Q. What is the voltage drop across a 5Ω resistor carrying a current of 3A?
-
A.
5V
-
B.
10V
-
C.
15V
-
D.
20V
Solution
Using Ohm's law, V = I * R = 3A * 5Ω = 15V.
Correct Answer: C — 15V
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Q. What is the volume occupied by 1 mole of an ideal gas at STP (Standard Temperature and Pressure)?
-
A.
22.4 L
-
B.
24.0 L
-
C.
18.0 L
-
D.
20.0 L
Solution
At STP, 1 mole of an ideal gas occupies 22.4 liters.
Correct Answer: A — 22.4 L
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Q. What is the volume occupied by 1 mole of an ideal gas at STP?
-
A.
22.4 L
-
B.
24 L
-
C.
20 L
-
D.
18 L
Solution
At STP, 1 mole of an ideal gas occupies 22.4 liters.
Correct Answer: A — 22.4 L
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Q. What is the volume occupied by 4 moles of an ideal gas at STP?
-
A.
22.4 L
-
B.
44.8 L
-
C.
67.2 L
-
D.
89.6 L
Solution
At STP, 1 mole of gas occupies 22.4 L. Therefore, 4 moles occupy 4 x 22.4 L = 89.6 L.
Correct Answer: B — 44.8 L
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Q. What is the volume of 0.2 M NaOH required to neutralize 0.1 M HCl in 250 mL? (2020)
-
A.
125 mL
-
B.
250 mL
-
C.
500 mL
-
D.
100 mL
Solution
Using the formula M1V1 = M2V2, (0.1 M)(0.25 L) = (0.2 M)(V2). V2 = 0.125 L = 125 mL.
Correct Answer: A — 125 mL
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Q. What is the volume of 1 liter in cubic meters?
-
A.
0.001
-
B.
0.01
-
C.
1
-
D.
1000
Solution
1 liter is equal to 0.001 cubic meters.
Correct Answer: A — 0.001
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Q. What is the volume of 1 M HCl solution needed to obtain 0.5 moles of HCl? (2022)
-
A.
0.5 L
-
B.
1 L
-
C.
2 L
-
D.
0.25 L
Solution
Volume = moles / molarity = 0.5 moles / 1 M = 0.5 L.
Correct Answer: A — 0.5 L
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Q. What is the volume of 1 M NaOH solution required to obtain 0.5 moles of NaOH?
-
A.
0.5 L
-
B.
1 L
-
C.
2 L
-
D.
0.25 L
Solution
Using the formula M = moles/volume, Volume = moles/M = 0.5 moles / 1 M = 0.5 L.
Correct Answer: A — 0.5 L
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Q. What is the volume of 1 mole of an ideal gas at STP (Standard Temperature and Pressure)?
-
A.
22.4 L
-
B.
24.0 L
-
C.
18.0 L
-
D.
20.0 L
Solution
At STP, 1 mole of an ideal gas occupies 22.4 liters.
Correct Answer: A — 22.4 L
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Q. What is the volume of 1 mole of an ideal gas at STP?
-
A.
22.4 L
-
B.
24 L
-
C.
10 L
-
D.
1 L
Solution
At STP (Standard Temperature and Pressure), 1 mole of an ideal gas occupies 22.4 liters.
Correct Answer: A — 22.4 L
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Q. What is the volume of 1 mole of an ideal gas at STP? (2019) 2019
-
A.
22.4 L
-
B.
24 L
-
C.
1 L
-
D.
10 L
Solution
At STP, 1 mole of an ideal gas occupies 22.4 liters.
Correct Answer: A — 22.4 L
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Q. What is the volume of 1 mole of gas at STP?
-
A.
22.4 L
-
B.
24 L
-
C.
20 L
-
D.
18 L
Solution
At STP, 1 mole of gas occupies 22.4 liters.
Correct Answer: A — 22.4 L
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Q. What is the volume of 4 moles of an ideal gas at STP?
-
A.
22.4 L
-
B.
44.8 L
-
C.
89.6 L
-
D.
112 L
Solution
Volume = moles x volume per mole = 4 moles x 22.4 L/mole = 89.6 L.
Correct Answer: C — 89.6 L
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Q. What is the volume of a 2 M NaOH solution needed to obtain 4 moles of NaOH? (2021) 2021
-
A.
