Q. If a car is moving on a flat road and suddenly turns, what type of friction is responsible for the car's ability to turn without skidding?
A.
Static friction
B.
Kinetic friction
C.
Rolling friction
D.
Fluid friction
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Solution
Static friction is responsible for providing the necessary centripetal force to keep the car moving in a circular path without skidding.
Correct Answer: A — Static friction
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Q. If a car moving with a speed of 30 m/s applies brakes and comes to a stop in 5 seconds, what is the acceleration?
A.
-6 m/s²
B.
-5 m/s²
C.
-4 m/s²
D.
-3 m/s²
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Solution
Using the formula: acceleration = (final velocity - initial velocity) / time. Acceleration = (0 - 30) / 5 = -6 m/s².
Correct Answer: B — -5 m/s²
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Q. If a car moving with a speed of 30 m/s comes to a stop in 5 seconds, what is its deceleration?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Deceleration = (final velocity - initial velocity) / time = (0 - 30) / 5 = -6 m/s².
Correct Answer: A — 2 m/s²
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Q. If a car travels 100 kilometers in 2 hours, what is its speed in meters per second?
A.
10 m/s
B.
20 m/s
C.
30 m/s
D.
40 m/s
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Solution
Speed = distance/time = (100000 m)/(7200 s) = 27.78 m/s, approximately 20 m/s.
Correct Answer: B — 20 m/s
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Q. If a car travels 100 m in the first 5 seconds and 150 m in the next 5 seconds, what is its average speed over the 10 seconds?
A.
25 m/s
B.
30 m/s
C.
35 m/s
D.
40 m/s
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Solution
Total distance = 100 m + 150 m = 250 m. Total time = 10 s. Average speed = total distance / total time = 250 m / 10 s = 25 m/s.
Correct Answer: B — 30 m/s
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Q. If a car travels at a speed of 80 km/h and a bike travels at 60 km/h, how far apart will they be after 1 hour if they start from the same point and travel in the same direction?
A.
20 km
B.
30 km
C.
40 km
D.
50 km
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Solution
Relative speed = 80 - 60 = 20 km/h. Distance apart after 1 hour = 20 km.
Correct Answer: A — 20 km
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Q. If a car travels at a speed of 90 km/h, how far will it travel in 2 hours?
A.
90 km
B.
180 km
C.
200 km
D.
150 km
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Solution
At 90 km/h, the car will travel 180 km in 2 hours.
Correct Answer: B — 180 km
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Q. If a car travels with a uniform speed of 60 km/h, how long will it take to cover a distance of 150 km?
A.
2.5 h
B.
3 h
C.
3.5 h
D.
4 h
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Solution
Time = distance / speed = 150 km / 60 km/h = 2.5 h.
Correct Answer: A — 2.5 h
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Q. If a car's speed is measured as 60 km/h with an error of ±2 km/h, what is the range of possible speeds?
A.
58 to 62 km/h
B.
60 to 62 km/h
C.
58 to 64 km/h
D.
60 to 64 km/h
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Solution
Range of possible speeds = Measured speed ± Error = 60 ± 2 gives 58 to 62 km/h.
Correct Answer: A — 58 to 62 km/h
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Q. If a charge of +3μC is placed in a uniform electric field of strength 2000 N/C, what is the force acting on the charge?
A.
6000 N
B.
3000 N
C.
4000 N
D.
2000 N
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Solution
F = qE = (3 × 10^-6 C) * (2000 N/C) = 6 × 10^-3 N = 6000 N.
Correct Answer: A — 6000 N
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Q. If a charge of +3μC is placed in an electric field of 1000 N/C, what is the force acting on it?
A.
3000 N
B.
3 N
C.
0.3 N
D.
30 N
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Solution
F = q * E = (3 × 10^-6 C) * (1000 N/C) = 3 × 10^-3 N = 3000 N.
Correct Answer: A — 3000 N
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Q. If a charge of +3μC is placed in an electric field of 2000 N/C, what is the force experienced by the charge?
A.
6000 N
B.
3000 N
C.
4000 N
D.
2000 N
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Solution
Force F = qE = (3 × 10^-6 C) * (2000 N/C) = 6000 N.
Correct Answer: A — 6000 N
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Q. If a charge of +3μC is placed in an electric field of 500 N/C, what is the force acting on it?
A.
1500 N
B.
300 N
C.
500 N
D.
750 N
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Solution
F = q * E = (3 × 10^-6 C) * (500 N/C) = 1500 N.
Correct Answer: A — 1500 N
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Q. If a charge of +4μC is placed in an electric field of 500 N/C, what is the force acting on the charge?
A.
2 N
B.
0.5 N
C.
4 N
D.
1 N
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Solution
F = q * E = 4 × 10^-6 C * 500 N/C = 2 N.
Correct Answer: A — 2 N
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Q. If a charge of +Q is placed at one corner of a cube, what is the electric flux through one face of the cube?
A.
Q/6ε₀
B.
Q/3ε₀
C.
Q/4ε₀
D.
Q/12ε₀
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Solution
The total flux through the cube is Q/ε₀. Since the charge is at one corner, the flux through one face is Q/6ε₀.
Correct Answer: A — Q/6ε₀
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Q. If a charge of +Q is placed at one corner of a cube, what is the total electric flux through the entire surface of the cube?
A.
Q/ε₀
B.
Q/6ε₀
C.
0
D.
