Q. An object is in equilibrium under the action of three forces: 10 N, 15 N, and 20 N. What is the resultant force acting on the object? (2019)
-
A.
0 N
-
B.
5 N
-
C.
10 N
-
D.
15 N
Solution
In equilibrium, the resultant force is 0 N.
Correct Answer: A — 0 N
Learn More →
Q. An object is in equilibrium. If two forces of 10 N and 15 N act on it in opposite directions, what is the net force?
-
A.
5 N
-
B.
10 N
-
C.
15 N
-
D.
0 N
Solution
In equilibrium, the net force is zero. The forces cancel each other out: 15 N - 10 N = 5 N.
Correct Answer: A — 5 N
Learn More →
Q. An object is in equilibrium. What can be said about the net force acting on it?
-
A.
It is zero
-
B.
It is equal to its weight
-
C.
It is equal to the applied force
-
D.
It is maximum
Solution
For an object in equilibrium, the net force acting on it must be zero.
Correct Answer: A — It is zero
Learn More →
Q. An object is in free fall. What is its acceleration?
-
A.
0 m/s²
-
B.
9.8 m/s²
-
C.
10 m/s²
-
D.
5 m/s²
Solution
In free fall, the only force acting on the object is gravity, so its acceleration is approximately 9.8 m/s².
Correct Answer: B — 9.8 m/s²
Learn More →
Q. An object is lifted to a height of 10 m. If the mass of the object is 5 kg, what is the gravitational potential energy gained?
-
A.
50 J
-
B.
100 J
-
C.
150 J
-
D.
200 J
Solution
Potential Energy = mass × g × height = 5 kg × 9.8 m/s² × 10 m = 490 J.
Correct Answer: B — 100 J
Learn More →
Q. An object is lifted to a height of 10 m. If the mass of the object is 5 kg, what is the gravitational potential energy gained? (g = 9.8 m/s²)
-
A.
49 J
-
B.
98 J
-
C.
245 J
-
D.
490 J
Solution
Potential Energy (PE) = mgh = 5 kg * 9.8 m/s² * 10 m = 490 J.
Correct Answer: B — 98 J
Learn More →
Q. An object is lifted vertically 10 m against gravity. If the mass of the object is 5 kg, what is the work done against gravity?
-
A.
50 J
-
B.
100 J
-
C.
150 J
-
D.
200 J
Solution
Work done = mass × g × height = 5 kg × 9.8 m/s² × 10 m = 490 J.
Correct Answer: B — 100 J
Learn More →
Q. An object is lifted vertically 10 m. If the mass of the object is 5 kg, what is the gravitational potential energy gained?
-
A.
50 J
-
B.
100 J
-
C.
150 J
-
D.
200 J
Solution
Potential Energy (PE) = mgh = 5 kg * 9.8 m/s² * 10 m = 490 J.
Correct Answer: B — 100 J
Learn More →
Q. An object is lifted vertically 3 m against gravity. If the mass of the object is 4 kg, what is the work done against gravity? (g = 9.8 m/s²)
-
A.
117.6 J
-
B.
39.2 J
-
C.
29.4 J
-
D.
19.6 J
Solution
Work done = mgh = 4 kg × 9.8 m/s² × 3 m = 117.6 J.
Correct Answer: A — 117.6 J
Learn More →
Q. An object is lifted vertically 4 m against gravity. If the mass of the object is 3 kg, what is the work done against gravity? (g = 9.8 m/s²)
-
A.
117.6 J
-
B.
29.4 J
-
C.
39.2 J
-
D.
78.4 J
Solution
Work done (W) = mgh = 3 kg × 9.8 m/s² × 4 m = 117.6 J.
Correct Answer: A — 117.6 J
Learn More →
Q. An object is lifted vertically 4 m against gravity. If the mass of the object is 10 kg, what is the work done against gravity? (g = 9.8 m/s²)
-
A.
39.2 J
-
B.
78.4 J
-
C.
98 J
-
D.
196 J
Solution
Work done (W) = mgh = 10 kg × 9.8 m/s² × 4 m = 392 J.
Correct Answer: B — 78.4 J
Learn More →
Q. An object is lifted vertically 4 m against gravity. If the mass of the object is 10 kg, what is the work done against gravity? (2021)
-
A.
40 J
-
B.
80 J
-
C.
100 J
-
D.
200 J
Solution
Work Done = m * g * h = 10 kg * 9.8 m/s² * 4 m = 392 J (approx. 400 J).
Correct Answer: B — 80 J
Learn More →
Q. An object is lifted vertically 4 m. If the weight of the object is 50 N, how much work is done against gravity?
-
A.
100 J
-
B.
200 J
-
C.
150 J
-
D.
50 J
Solution
Work done (W) = Force (F) × Distance (d) = 50 N × 4 m = 200 J.
Correct Answer: B — 200 J
Learn More →
Q. An object is lifted vertically to a height of 10 m. If the mass of the object is 5 kg, what is the work done against gravity?
-
A.
50 J
-
B.
100 J
-
C.
150 J
-
D.
200 J
Solution
Work done = mass × g × height = 5 kg × 9.8 m/s² × 10 m = 490 J.
Correct Answer: B — 100 J
Learn More →
Q. An object is moving in a circular path with a constant speed. What can be said about the work done by the centripetal force?
-
A.
Positive work
-
B.
Negative work
-
C.
Zero work
-
D.
Depends on speed
Solution
Centripetal force does no work as it acts perpendicular to the direction of motion.
Correct Answer: C — Zero work
Learn More →
Q. An object is moving in a circular path with a constant speed. What type of energy is primarily involved?
-
A.
