What is the bond order of O2 if it has 12 electrons in bonding orbitals and 4 in antibonding orbitals?

1 question

1 item

Q: What is the bond order of O2 if it has 12 electrons in bonding orbitals and 4 in antibonding orbitals?

Solution: Bond order = (12 - 4) / 2 = 4. The bond order for O2 is actually 2, but this question is hypothetical.

Steps: 7

Step 1: Understand what bond order means. Bond order is a way to measure the strength and stability of a bond between two atoms.
Step 2: Identify the number of electrons in bonding orbitals. In this case, there are 12 electrons in bonding orbitals.
Step 3: Identify the number of electrons in antibonding orbitals. Here, there are 4 electrons in antibonding orbitals.
Step 4: Use the bond order formula: Bond order = (Number of bonding electrons - Number of antibonding electrons) / 2.
Step 5: Plug in the numbers: Bond order = (12 - 4) / 2.
Step 6: Calculate the result: 12 - 4 equals 8, and then 8 divided by 2 equals 4.
Step 7: Note that while the calculation gives a bond order of 4, the actual bond order for O2 is 2, indicating this is a hypothetical scenario.