Q. If a hollow cylinder rolls down an incline, how does its acceleration compare to that of a solid cylinder?
A.
Hollow cylinder accelerates faster
B.
Solid cylinder accelerates faster
C.
Both accelerate equally
D.
Depends on the angle of incline
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Solution
The solid cylinder has a lower moment of inertia compared to the hollow cylinder, thus it accelerates faster down the incline.
Correct Answer: B — Solid cylinder accelerates faster
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Q. If a hollow sphere and a solid sphere of the same mass and radius roll down the same incline, which one reaches the bottom first?
A.
Hollow sphere
B.
Solid sphere
C.
Both reach at the same time
D.
Depends on the angle of incline
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Solution
The solid sphere has a smaller moment of inertia compared to the hollow sphere, thus it accelerates faster and reaches the bottom first.
Correct Answer: B — Solid sphere
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Q. If a hollow sphere rolls down an incline, how does its acceleration compare to that of a solid sphere?
A.
Greater
B.
Less
C.
Equal
D.
Depends on mass
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Solution
The hollow sphere has a greater moment of inertia, resulting in less acceleration compared to the solid sphere.
Correct Answer: B — Less
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Q. If a length is measured as 0.0500 m, how many significant figures does it have?
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Solution
Leading zeros are not significant. The significant figures are 5, 0, 0, which gives a total of 3 significant figures.
Correct Answer: C — 4
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Q. If a length is measured as 0.0600 m, how many significant figures does it have?
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Solution
The number 0.0600 m has 3 significant figures. The leading zeros do not count, but the trailing zeros after the decimal point do.
Correct Answer: C — 4
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Q. If a length is measured as 150.0 cm, how many significant figures does it have?
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Solution
The number 150.0 has 4 significant figures because the trailing zero after the decimal point counts as significant.
Correct Answer: C — 4
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Q. If a length is measured as 2.5 m, how many centimeters is that?
A.
25
B.
250
C.
2.5
D.
2500
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Solution
2.5 meters is equal to 250 centimeters.
Correct Answer: B — 250
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Q. If a length is measured as 2.5 m, how many millimeters is that?
A.
25
B.
250
C.
2500
D.
25000
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Solution
2.5 m is equal to 2500 millimeters.
Correct Answer: C — 2500
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Q. If a length is measured as 2.5 m, what is this length in millimeters?
A.
25
B.
250
C.
2500
D.
25000
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Solution
2.5 m is equal to 2500 mm (2.5 m × 1000 mm/m).
Correct Answer: C — 2500
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Q. If a length is measured as 25.0 cm, what is the uncertainty in this measurement?
A.
0.1 cm
B.
0.01 cm
C.
1 cm
D.
0.5 cm
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Solution
The uncertainty is 0.1 cm, as the last digit is in the tenths place.
Correct Answer: A — 0.1 cm
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Q. If a length is measured as 250 m with an error of 5 m, what is the absolute error?
A.
5 m
B.
0.5 m
C.
0.05 m
D.
50 m
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Solution
The absolute error is given as 5 m.
Correct Answer: A — 5 m
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Q. If a length is measured as 30.0 cm with an uncertainty of ±0.2 cm, what is the maximum possible error?
A.
0.1 cm
B.
0.2 cm
C.
0.3 cm
D.
0.4 cm
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Solution
Maximum possible error is equal to the uncertainty, which is ±0.2 cm.
Correct Answer: B — 0.2 cm
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Q. If a lens forms a real image at a distance of 40 cm from the lens, and the object is placed at 60 cm, what is the focal length of the lens?
A.
15 cm
B.
20 cm
C.
25 cm
D.
30 cm
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Solution
Using the lens formula 1/f = 1/v - 1/u, we have 1/f = 1/40 - 1/(-60) = 1/40 + 1/60 = 1/24. Therefore, f = 24 cm.
Correct Answer: C — 25 cm
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Q. If a lens has a focal length of -20 cm, what type of lens is it?
A.
Convex lens
B.
Concave lens
C.
Biconvex lens
D.
Biconcave lens
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Solution
A negative focal length indicates that the lens is a concave lens.
Correct Answer: B — Concave lens
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Q. If a lens has a power of -2 D, what is its focal length?
A.
-50 cm
B.
-25 cm
C.
25 cm
D.
50 cm
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Solution
Power (P) = 1/f, so f = 1/P = 1/(-2) = -0.5 m = -50 cm.
Correct Answer: B — -25 cm
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Q. If a lens has a power of -2 D, what type of lens is it?
A.
Convex lens
B.
Concave lens
C.
Bifocal lens
D.
Plano-convex lens
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Solution
A negative power indicates a concave lens.
Correct Answer: B — Concave lens
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Q. If a light ray enters a medium with a refractive index of 1.33 at an angle of 60°, what is the angle of refraction in the medium?
A.
30°
B.
45°
C.
60°
D.
75°
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Solution
Using Snell's law: n1 * sin(θ1) = n2 * sin(θ2), 1 * sin(60°) = 1.33 * sin(θ2) => sin(θ2) = (sin(60°)/1.33) ≈ 0.577, θ2 ≈ 35.0°.