Kinetic Energy
-
B.
Potential Energy
-
C.
Mechanical Energy
-
D.
Thermal Energy
Solution
The object has Kinetic Energy due to its motion in the circular path.
Correct Answer: A — Kinetic Energy
Learn More →
Q. An object is moving in a circular path with a radius of 10 m and a speed of 5 m/s. What is the net force acting on the object if its mass is 2 kg?
-
A.
1 N
-
B.
2 N
-
C.
5 N
-
D.
10 N
Solution
Centripetal force (F_c) = mv²/r = 2 kg * (5 m/s)² / (10 m) = 5 N.
Correct Answer: D — 10 N
Learn More →
Q. An object is moving in a circular path with a radius of 10 m at a speed of 5 m/s. What is the period of the motion?
-
A.
2π s
-
B.
4π s
-
C.
10 s
-
D.
20 s
Solution
Period (T) = 2πr/v = 2π(10)/5 = 4π s.
Correct Answer: A — 2π s
Learn More →
Q. An object is moving in a circular path with a radius of 3 m and an angular speed of 2 rad/s. What is the linear speed of the object?
-
A.
3 m/s
-
B.
6 m/s
-
C.
9 m/s
-
D.
12 m/s
Solution
Linear speed (v) = rω = 3 m * 2 rad/s = 6 m/s.
Correct Answer: B — 6 m/s
Learn More →
Q. An object is moving with a speed of 15 m/s and has a mass of 3 kg. What is its kinetic energy?
-
A.
67.5 J
-
B.
45 J
-
C.
90 J
-
D.
135 J
Solution
Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 3 kg × (15 m/s)² = 0.5 × 3 × 225 = 337.5 J.
Correct Answer: C — 90 J
Learn More →
Q. An object is moving with a velocity of 10 m/s. What is its kinetic energy if its mass is 2 kg? (2022)
-
A.
10 J
-
B.
20 J
-
C.
30 J
-
D.
40 J
Solution
Kinetic Energy = (1/2)mv² = (1/2) × 2 kg × (10 m/s)² = 100 J
Correct Answer: B — 20 J
Learn More →
Q. An object is placed 10 cm from a convex lens with a focal length of 5 cm. What is the nature of the image formed? (2022)
-
A.
Real and inverted
-
B.
Virtual and erect
-
C.
Real and erect
-
D.
Virtual and inverted
Solution
Since the object distance is less than the focal length, the image formed is virtual and erect.
Correct Answer: B — Virtual and erect
Learn More →
Q. An object is placed 10 cm in front of a convex mirror with a focal length of 5 cm. What is the nature of the image formed?
-
A.
Real and inverted
-
B.
Virtual and erect
-
C.
Real and erect
-
D.
Virtual and inverted
Solution
Convex mirrors always produce virtual and erect images.
Correct Answer: B — Virtual and erect
Learn More →
Q. An object is placed 15 cm in front of a convex lens of focal length 10 cm. What is the position of the image formed? (2020)
-
A.
5 cm
-
B.
10 cm
-
C.
30 cm
-
D.
15 cm
Solution
Using the lens formula: 1/f = 1/v - 1/u, where f = 10 cm and u = -15 cm, we find v = 30 cm.
Correct Answer: C — 30 cm
Learn More →
Q. An object is placed 25 cm from a convex lens of focal length 10 cm. Where is the image formed?
-
A.
10 cm
-
B.
15 cm
-
C.
20 cm
-
D.
30 cm
Solution
Using the lens formula 1/f = 1/v - 1/u, we find v = 20 cm.
Correct Answer: C — 20 cm
Learn More →
Q. An object is placed 30 cm from a concave lens of focal length 15 cm. What is the nature of the image formed?
-
A.
Real and inverted
-
B.
Virtual and erect
-
C.
Real and erect
-
D.
Virtual and inverted
Solution
For a concave lens, the image formed is virtual and erect when the object is placed in front of it.
Correct Answer: B — Virtual and erect
Learn More →
Q. An object is placed 30 cm in front of a convex lens of focal length 15 cm. What is the position of the image formed? (2020)
-
A.
10 cm
-
B.
15 cm
-
C.
20 cm
-
D.
25 cm
Solution
Using the lens formula 1/f = 1/v - 1/u, where u = -30 cm and f = 15 cm, we find v = 10 cm.
Correct Answer: D — 25 cm
Learn More →
Q. An object is placed 40 cm from a convex lens with a focal length of 10 cm. Where is the image formed?
-
A.
At 10 cm
-
B.
At 20 cm
-
C.
At 30 cm
-
D.
At 40 cm
Solution
Using the lens formula, the image is formed at 30 cm on the opposite side.
Correct Answer: C — At 30 cm
Learn More →
Q. An object is placed 50 cm from a converging lens of focal length 25 cm. Where will the image be formed?
-
A.
16.67 cm
-
B.
33.33 cm
-
C.
25 cm
-
D.
20 cm
Solution
Using the lens formula 1/f = 1/v - 1/u, we find v = 33.33 cm.
Correct Answer: B — 33.33 cm
Learn More →
Q. An object is placed at a distance of 15 cm from a convex lens of focal length 10 cm. Where is the image formed?
-
A.
5 cm
-
B.
10 cm
-
C.
15 cm
-
D.
20 cm
Solution
Using the lens formula, 1/f = 1/v - 1/u, we find v = 30 cm, meaning the image is formed 30 cm on the opposite side.
Correct Answer: D — 20 cm
Learn More →
Showing 2761 to 2790 of 24796 (827 Pages)
