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An object is thrown vertically upwards with a speed of 15 m/s. What is the maxim
An object is thrown vertically upwards with a speed of 15 m/s. What is the maximum height it reaches? (g = 10 m/s²)
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Practice Questions
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Q1
An object is thrown vertically upwards with a speed of 15 m/s. What is the maximum height it reaches? (g = 10 m/s²)
11.25 m
22.5 m
15 m
20 m
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Maximum Height (h) = v^2 / (2g) = (15^2) / (2 * 10) = 11.25 m
Questions & Step-by-step Solutions
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Q
Q: An object is thrown vertically upwards with a speed of 15 m/s. What is the maximum height it reaches? (g = 10 m/s²)
Solution:
Maximum Height (h) = v^2 / (2g) = (15^2) / (2 * 10) = 11.25 m
Steps: 7
Show Steps
Step 1: Identify the initial speed (v) of the object, which is 15 m/s.
Step 2: Identify the acceleration due to gravity (g), which is 10 m/s².
Step 3: Use the formula for maximum height (h) reached by the object: h = v^2 / (2g).
Step 4: Calculate v^2: 15^2 = 225.
Step 5: Calculate 2g: 2 * 10 = 20.
Step 6: Divide v^2 by 2g: 225 / 20 = 11.25.
Step 7: Conclude that the maximum height reached by the object is 11.25 m.
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