Q. An object is placed at a distance of 30 cm from a convex lens of focal length 15 cm. What is the distance of the image from the lens?
A.
10 cm
B.
15 cm
C.
20 cm
D.
30 cm
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Solution
Using the lens formula, 1/f = 1/v - 1/u. Here, f = 15 cm, u = -30 cm. Solving gives v = 10 cm.
Correct Answer: C — 20 cm
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Q. An object is placed at a distance of 40 cm from a convex lens of focal length 20 cm. Where will the image be formed?
A.
10 cm
B.
20 cm
C.
30 cm
D.
40 cm
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Solution
Using the lens formula 1/f = 1/v - 1/u, we find v = 10 cm.
Correct Answer: A — 10 cm
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Q. An object is placed at the focus of a concave lens. What type of image is formed?
A.
Real and inverted
B.
Virtual and erect
C.
Real and erect
D.
Virtual and inverted
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Solution
A concave lens always forms a virtual and erect image regardless of the object position.
Correct Answer: B — Virtual and erect
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Q. An object is placed at the focus of a concave mirror. What type of image is formed?
A.
Real and inverted
B.
Virtual and upright
C.
No image
D.
Real and upright
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Solution
When the object is at the focus of a concave mirror, the rays are parallel after reflection, resulting in no image being formed.
Correct Answer: C — No image
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Q. An object is projected at an angle of 60 degrees with an initial speed of 30 m/s. What is the horizontal component of its velocity?
A.
15 m/s
B.
25 m/s
C.
30 m/s
D.
20 m/s
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Solution
Horizontal component (v_x) = u * cos(θ) = 30 * (1/2) = 15 m/s.
Correct Answer: B — 25 m/s
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Q. An object is projected at an angle of 60 degrees with an initial speed of 30 m/s. What is the vertical component of its velocity?
A.
15 m/s
B.
25 m/s
C.
30 m/s
D.
20 m/s
Show solution
Solution
Vertical component (v_y) = u * sin(θ) = 30 * (√3/2) = 25.98 m/s.
Correct Answer: B — 25 m/s
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Q. An object is projected at an angle of 60 degrees with an initial velocity of 30 m/s. What is the horizontal component of its velocity?
A.
15 m/s
B.
25 m/s
C.
30 m/s
D.
20 m/s
Show solution
Solution
Horizontal component Vx = u * cos(θ) = 30 * (1/2) = 15 m/s.
Correct Answer: B — 25 m/s
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Q. An object is projected at an angle of 60 degrees with an initial velocity of 30 m/s. What is the time of flight?
A.
3 s
B.
5 s
C.
6 s
D.
10 s
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Solution
Time of flight (T) = (2u * sin(θ)) / g = (2 * 30 * √3/2) / 9.8 = 5.18 s.
Correct Answer: C — 6 s
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Q. An object is thrown at an angle of 30 degrees with a speed of 40 m/s. What is the time of flight until it returns to the same vertical level?
A.
4 s
B.
5 s
C.
6 s
D.
8 s
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Solution
Time of flight (T) = (2 * u * sin(θ)) / g = (2 * 40 * 0.5) / 9.8 ≈ 4.08 s.
Correct Answer: C — 6 s
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Q. An object is thrown horizontally from the top of a 45 m high cliff. How far from the base of the cliff will it land if the initial speed is 10 m/s?
A.
10 m
B.
20 m
C.
30 m
D.
40 m
Show solution
Solution
Time of flight (t) = √(2h/g) = √(2*45/9.8) = 3.03 s. Horizontal distance = speed * time = 10 * 3.03 = 30.3 m.
Correct Answer: B — 20 m
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Q. An object is thrown horizontally from the top of a 45 m high cliff. How far from the base of the cliff will it land if it is thrown with a speed of 10 m/s?
A.
20 m
B.
30 m
C.
40 m
D.
50 m
Show solution
Solution
Time of flight (t) = √(2h/g) = √(2*45/9.8) = 3.03 s. Horizontal distance = speed * time = 10 * 3.03 = 30.3 m.
Correct Answer: B — 30 m
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Q. An object is thrown horizontally from the top of a cliff 80 m high. How long does it take to hit the ground?
A.
2 s
B.
4 s
C.
5 s
D.
8 s
Show solution
Solution
Using h = (1/2)gt^2, we have 80 = (1/2)(9.8)t^2, solving gives t ≈ 4 s.
Correct Answer: B — 4 s
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Q. An object is thrown horizontally from the top of a cliff of height 80 m. How long does it take to hit the ground?
A.
2 s
B.
4 s
C.
5 s
D.
8 s
Show solution
Solution
Using h = (1/2)gt^2, we have 80 = (1/2)(9.8)t^2, solving gives t ≈ 4 s.
Correct Answer: B — 4 s
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Q. An object is thrown horizontally from the top of a tower 80 m high. How long will it take to hit the ground?
A.
4 s
B.
5 s
C.
3 s
D.
2 s
Show solution
Solution
Using the equation h = (1/2)gt², where h = 80 m and g = 9.8 m/s², we have 80 = (1/2)*9.8*t². Solving gives t² = 16.33, so t ≈ 4 s.
Correct Answer: B — 5 s
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Q. An object is thrown upwards with a speed of 20 m/s. How long will it take to reach the maximum height? (Assume g = 10 m/s²)
A.
1 s
B.
2 s
C.
3 s
D.
4 s
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Solution
Time to reach maximum height = initial velocity / g = 20 m/s / 10 m/s² = 2 s.
Correct Answer: B — 2 s
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Q. An object is thrown vertically upward with a speed of 20 m/s. How high will it rise before coming to rest?
