What is the major product of the reaction of 1-chloropropane with sodium hydroxide in an SN2 mechanism?
Practice Questions
1 question
Q1
What is the major product of the reaction of 1-chloropropane with sodium hydroxide in an SN2 mechanism?
1-propanol
2-propanol
Propyl chloride
Sodium chloride
The reaction of 1-chloropropane with sodium hydroxide in an SN2 mechanism results in the formation of 1-propanol through nucleophilic substitution.
Questions & Step-by-step Solutions
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Q
Q: What is the major product of the reaction of 1-chloropropane with sodium hydroxide in an SN2 mechanism?
Solution: The reaction of 1-chloropropane with sodium hydroxide in an SN2 mechanism results in the formation of 1-propanol through nucleophilic substitution.
Steps: 6
Step 1: Identify the reactants. We have 1-chloropropane (C3H7Cl) and sodium hydroxide (NaOH).
Step 2: Understand the SN2 mechanism. In this mechanism, a nucleophile attacks the carbon atom that is bonded to the leaving group (chlorine in this case).
Step 3: Recognize that sodium hydroxide (NaOH) provides hydroxide ions (OH-) which act as the nucleophile.
Step 4: The hydroxide ion attacks the carbon atom in 1-chloropropane that is attached to the chlorine atom.
Step 5: As the hydroxide ion attacks, the chlorine atom leaves, resulting in the formation of a new bond between the carbon and the hydroxide ion.
Step 6: The product formed is 1-propanol (C3H8O), which is an alcohol.
