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An object is moving in a circular path with a radius of 10 m at a speed of 5 m/s
An object is moving in a circular path with a radius of 10 m at a speed of 5 m/s. What is the period of the motion?
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Q1
An object is moving in a circular path with a radius of 10 m at a speed of 5 m/s. What is the period of the motion?
2π s
4π s
10 s
20 s
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Period (T) = 2πr/v = 2π(10)/5 = 4π s.
Questions & Step-by-step Solutions
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Q
Q: An object is moving in a circular path with a radius of 10 m at a speed of 5 m/s. What is the period of the motion?
Solution:
Period (T) = 2πr/v = 2π(10)/5 = 4π s.
Steps: 7
Show Steps
Step 1: Identify the radius of the circular path. In this case, the radius (r) is 10 meters.
Step 2: Identify the speed of the object. Here, the speed (v) is 5 meters per second.
Step 3: Use the formula for the period (T) of circular motion, which is T = 2πr/v.
Step 4: Substitute the values into the formula: T = 2π(10)/5.
Step 5: Calculate the numerator: 2π(10) = 20π.
Step 6: Divide the result by the speed: 20π/5 = 4π.
Step 7: The period of the motion is 4π seconds.
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