A.
10 m
B.
20 m
C.
30 m
D.
40 m
Show solution
Solution
Maximum height (H) = (u²)/(2g) = (20²)/(2*9.8) ≈ 20.4 m.
Correct Answer: C — 30 m
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Q. An object is thrown vertically upward with a speed of 30 m/s. How high will it rise before coming to rest?
A.
45 m
B.
90 m
C.
135 m
D.
180 m
Show solution
Solution
Using the formula: h = (v² - u²) / (2g), where v = 0 m/s, u = 30 m/s, g = 9.8 m/s². h = (0 - 30²) / (2 * -9.8) = 45.92 m, approximately 45 m.
Correct Answer: B — 90 m
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Q. An object is thrown vertically upward with a speed of 30 m/s. How high will it rise before coming to a momentary stop?
A.
45 m
B.
60 m
C.
90 m
D.
135 m
Show solution
Solution
Using the formula: h = (v² - u²) / (2g), where v = 0 m/s (at the highest point), u = 30 m/s, g = 9.8 m/s². h = (0 - 30²) / (2 * -9.8) = 45.92 m, approximately 45 m.
Correct Answer: B — 60 m
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Q. An object is thrown vertically upwards with a speed of 15 m/s. What is the maximum height it reaches? (g = 10 m/s²)
A.
11.25 m
B.
22.5 m
C.
15 m
D.
20 m
Show solution
Solution
Maximum Height (h) = v^2 / (2g) = (15^2) / (2 * 10) = 11.25 m
Correct Answer: B — 22.5 m
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Q. An object is thrown vertically upwards with a speed of 20 m/s. How high will it rise before coming to rest? (Take g = 10 m/s²) (2020)
A.
20 m
B.
40 m
C.
50 m
D.
80 m
Show solution
Solution
Using the formula h = (u²)/(2g) = (20²)/(2 × 10) = 20 m.
Correct Answer: B — 40 m
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Q. An object is thrown vertically upwards with a speed of 20 m/s. How long will it take to reach the maximum height?
A.
1 s
B.
2 s
C.
3 s
D.
4 s
Show solution
Solution
Time to reach maximum height (t) = u/g = 20/9.8 = 2.04 s.
Correct Answer: B — 2 s
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Q. An object is thrown vertically upwards with a speed of 30 m/s. How high will it rise before coming to rest?
A.
45 m
B.
60 m
C.
90 m
D.
120 m
Show solution
Solution
Using the formula: h = (v² - u²) / (2g), where v = 0 m/s, u = 30 m/s, g = 9.8 m/s². h = (0 - 30²) / (2 * -9.8) = 45.92 m, approximately 45 m.
Correct Answer: B — 60 m
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Q. An object is thrown vertically upwards with a speed of 30 m/s. How high will it rise before coming to rest momentarily?
A.
45 m
B.
60 m
C.
90 m
D.
135 m
Show solution
Solution
Using the formula: h = (v² - u²) / (2g), where v = 0 m/s (at the highest point), u = 30 m/s, g = 9.8 m/s². h = (0 - 30²) / (2 * -9.8) = 45.92 m, approximately 45 m.
Correct Answer: B — 60 m
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Q. An object is thrown vertically upwards with a velocity of 20 m/s. How high will it rise? (Assume g = 10 m/s²) (2020)
A.
20 m
B.
30 m
C.
40 m
D.
50 m
Show solution
Solution
Using h = v²/(2g) = (20 m/s)² / (2 × 10 m/s²) = 20 m.
Correct Answer: A — 20 m
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Q. An object moves in a circular path with a radius of 10 m at a speed of 5 m/s. What is the period of the motion?
A.
2π s
B.
4π s
C.
10 s
D.
20 s
Show solution
Solution
Period (T) = (2πr)/v = (2π * 10)/5 = 4π s.
Correct Answer: A — 2π s
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Q. An object moves in a straight line with a uniform speed of 10 m/s. How far will it travel in 15 seconds? (2023)
A.
100 m
B.
120 m
C.
150 m
D.
200 m
Show solution
Solution
Distance = Speed × Time = 10 m/s × 15 s = 150 m.
Correct Answer: C — 150 m
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Q. An object moves in a straight line with a uniform speed of 30 m/s. How far will it travel in 15 seconds? (2022)
A.
300 m
B.
450 m
C.
600 m
D.
750 m
Show solution
Solution
Distance = Speed × Time = 30 m/s × 15 s = 450 m.
Correct Answer: C — 600 m
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Q. An object moves in a straight line with a velocity of 10 m/s. If it accelerates at 2 m/s² for 5 seconds, what will be its final velocity?
A.
20 m/s
B.
30 m/s
C.
10 m/s
D.
15 m/s
Show solution
Solution
Final velocity (v) = u + at = 10 + (2 * 5) = 20 m/s.
Correct Answer: B — 30 m/s
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Q. An object moves in a straight line with an acceleration of 2 m/s². If its initial velocity is 3 m/s, what will be its velocity after 5 seconds?
A.
8 m/s
B.
10 m/s
C.
13 m/s
D.
15 m/s
Show solution
Solution
Final velocity (v) = u + at = 3 + (2 * 5) = 13 m/s.
Correct Answer: C — 13 m/s
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Q. An object moves in a straight line with an acceleration of 2 m/s². If its initial velocity is 10 m/s, what will be its velocity after 5 seconds?
A.
10 m/s
B.
20 m/s
C.
30 m/s
D.
40 m/s
Show solution
Solution
Final velocity (v) = u + at = 10 + 2*5 = 20 m/s.
Correct Answer: C — 30 m/s
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