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What is the work done in moving a charge of 2 μC from a point at 50 V to another
What is the work done in moving a charge of 2 μC from a point at 50 V to another at 100 V?
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Practice Questions
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Q1
What is the work done in moving a charge of 2 μC from a point at 50 V to another at 100 V?
100 μJ
200 μJ
150 μJ
50 μJ
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Work done W = q * ΔV = (2 × 10^-6 C) * (100 V - 50 V) = 100 μJ.
Questions & Step-by-step Solutions
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Q
Q: What is the work done in moving a charge of 2 μC from a point at 50 V to another at 100 V?
Solution:
Work done W = q * ΔV = (2 × 10^-6 C) * (100 V - 50 V) = 100 μJ.
Steps: 6
Show Steps
Step 1: Identify the charge being moved. In this case, it is 2 μC (microcoulombs). Convert this to coulombs: 2 μC = 2 × 10^-6 C.
Step 2: Identify the initial and final voltages. The initial voltage is 50 V and the final voltage is 100 V.
Step 3: Calculate the change in voltage (ΔV). This is done by subtracting the initial voltage from the final voltage: ΔV = 100 V - 50 V = 50 V.
Step 4: Use the formula for work done (W) in moving a charge in an electric field: W = q * ΔV, where q is the charge and ΔV is the change in voltage.
Step 5: Substitute the values into the formula: W = (2 × 10^-6 C) * (50 V).
Step 6: Calculate the work done: W = 2 × 10^-6 C * 50 V = 100 × 10^-6 J = 100 μJ.
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