Q. If a circuit has a total resistance of 12Ω and a current of 1.5A flows through it, what is the total voltage supplied by the battery?
A.
18V
B.
12V
C.
6V
D.
24V
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Solution
Using Ohm's Law, V = I * R = 1.5A * 12Ω = 18V.
Correct Answer: A — 18V
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Q. If a circuit has a total resistance of 12Ω and a current of 3A, what is the voltage supplied by the battery?
A.
36V
B.
24V
C.
12V
D.
9V
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Solution
Using Ohm's Law, V = I * R = 3A * 12Ω = 36V.
Correct Answer: A — 36V
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Q. If a circuit has a total resistance of 5Ω and a current of 3A flows through it, what is the voltage across the circuit?
A.
10V
B.
15V
C.
20V
D.
25V
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Solution
Using Ohm's law, V = I * R = 3A * 5Ω = 15V.
Correct Answer: B — 15V
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Q. If a circuit has a total resistance of 5Ω and a current of 3A, what is the voltage across the circuit?
A.
10V
B.
15V
C.
5V
D.
20V
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Solution
Using Ohm's law, V = I * R = 3A * 5Ω = 15V.
Correct Answer: B — 15V
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Q. If a circuit has a total voltage of 10V and a total current of 2A, what is the total resistance in the circuit?
A.
5Ω
B.
10Ω
C.
15Ω
D.
20Ω
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Solution
Using Ohm's Law (R = V/I), total resistance R = 10V/2A = 5Ω.
Correct Answer: A — 5Ω
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Q. If a circuit has a total voltage of 24V and two resistors of 6Ω and 3Ω in series, what is the current flowing through the circuit?
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Solution
Total resistance R_total = 6Ω + 3Ω = 9Ω. Current I = V/R = 24V / 9Ω = 2.67A.
Correct Answer: B — 3A
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Q. If a circuit has a total voltage of 24V and two resistors of 8Ω and 4Ω in series, what is the current flowing through the circuit?
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Solution
Total resistance R_total = 8Ω + 4Ω = 12Ω. Using Ohm's law, I = V/R = 24V/12Ω = 2A.
Correct Answer: B — 2A
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Q. If a circuit has a total voltage of 30V and a total resistance of 15Ω, what is the total current in the circuit?
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Solution
Using Ohm's law, I = V/R = 30V/15Ω = 2A.
Correct Answer: C — 3A
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Q. If a circuit has a voltage of 24 volts and a current of 6 amperes, what is the resistance?
A.
4 Ω
B.
6 Ω
C.
8 Ω
D.
12 Ω
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Solution
Using Ohm's Law, R = V / I = 24 V / 6 A = 4 Ω.
Correct Answer: C — 8 Ω
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Q. If a circuit has a voltage of 30V and a total resistance of 10Ω, what is the total current flowing through the circuit?
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Solution
Using Ohm's law, I = V/R = 30V/10Ω = 3A.
Correct Answer: C — 4A
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Q. If a circuit has two branches with resistances of 4Ω and 8Ω, what is the total current if the voltage across the branches is 12V?
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Solution
For the 4Ω branch, I1 = V/R1 = 12V / 4Ω = 3A. For the 8Ω branch, I2 = V/R2 = 12V / 8Ω = 1.5A. Total current = I1 + I2 = 3A + 1.5A = 4.5A.
Correct Answer: B — 2A
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Q. If a circular loop of radius R carries a current I, what is the magnetic field at the center of the loop?
A.
μ₀I/2R
B.
μ₀I/4R
C.
μ₀I/R
D.
μ₀I/8R
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Solution
Using Ampere's Law, B = μ₀I/2R at the center of a circular loop.
Correct Answer: A — μ₀I/2R
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Q. If a circular loop of radius R carries a current I, what is the magnetic field at the center of the loop according to Ampere's Law?
A.
μ₀I/2R
B.
μ₀I/4R
C.
μ₀I/R
D.
μ₀I/πR
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Solution
The magnetic field at the center of a circular loop is given by B = (μ₀I)/(2R).
Correct Answer: A — μ₀I/2R
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Q. If a coil with a resistance of 10 ohms has an induced EMF of 20 volts, what is the induced current?
A.
2 A
B.
0.5 A
C.
10 A
D.
20 A
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Solution
Using Ohm's law (I = V/R), the induced current I = 20V / 10Ω = 2 A.
Correct Answer: A — 2 A
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Q. If a concave lens has a focal length of -10 cm, what is the nature of the image formed when an object is placed at 5 cm from the lens?
A.
Real and inverted
B.
Virtual and upright
C.
Real and upright
D.
Virtual and inverted
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Solution
Concave lenses always produce virtual and upright images.
Correct Answer: B — Virtual and upright
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Q. If a concave lens has a focal length of -10 cm, what is the nature of the image formed when the object is placed at 5 cm?
A.
Real and inverted
B.
Virtual and upright
C.
Real and upright
D.
Virtual and inverted
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Solution
Concave lenses always produce virtual and upright images.
