What is the bond order of a molecule with 10 electrons in a molecular orbital diagram showing 5 bonding and 5 antibonding electrons?

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Q: What is the bond order of a molecule with 10 electrons in a molecular orbital diagram showing 5 bonding and 5 antibonding electrons?

Solution: Bond order = (Number of bonding electrons - Number of antibonding electrons) / 2 = (5 - 5) / 2 = 0.

Steps: 5

Step 1: Identify the number of bonding electrons in the molecule. In this case, there are 5 bonding electrons.
Step 2: Identify the number of antibonding electrons in the molecule. Here, there are also 5 antibonding electrons.
Step 3: Use the bond order formula: Bond order = (Number of bonding electrons - Number of antibonding electrons) / 2.
Step 4: Substitute the values into the formula: Bond order = (5 - 5) / 2.
Step 5: Calculate the result: Bond order = 0 / 2 = 0.