What is the change in enthalpy (ΔH) for the reaction: H2(g) + 1/2 O2(g) → H2O(l) if the standard enthalpy of formation of H2O(l) is -285.8 kJ/mol?

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Q: What is the change in enthalpy (ΔH) for the reaction: H2(g) + 1/2 O2(g) → H2O(l) if the standard enthalpy of formation of H2O(l) is -285.8 kJ/mol?

Solution: The change in enthalpy for the reaction is equal to the standard enthalpy of formation of H2O(l), which is -285.8 kJ/mol.

Steps: 5

Step 1: Identify the reaction: H2(g) + 1/2 O2(g) → H2O(l).
Step 2: Understand that the standard enthalpy of formation (ΔHf) is the change in enthalpy when one mole of a compound is formed from its elements in their standard states.
Step 3: Note that the standard enthalpy of formation of H2O(l) is given as -285.8 kJ/mol.
Step 4: Recognize that the change in enthalpy (ΔH) for the reaction is equal to the standard enthalpy of formation of the product, H2O(l).
Step 5: Conclude that the change in enthalpy (ΔH) for the reaction is -285.8 kJ/mol.