly known as isobutanol.
Correct Answer: A — Isobutanol
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Q. What is the common use of alkenes in the industry?
A.
Fuel
B.
Plastics production
C.
Solvents
D.
Food additives
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Solution
Alkenes are commonly used in the production of plastics, such as polyethylene.
Correct Answer: B — Plastics production
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Q. What is the concentration of hydroxide ions in a solution with a pH of 11?
A.
1 x 10^-3 M
B.
1 x 10^-4 M
C.
1 x 10^-5 M
D.
1 x 10^-6 M
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Solution
pOH = 14 - pH = 14 - 11 = 3. [OH-] = 10^-pOH = 10^-3 M.
Correct Answer: A — 1 x 10^-3 M
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Q. What is the conjugate base of H2SO4?
A.
HSO4-
B.
SO4^2-
C.
H3O+
D.
H2O
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Solution
The conjugate base of H2SO4 is HSO4-, formed when H2SO4 donates a proton (H+).
Correct Answer: A — HSO4-
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Q. What is the coordination number of a metal in a complex with a tetrahedral geometry?
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Solution
In a tetrahedral complex, the coordination number is 4, as there are four ligands surrounding the central metal atom.
Correct Answer: B — 4
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Q. What is the coordination number of a metal in a complex with an octahedral geometry?
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Solution
In an octahedral complex, the coordination number is 6, as there are six ligands surrounding the central metal atom.
Correct Answer: C — 6
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Q. What is the coordination number of a metal in a complex with six ligands?
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Solution
The coordination number is defined as the number of ligand atoms that are bonded to the central metal atom. In this case, with six ligands, the coordination number is 6.
Correct Answer: C — 6
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Q. What is the coordination number of hydrogen in the complex ion [H2O]2+?
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Solution
In the complex ion [H2O]2+, the coordination number of hydrogen is 2.
Correct Answer: B — 2
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Q. What is the coordination number of hydrogen in the complex [Ni(H2)6]?
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Solution
In the complex [Ni(H2)6], the coordination number of hydrogen is 6, as there are six hydrogen ligands coordinated to nickel.
Correct Answer: C — 6
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Q. What is the coordination number of the central metal ion in a complex with the formula [Co(NH3)6]Cl3?
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Solution
The coordination number is determined by the number of ligands attached to the central metal ion. In this case, there are six NH3 ligands, giving a coordination number of 6.
Correct Answer: C — 6
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Q. What is the coordination number of the central metal ion in the complex [Cu(NH3)4]SO4?
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Solution
The coordination number of copper in [Cu(NH3)4]SO4 is 4, as it is surrounded by four ammonia ligands.
Correct Answer: B — 4
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