Correct Answer: B — 45°
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Q. If a light ray in a medium with n=1.5 strikes a boundary with n=1.0 at an angle of 70°, what will happen?
A.
Total internal reflection occurs
B.
Light refracts into the air
C.
Light is absorbed
D.
Light reflects at 70°
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Solution
Since the angle of incidence (70°) is greater than the critical angle (approximately 41.8°), total internal reflection occurs.
Correct Answer: A — Total internal reflection occurs
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Q. If a light ray in diamond (n=2.42) strikes the diamond-air interface at an angle of 70°, will it undergo total internal reflection?
A.
Yes
B.
No
C.
Only if the angle is decreased
D.
Only if the angle is increased
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Solution
The critical angle for diamond to air is sin⁻¹(1/2.42) ≈ 24.4°. Since 70° > 24.4°, total internal reflection will occur.
Correct Answer: A — Yes
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Q. If a light wave passes through a narrow slit and produces a diffraction pattern, what happens to the intensity of the central maximum compared to the other maxima?
A.
It is the same
B.
It is greater
C.
It is lesser
D.
It is zero
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Solution
The intensity of the central maximum is greater than that of the other maxima in a diffraction pattern.
Correct Answer: B — It is greater
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Q. If a liquid droplet is formed on a surface, what shape does it take due to surface tension?
A.
Square
B.
Flat
C.
Sphere
D.
Triangle
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Solution
A liquid droplet takes the shape of a sphere because this shape minimizes the surface area for a given volume, thus minimizing surface energy.
Correct Answer: C — Sphere
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Q. If a liquid droplet is perfectly spherical, what can be said about the forces acting on it?
A.
Net force is zero
B.
Net force is upward
C.
Net force is downward
D.
Net force is horizontal
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Solution
In a perfectly spherical droplet, the cohesive forces are balanced, resulting in a net force of zero.
Correct Answer: A — Net force is zero
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Q. If a liquid has a high surface tension, what can be inferred about its molecular interactions?
A.
Weak intermolecular forces
B.
Strong intermolecular forces
C.
No intermolecular forces
D.
Only gravitational forces
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Solution
A high surface tension indicates strong intermolecular forces, as these forces are responsible for the cohesive behavior of the liquid.
Correct Answer: B — Strong intermolecular forces
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Q. If a liquid has a surface tension of 0.05 N/m, what is the work done in increasing the surface area by 1 m²?
A.
0.05 J
B.
0.1 J
C.
0.2 J
D.
0.5 J
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Solution
Work done = Surface Tension × Change in Area = 0.05 N/m × 1 m² = 0.05 J.
Correct Answer: A — 0.05 J
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Q. If a long straight conductor carries a current I, what is the magnetic field at a distance r from the wire?
A.
μ₀I/(2πr)
B.
μ₀I/(4πr²)
C.
μ₀I/(2r)
D.
μ₀I/(πr²)
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Solution
According to Ampere's Law, the magnetic field B at a distance r from a long straight conductor carrying current I is given by B = μ₀I/(2πr).
Correct Answer: A — μ₀I/(2πr)
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Q. If a long straight conductor carries a current I, what is the magnetic field B at a distance r from the wire?
A.
B = μ₀I/(2πr)
B.
B = μ₀I/(4πr²)
C.
B = μ₀I/(2r)
D.
B = μ₀I/(πr²)
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Solution
According to Ampere's Law, the magnetic field B around a long straight conductor is given by B = μ₀I/(2πr).
Correct Answer: A — B = μ₀I/(2πr)
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Q. If a long straight wire carries a current I, what is the direction of the magnetic field at a point located directly above the wire?
A.
Towards the wire
B.
Away from the wire
C.
Clockwise around the wire
D.
Counterclockwise around the wire
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Solution
Using the right-hand rule, the magnetic field at a point directly above the wire is directed counterclockwise around the wire.
Correct Answer: D — Counterclockwise around the wire
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Q. If a long straight wire carries a current I, what is the magnetic field at a distance r from the wire according to Ampere's Law?
A.
μ₀I/(2πr)
B.
μ₀I/(4πr²)
C.
I/(2πr)
D.
μ₀I/(r)
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Solution
Using Ampere's Law, the magnetic field B at a distance r from a long straight wire carrying current I is given by B = μ₀I/(2πr).
Correct Answer: A — μ₀I/(2πr)
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Q. If a long straight wire carries a current I, what is the magnetic field at a distance r from the wire according to the Biot-Savart Law?
A.
μ₀I/(2πr)
B.
μ₀I/(4πr^2)
C.
μ₀I/(2r)
D.
μ₀I/(4πr)
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Solution
The magnetic field B at a distance r from a long straight wire carrying current I is given by B = μ₀I/(2πr).
Correct Answer: A — μ₀I/(2πr)
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Q. If a long straight wire carries a current I, what is the magnetic field B at a distance r from the wire?
A.
B = μ₀I/(2πr)
B.
B = μ₀I/(4πr^2)
C.
B = μ₀I/(2r)
D.
B = μ₀I/(πr^2)
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Solution
The magnetic field B at a distance r from a long straight wire carrying current I is given by B = μ₀I/(2πr).
Correct Answer: A — B = μ₀I/(2πr)
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