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If a charge of +3μC is placed in an electric field of 2000 N/C, what is the forc
If a charge of +3μC is placed in an electric field of 2000 N/C, what is the force experienced by the charge?
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Q1
If a charge of +3μC is placed in an electric field of 2000 N/C, what is the force experienced by the charge?
6000 N
3000 N
4000 N
2000 N
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Force F = qE = (3 × 10^-6 C) * (2000 N/C) = 6000 N.
Questions & Step-by-step Solutions
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Q
Q: If a charge of +3μC is placed in an electric field of 2000 N/C, what is the force experienced by the charge?
Solution:
Force F = qE = (3 × 10^-6 C) * (2000 N/C) = 6000 N.
Steps: 6
Show Steps
Step 1: Identify the charge (q) given in the problem, which is +3μC. Convert this to coulombs: +3μC = 3 × 10^-6 C.
Step 2: Identify the electric field strength (E) given in the problem, which is 2000 N/C.
Step 3: Use the formula for force (F) experienced by a charge in an electric field: F = qE.
Step 4: Substitute the values into the formula: F = (3 × 10^-6 C) * (2000 N/C).
Step 5: Calculate the force: F = 3 × 2000 × 10^-6 N = 6000 N.
Step 6: Conclude that the force experienced by the charge is 6000 N.
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