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An object is moving in a circular path with a radius of 10 m and a speed of 5 m/
An object is moving in a circular path with a radius of 10 m and a speed of 5 m/s. What is the net force acting on the object if its mass is 2 kg?
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Q1
An object is moving in a circular path with a radius of 10 m and a speed of 5 m/s. What is the net force acting on the object if its mass is 2 kg?
1 N
2 N
5 N
10 N
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Centripetal force (F_c) = mv²/r = 2 kg * (5 m/s)² / (10 m) = 5 N.
Questions & Step-by-step Solutions
1 item
Q
Q: An object is moving in a circular path with a radius of 10 m and a speed of 5 m/s. What is the net force acting on the object if its mass is 2 kg?
Solution:
Centripetal force (F_c) = mv²/r = 2 kg * (5 m/s)² / (10 m) = 5 N.
Steps: 9
Show Steps
Step 1: Identify the formula for centripetal force, which is F_c = mv²/r.
Step 2: Determine the mass (m) of the object, which is given as 2 kg.
Step 3: Determine the speed (v) of the object, which is given as 5 m/s.
Step 4: Determine the radius (r) of the circular path, which is given as 10 m.
Step 5: Substitute the values into the formula: F_c = 2 kg * (5 m/s)² / (10 m).
Step 6: Calculate (5 m/s)², which equals 25 m²/s².
Step 7: Multiply 2 kg by 25 m²/s², which equals 50 kg*m²/s².
Step 8: Divide 50 kg*m²/s² by 10 m, which equals 5 N.
Step 9: Conclude that the net force acting on the object is 5 N.
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