If a charge of +3μC is placed in a uniform electric field of strength 2000 N/C, what is the force acting on the charge?

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Q: If a charge of +3μC is placed in a uniform electric field of strength 2000 N/C, what is the force acting on the charge?

Solution: F = qE = (3 × 10^-6 C) * (2000 N/C) = 6 × 10^-3 N = 6000 N.

Steps: 6

Step 1: Identify the charge value. The charge given is +3μC (microcoulombs). Convert this to coulombs: +3μC = 3 × 10^-6 C.
Step 2: Identify the electric field strength. The electric field strength given is 2000 N/C.
Step 3: Use the formula for force in an electric field, which is F = qE, where F is the force, q is the charge, and E is the electric field strength.
Step 4: Substitute the values into the formula: F = (3 × 10^-6 C) * (2000 N/C).
Step 5: Calculate the force: F = 3 × 2000 × 10^-6 N = 6000 × 10^-6 N = 6 × 10^-3 N.
Step 6: Convert the force to a more understandable unit if needed: 6 × 10^-3 N is equal to 0.006 N or 6000 μN.