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An object is projected at an angle of 60 degrees with an initial speed of 30 m/s
An object is projected at an angle of 60 degrees with an initial speed of 30 m/s. What is the vertical component of its velocity?
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Practice Questions
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Q1
An object is projected at an angle of 60 degrees with an initial speed of 30 m/s. What is the vertical component of its velocity?
15 m/s
25 m/s
30 m/s
20 m/s
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Vertical component (v_y) = u * sin(θ) = 30 * (√3/2) = 25.98 m/s.
Questions & Step-by-step Solutions
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Q
Q: An object is projected at an angle of 60 degrees with an initial speed of 30 m/s. What is the vertical component of its velocity?
Solution:
Vertical component (v_y) = u * sin(θ) = 30 * (√3/2) = 25.98 m/s.
Steps: 6
Show Steps
Step 1: Identify the initial speed (u) of the object, which is given as 30 m/s.
Step 2: Identify the angle of projection (θ), which is given as 60 degrees.
Step 3: Use the sine function to find the vertical component of the velocity. The formula is v_y = u * sin(θ).
Step 4: Calculate sin(60 degrees). The value of sin(60 degrees) is √3/2.
Step 5: Substitute the values into the formula: v_y = 30 * (√3/2).
Step 6: Calculate the result: v_y = 30 * 0.866 (approximately) = 25.98 m/s.
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