The work done by a gas during expansion at constant pressure is given by W = PΔV.

During isothermal expansion, the work done by the gas is equal to the heat absorbed, as the internal energy remains constant.

Work done (W) = P * ΔV = 3 atm * (5 L - 2 L) = 3 atm * 3 L = 9 atm·L = 15 J (1 atm·L = 101.325 J)

Work done (W) = PΔV = P(V_final - V_initial) = 5 atm * (5 L - 2 L) = 15 L·atm.

The work done by an ideal gas during an isobaric (constant pressure) expansion is given by W = PΔV.

The work done by an ideal gas during an isobaric process is given by W = PΔV.

The work done by an ideal gas during an isothermal expansion is W = nRT ln(Vf/Vi).

The work done during an isothermal expansion is given by W = nRT ln(V2/V1).

The work done by an ideal gas during an isothermal expansion is given by W = nRT ln(Vf/Vi).

For an ideal gas undergoing isothermal expansion, the work done is given by W = nRT ln(Vf/Vi).

Frictional force F_friction = μk * N = 0.4 * 5 kg * 9.8 m/s² = 19.6 N. Work done by friction = -F_friction * distance = -19.6 N * 2 m = -39.2 N·m, approximately -40 N·m.

In an isochoric process, the volume remains constant, so no work is done by the system (W = PΔV = 0).

In an isochoric process, the volume remains constant, so no work is done by the system (W = PΔV = 0).

The work done by the system during expansion against a constant external pressure is given by W = PΔV.

Work done W = F * d = q * E * d = (2 × 10^-6 C) * (500 N/C) * (0.4 m) = 0.4 J = 80 J.

Work done W = q * V = (2 × 10^-6 C) * (5 V) = 10 μJ.

W = q * V = 2 × 10^-6 C * 10 V = 20 × 10^-6 J = 20 μJ.

Work done W = q * ΔV = 2 × 10^-6 C * (100 V - 50 V) = 2 × 10^-6 * 50 = 0.1 mJ.

Work done W = q * ΔV = (2 × 10^-6 C) * (100 V - 50 V) = 100 μJ.

The work done is equal to the change in gravitational potential energy, which depends on the initial and final positions.

The work done in moving an object in a uniform gravitational field depends only on the height difference between points A and B.

The work done in moving an object in a gravitational field depends only on the initial and final positions, not the path taken.

In an isochoric process, the volume remains constant, which means no work is done on or by the gas. Therefore, the work done is zero.

The work done on a gas during isothermal compression is positive, as work is done on the gas to compress it.

Work done (W) = P * ΔV = 2 atm * (2 L - 4 L) = 2 atm * (-2 L) = -4 L·atm (work done on the gas is positive).

Work done (W) = P * ΔV = 200 kPa * (2 L - 5 L) = 200 kPa * (-3 L) = -600 J (work done on the gas).

Work done (W) = nRT ln(Vf/Vi) = 1 mol * 8.314 J/(mol K) * 300 K * ln(20/10) = 2.5 kJ.

Work done = nRT ln(Vf/Vi) = 1 mol × 8.31 J/mol·K × 300 K × ln(20/10) = 1660 J.

Work done W = nRT ln(Vf/Vi) = 1 * 8.314 * 300 * ln(20/10) = 600 J.

Work done (W) = F × d = 50 N × 3 m = 150 J.