Correct Answer: B — Virtual and upright
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Q. If a concave lens has a focal length of -15 cm, what is its power?
A.
-6.67 D
B.
6.67 D
C.
-15 D
D.
15 D
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Solution
Power (P) = 1/f = 1/(-0.15) = -6.67 D.
Correct Answer: A — -6.67 D
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Q. If a concave lens has a focal length of -20 cm, what is the nature of the image formed when an object is placed at 30 cm from the lens?
A.
Real and inverted
B.
Virtual and upright
C.
Real and upright
D.
Virtual and inverted
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Solution
For a concave lens, the image formed is virtual and upright when the object is placed beyond the focal length.
Correct Answer: B — Virtual and upright
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Q. If a concave lens has a focal length of -20 cm, what is the nature of the image formed when an object is placed at 30 cm?
A.
Real and inverted
B.
Virtual and upright
C.
Real and upright
D.
Virtual and inverted
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Solution
The image formed by a concave lens is virtual and upright when the object is placed beyond the focal length.
Correct Answer: B — Virtual and upright
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Q. If a concave mirror has a radius of curvature of 20 cm, what is its focal length?
A.
5 cm
B.
10 cm
C.
15 cm
D.
20 cm
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Solution
The focal length (f) of a concave mirror is half the radius of curvature (R). Therefore, f = R/2 = 20 cm / 2 = 10 cm.
Correct Answer: B — 10 cm
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Q. If a conductor is moved perpendicular to a magnetic field, what is the effect on the induced EMF?
A.
It is maximized
B.
It is minimized
C.
It becomes zero
D.
It fluctuates
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Solution
The induced EMF is maximized when the conductor moves perpendicular to the magnetic field lines.
Correct Answer: A — It is maximized
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Q. If a conductor moves through a magnetic field, what is the induced EMF dependent on?
A.
The speed of the conductor and the strength of the magnetic field
B.
The length of the conductor only
C.
The temperature of the conductor
D.
The type of material of the conductor
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Solution
The induced EMF is dependent on the speed of the conductor and the strength of the magnetic field it moves through.
Correct Answer: A — The speed of the conductor and the strength of the magnetic field
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Q. If a convex lens has a focal length of 15 cm, what is the power of the lens?
A.
+2.5 D
B.
+5 D
C.
+10 D
D.
+15 D
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Solution
Power (P) is given by P = 1/f (in meters). Thus, P = 1/0.15 = +6.67 D.
Correct Answer: B — +5 D
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Q. If a current of 2 A flows through a resistor of 5 ohms, what is the voltage across the resistor?
A.
5 V
B.
10 V
C.
15 V
D.
20 V
Show solution
Solution
Using Ohm's law, V = I * R = 2 A * 5 ohms = 10 V.
Correct Answer: B — 10 V
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Q. If a current of 3 A flows through a resistor of 5 ohms, what is the voltage across the resistor?
A.
15 V
B.
10 V
C.
5 V
D.
20 V
Show solution
Solution
Using Ohm's law, V = I * R = 3 A * 5 ohms = 15 V.
Correct Answer: A — 15 V
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Q. If a current-carrying wire is bent into a circular loop, what is the direction of the magnetic field at the center of the loop according to the Biot-Savart Law?
A.
Out of the plane of the loop
B.
Into the plane of the loop
C.
Clockwise
D.
Counterclockwise
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Solution
According to the right-hand rule applied to the Biot-Savart Law, the magnetic field at the center of a circular loop of current is directed out of the plane of the loop.
Correct Answer: A — Out of the plane of the loop
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Q. If a cyclist is moving at a constant speed and exerts a force of 200 N, what is the power output if the speed is 5 m/s?
A.
1000 W
B.
500 W
C.
200 W
D.
400 W
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Solution
Power can be calculated using P = F * v. Here, F = 200 N and v = 5 m/s. Thus, P = 200 N * 5 m/s = 1000 W.
Correct Answer: A — 1000 W
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Q. If a cyclist travels at 15 km/h and a pedestrian walks at 5 km/h, how much faster is the cyclist than the pedestrian?
A.
5 km/h
B.
10 km/h
C.
15 km/h
D.
20 km/h
Show solution
Solution
Difference in speed = 15 - 5 = 10 km/h.
Correct Answer: B — 10 km/h
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Q. If a damped oscillator has a damping ratio of 0.5, what type of damping does it exhibit?
A.
Underdamped
B.
Critically damped
C.
Overdamped
D.
None of the above
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Solution
A damping ratio (ζ) < 1 indicates underdamped motion.
Correct Answer: A — Underdamped
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Q. If a damped oscillator has a mass of 5 kg, a spring constant of 20 N/m, and a damping coefficient of 1 kg/s, what is the natural frequency of the system?
A.
1 Hz
B.
2 Hz
C.
3 Hz
D.
4 Hz
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Solution
Natural frequency (ω_n) = √(k/m) = √(20/5) = √4 = 2 Hz.
Correct Answer: B — 2 Hz
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