What is the bond order of a molecule with 10 electrons in a molecular orbital diagram?
Practice Questions
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What is the bond order of a molecule with 10 electrons in a molecular orbital diagram?
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Bond order = (number of bonding electrons - number of antibonding electrons) / 2. For 10 electrons, if all are bonding, bond order = 10/2 = 5. If 2 are antibonding, bond order = (10-2)/2 = 4. The most stable configuration gives a bond order of 2.
Questions & Step-by-step Solutions
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Q
Q: What is the bond order of a molecule with 10 electrons in a molecular orbital diagram?
Solution: Bond order = (number of bonding electrons - number of antibonding electrons) / 2. For 10 electrons, if all are bonding, bond order = 10/2 = 5. If 2 are antibonding, bond order = (10-2)/2 = 4. The most stable configuration gives a bond order of 2.
Steps: 7
Step 1: Understand that bond order is a way to measure the stability of a bond in a molecule.
Step 2: Know the formula for bond order: Bond order = (number of bonding electrons - number of antibonding electrons) / 2.
Step 3: Identify the total number of electrons in the molecule, which is given as 10.
Step 4: Determine how many of those 10 electrons are in bonding orbitals and how many are in antibonding orbitals.
Step 5: If all 10 electrons are bonding, calculate bond order: Bond order = 10 / 2 = 5.
Step 6: If 2 electrons are in antibonding orbitals, calculate bond order: Bond order = (10 - 2) / 2 = 4.
Step 7: Consider the most stable configuration, which typically gives a bond order of 2.
