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If a circuit has two branches with resistances of 4Ω and 8Ω, what is the total c
If a circuit has two branches with resistances of 4Ω and 8Ω, what is the total current if the voltage across the branches is 12V?
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Practice Questions
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If a circuit has two branches with resistances of 4Ω and 8Ω, what is the total current if the voltage across the branches is 12V?
1A
2A
3A
4A
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For the 4Ω branch, I1 = V/R1 = 12V / 4Ω = 3A. For the 8Ω branch, I2 = V/R2 = 12V / 8Ω = 1.5A. Total current = I1 + I2 = 3A + 1.5A = 4.5A.
Questions & Step-by-step Solutions
1 item
Q
Q: If a circuit has two branches with resistances of 4Ω and 8Ω, what is the total current if the voltage across the branches is 12V?
Solution:
For the 4Ω branch, I1 = V/R1 = 12V / 4Ω = 3A. For the 8Ω branch, I2 = V/R2 = 12V / 8Ω = 1.5A. Total current = I1 + I2 = 3A + 1.5A = 4.5A.
Steps: 8
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Step 1: Identify the resistances in the circuit. We have two branches: one with 4Ω and another with 8Ω.
Step 2: Note the voltage across the branches, which is 12V.
Step 3: Calculate the current in the 4Ω branch using Ohm's Law (I = V/R). For the 4Ω branch, I1 = 12V / 4Ω.
Step 4: Perform the calculation for the 4Ω branch: I1 = 12V / 4Ω = 3A.
Step 5: Calculate the current in the 8Ω branch using Ohm's Law (I = V/R). For the 8Ω branch, I2 = 12V / 8Ω.
Step 6: Perform the calculation for the 8Ω branch: I2 = 12V / 8Ω = 1.5A.
Step 7: Add the currents from both branches to find the total current: Total current = I1 + I2.
Step 8: Perform the addition: Total current = 3A + 1.5A = 4.5A.
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