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What is the bond order of a molecule with 10 electrons in bonding orbitals and 4
What is the bond order of a molecule with 10 electrons in bonding orbitals and 4 electrons in antibonding orbitals?
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Q1
What is the bond order of a molecule with 10 electrons in bonding orbitals and 4 electrons in antibonding orbitals?
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Bond order = (Number of bonding electrons - Number of antibonding electrons) / 2 = (10 - 4) / 2 = 3.
Questions & Step-by-step Solutions
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Q
Q: What is the bond order of a molecule with 10 electrons in bonding orbitals and 4 electrons in antibonding orbitals?
Solution:
Bond order = (Number of bonding electrons - Number of antibonding electrons) / 2 = (10 - 4) / 2 = 3.
Steps: 6
Show Steps
Step 1: Identify the number of bonding electrons in the molecule. In this case, there are 10 bonding electrons.
Step 2: Identify the number of antibonding electrons in the molecule. Here, there are 4 antibonding electrons.
Step 3: Use the bond order formula: Bond order = (Number of bonding electrons - Number of antibonding electrons) / 2.
Step 4: Substitute the values into the formula: Bond order = (10 - 4) / 2.
Step 5: Calculate the result: 10 - 4 equals 6, then divide 6 by 2 to get 3.
Step 6: Conclude that the bond order of the molecule is 3.
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