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If a charge of +3μC is placed in an electric field of 500 N/C, what is the force
If a charge of +3μC is placed in an electric field of 500 N/C, what is the force acting on it?
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Q1
If a charge of +3μC is placed in an electric field of 500 N/C, what is the force acting on it?
1500 N
300 N
500 N
750 N
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F = q * E = (3 × 10^-6 C) * (500 N/C) = 1500 N.
Questions & Step-by-step Solutions
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Q
Q: If a charge of +3μC is placed in an electric field of 500 N/C, what is the force acting on it?
Solution:
F = q * E = (3 × 10^-6 C) * (500 N/C) = 1500 N.
Steps: 7
Show Steps
Step 1: Identify the charge (q) given in the problem. It is +3μC (microcoulombs).
Step 2: Convert the charge from microcoulombs to coulombs. 1μC = 10^-6 C, so +3μC = 3 × 10^-6 C.
Step 3: Identify the electric field strength (E) given in the problem. It is 500 N/C (newtons per coulomb).
Step 4: Use the formula for force (F) in an electric field, which is F = q * E.
Step 5: Substitute the values into the formula: F = (3 × 10^-6 C) * (500 N/C).
Step 6: Calculate the force: F = 3 × 500 × 10^-6 N = 1500 × 10^-6 N = 0.0015 N.
Step 7: The final answer for the force acting on the charge is 0.0015 N or 1500 μN.
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