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What is the major product of the following reaction: CH3Br + NaOH (ethanol)?
What is the major product of the following reaction: CH3Br + NaOH (ethanol)?
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Practice Questions
1 question
Q1
What is the major product of the following reaction: CH3Br + NaOH (ethanol)?
CH3OH
CH3O-Na+
CH3-NaBr
CH3-CH2-OH
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The reaction is an SN2 substitution where the nucleophile (OH-) attacks the carbon bonded to Br, resulting in the formation of CH3OH.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the major product of the following reaction: CH3Br + NaOH (ethanol)?
Solution:
The reaction is an SN2 substitution where the nucleophile (OH-) attacks the carbon bonded to Br, resulting in the formation of CH3OH.
Steps: 5
Show Steps
Step 1: Identify the reactants. We have CH3Br (methyl bromide) and NaOH (sodium hydroxide) in ethanol.
Step 2: Recognize that NaOH provides OH- (hydroxide ion), which acts as a nucleophile.
Step 3: Understand that in an SN2 reaction, the nucleophile (OH-) will attack the carbon atom that is bonded to the bromine (Br) in CH3Br.
Step 4: The Br atom is a good leaving group, so when OH- attacks the carbon, Br leaves, and we form a new bond between the carbon and the OH group.
Step 5: The product formed is CH3OH (methanol), as the Br is replaced by the OH group.
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