The major product of the elimination of 2-bromobutane with a strong base is butene, specifically 2-butene due to the more stable alkene formation.

The reaction is an SN2 substitution where the nucleophile (OH-) attacks the carbon bonded to Br, resulting in the formation of CH3OH.

The major product of the hydration of propene is propan-2-ol due to Markovnikov's rule.

The reaction is a nucleophilic substitution (SN2) where sodium hydroxide replaces the bromine atom, resulting in 1-Propanol.

The major product is 1-Propanol, as the reaction proceeds via an SN2 mechanism leading to the formation of an alcohol.

The hydrogenation of 1-butene leads to the formation of butane as the major product.

The reaction follows Markovnikov's rule, where HBr adds across the double bond, leading to the formation of 2-bromobutane as the major product.

The hydrogenation of 1-butyne in the presence of a catalyst produces butane as the major product.

The addition of HBr to 1-butyne follows Markovnikov's rule, leading to the formation of 2-bromobutane.

The major product is 2-butene, as potassium tert-butoxide promotes elimination (E2) leading to the formation of an alkene.

The reaction of propene with bromine results in the formation of 1,2-dibromopropane through an addition reaction.

The major product is 2-bromopropane due to Markovnikov's rule, where H adds to the less substituted carbon.

The reaction is an elimination reaction (E2) leading to the formation of 2-methylpropene as the major product.

The reaction of 1-butyne with HBr follows Markovnikov's rule, leading to the formation of 2-bromobutane.

The reaction of 1-chloropropane with sodium hydroxide in an SN2 mechanism results in the formation of 1-propanol through nucleophilic substitution.

The reaction is a hydrogenation that converts 1-pentene to pentane, a saturated hydrocarbon.

The strong base induces an E2 elimination reaction, leading to the formation of 2-methylpropene as the major product.

The reaction favors elimination due to the bulky substrate, leading to the formation of 2-methylpropene.

The reaction of 2-methylpropene with H2 in the presence of a platinum catalyst results in the hydrogenation of the alkene to form 2-methylpropane.

The major product is 2-bromopropane due to Markovnikov's rule, where the bromine adds to the more substituted carbon.

The addition of HBr to 2-pentene follows Markovnikov's rule, leading to the formation of 2-bromopentane.

The reaction is an electrophilic aromatic substitution, resulting in the formation of bromobenzene as the major product.

The hydrogenation of 2-methylpropene results in the saturation of the double bond, yielding 2-methylpropane as the major product.

The major product is 2-methylpropan-2-ol due to Markovnikov's rule, where water adds to the more substituted carbon.

The major product is para-nitroanisole due to the electron-donating effect of the methoxy group, which directs the electrophile to the para position.

Phenol reacts with bromine water to predominantly form 2-bromophenol due to the activating effect of the hydroxyl group.

The maximum number of electrons in a subshell is given by 2n^2. For d (n=3), it is 2(3^2) = 18, but only 10 can occupy 3d.

The maximum number of electrons in an energy level is given by the formula 2n^2. For n=2, it is 2(2^2) = 8.

The maximum number of stereoisomers for a compound with n chiral centers is given by 2^n. For 2 chiral centers, it is 2^2 = 4.

Nitrogen has three unpaired electrons in its 2p orbitals (1s2 2s2 2p3).