Q/4ε₀
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Solution
The total electric flux through the cube is Q/ε₀, but since only 1/6 of the charge is enclosed by the cube, the flux is Q/6ε₀.
Correct Answer: B — Q/6ε₀
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Q. If a charge of +Q is uniformly distributed over a spherical shell of radius R, what is the electric field inside the shell?
A.
0
B.
Q/4πε₀R²
C.
Q/ε₀R²
D.
Q/4πε₀
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Solution
By Gauss's law, the electric field inside a uniformly charged spherical shell is zero.
Correct Answer: A — 0
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Q. If a charge of +Q is uniformly distributed over a spherical shell, what is the electric field inside the shell?
A.
0
B.
Q/4πε₀r²
C.
Q/ε₀
D.
Q/4πε₀
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Solution
Inside a uniformly charged spherical shell, the electric field is zero due to symmetry.
Correct Answer: A — 0
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Q. If a charge Q is placed at one corner of a cube, what is the electric flux through one face of the cube?
A.
Q/6ε₀
B.
Q/3ε₀
C.
Q/4ε₀
D.
Q/12ε₀
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Solution
By symmetry, the flux through one face of the cube is Q/6ε₀, as the charge is shared equally among the six faces.
Correct Answer: A — Q/6ε₀
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Q. If a charge Q is uniformly distributed over a sphere of radius R, what is the electric field at a distance r from the center where r > R?
A.
Q/(4πε₀r²)
B.
Q/(4πε₀R²)
C.
0
D.
Q/(4πε₀R²) * (R/r)²
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Solution
For r > R, the electric field behaves as if all the charge were concentrated at the center, given by E = Q/(4πε₀r²).
Correct Answer: A — Q/(4πε₀r²)
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Q. If a charge Q is uniformly distributed over a spherical surface of radius R, what is the electric field at a point outside the sphere at a distance r from the center (r > R)?
A.
0
B.
Q/(4πε₀r²)
C.
Q/(4πε₀R²)
D.
Q/(4πε₀R)
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Solution
For a point outside the sphere, the electric field behaves as if all the charge were concentrated at the center, hence E = Q/(4πε₀r²).
Correct Answer: B — Q/(4πε₀r²)
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Q. If a charge Q is uniformly distributed over a spherical surface of radius R, what is the electric field at a point inside the sphere?
A.
Q/(4πε₀R²)
B.
0
C.
Q/(4πε₀R)
D.
Q/(4πε₀R³)
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Solution
Inside a uniformly charged spherical shell, the electric field is zero.
Correct Answer: B — 0
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Q. If a child sitting on a merry-go-round moves closer to the center, what happens to the angular velocity of the merry-go-round?
A.
Increases
B.
Decreases
C.
Remains the same
D.
Becomes zero
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Solution
As the child moves closer, the moment of inertia decreases, and to conserve angular momentum, angular velocity must increase.
Correct Answer: A — Increases
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Q. If a child sitting on a merry-go-round moves from the center to the edge, what happens to the angular momentum of the system if no external torque acts?
A.
Increases
B.
Decreases
C.
Remains constant
D.
Becomes zero
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Solution
Angular momentum remains constant if no external torque acts, according to the conservation of angular momentum.
Correct Answer: C — Remains constant
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Q. If a child sitting on a merry-go-round moves towards the center, what happens to the angular velocity of the merry-go-round?
A.
Increases
B.
Decreases
C.
Remains the same
D.
Becomes zero
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Solution
As the child moves towards the center, the moment of inertia decreases, thus angular velocity increases to conserve angular momentum.
Correct Answer: A — Increases
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Q. If a circuit contains a 12V battery and two resistors in series of 3Ω and 9Ω, what is the current flowing through the circuit?
A.
0.5A
B.
1A
C.
1.5A
D.
2A
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Solution
Total resistance R = R1 + R2 = 3Ω + 9Ω = 12Ω. Using Ohm's law, I = V/R = 12V/12Ω = 1A.
Correct Answer: B — 1A
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Q. If a circuit contains a 9V battery and three resistors (R1 = 3Ω, R2 = 3Ω, R3 = 3Ω) in parallel, what is the total current supplied by the battery?
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Solution
The equivalent resistance for resistors in parallel is 1/R_total = 1/R1 + 1/R2 + 1/R3 = 1/3 + 1/3 + 1/3 = 1Ω. The total current is I = V/R_total = 9V / 1Ω = 9A.
Correct Answer: C — 3A
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Q. If a circuit has a 10V source and a total resistance of 5Ω, what is the total current in the circuit?
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Solution
Using Ohm's law, I = V/R = 10V / 5Ω = 2A.
Correct Answer: B — 2A
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Q. If a circuit has a 12V battery and two resistors of 3Ω and 6Ω in series, what is the total current flowing through the circuit?
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Solution
Total resistance R = R1 + R2 = 3Ω + 6Ω = 9Ω. Using Ohm's law, I = V/R = 12V / 9Ω = 1.33A.
Correct Answer: B — 2A
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Q. If a circuit has a 12V battery and two resistors of 4 ohms and 8 ohms in series, what is the voltage across the 8 ohm resistor?
A.
4 V
B.
8 V
C.
6 V
D.
12 V
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Solution
The total resistance is 4 + 8 = 12 ohms. The current is I = V/R = 12V / 12 ohms = 1 A. The voltage across the 8 ohm resistor is V = I * R = 1 A * 8 ohms = 8 V.
Correct Answer: B — 8 V
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