2 L
-
B.
1 L
-
C.
0.5 L
-
D.
4 L
Solution
Volume (L) = moles / molarity = 4 moles / 2 M = 2 L.
Correct Answer: A — 2 L
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Q. What is the volume of a 2 M solution that contains 4 moles of solute?
-
A.
2 L
-
B.
4 L
-
C.
1 L
-
D.
0.5 L
Solution
Volume = moles of solute / molarity = 4 moles / 2 M = 2 L.
Correct Answer: B — 4 L
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Q. What is the volume of a cube with a side length of 2 meters?
-
A.
4 m³
-
B.
6 m³
-
C.
8 m³
-
D.
10 m³
Solution
Volume = side³ = 2³ = 8 m³.
Correct Answer: C — 8 m³
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Q. What is the volume of a cube with a side length of 3 cm?
-
A.
9 cm³
-
B.
18 cm³
-
C.
27 cm³
-
D.
36 cm³
Solution
The volume of a cube is given by side³, so 3 cm³ = 27 cm³.
Correct Answer: C — 27 cm³
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Q. What is the volume of a cube with a side length of 4 units?
-
A.
16 cubic units
-
B.
64 cubic units
-
C.
32 cubic units
-
D.
48 cubic units
Solution
Volume = side^3 = 4^3 = 64 cubic units.
Correct Answer: B — 64 cubic units
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Q. What is the volume of a cube with side length 3 units? (2023)
Solution
Volume = side³ = 3³ = 27 cubic units.
Correct Answer: B — 27
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Q. What is the volume of a cube with side length 4 units? (2020)
Solution
Volume = side³ = 4³ = 64 cubic units.
Correct Answer: B — 64
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Q. What is the volume of a cylinder with a radius of 3 cm and a height of 10 cm? (Use π = 3.14) (2021)
-
A.
28.26 cm³
-
B.
84.78 cm³
-
C.
94.2 cm³
-
D.
100.5 cm³
Solution
Volume = πr²h = 3.14 * (3)² * 10 = 3.14 * 9 * 10 = 282.6 cm³.
Correct Answer: B — 84.78 cm³
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Q. What is the volume of a cylinder with radius 2 and height 5? (2023)
-
A.
20π
-
B.
10π
-
C.
15π
-
D.
25π
Solution
Volume = πr²h = π(2²)(5) = 20π cubic units.
Correct Answer: A — 20π
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Q. What is the volume of a cylinder with radius 3 units and height 5 units? (2021)
-
A.
45π
-
B.
30π
-
C.
15π
-
D.
9π
Solution
Volume = πr²h = π(3²)(5) = 45π cubic units.
Correct Answer: A — 45π
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Q. What is the volume of a sphere with radius 5 units? (2021)
-
A.
500/3π
-
B.
125/3π
-
C.
100/3π
-
D.
200/3π
Solution
Volume = (4/3)πr³ = (4/3)π(5)³ = (4/3)π(125) = 500/3π cubic units.
Correct Answer: A — 500/3π
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Q. What is the volume of CO2 produced at STP when 2 moles of C2H5OH are completely combusted?
-
A.
22.4 L
-
B.
44.8 L
-
C.
67.2 L
-
D.
89.6 L
Solution
C2H5OH + 3O2 → 2CO2 + 3H2O. 2 moles of C2H5OH produce 4 moles of CO2. Volume = 4 * 22.4 L = 89.6 L.
Correct Answer: B — 44.8 L
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Q. What is the volume percent concentration of a solution containing 30 mL of ethanol in 150 mL of solution?
-
A.
20%
-
B.
25%
-
C.
30%
-
D.
15%
Solution
Volume percent = (volume of solute / total volume) x 100 = (30 mL / 150 mL) x 100 = 20%.
Correct Answer: B — 25%
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Q. What is the volume percent of ethanol in a solution made by mixing 30 mL of ethanol with 70 mL of water?
-
A.
30%
-
B.
70%
-
C.
50%
-
D.
20%
Solution
Volume percent = (volume of solute / total volume) × 100 = (30 mL / (30 mL + 70 mL)) × 100 = 30%.
Correct Answer: A — 30%
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Q. What is the wavelength of a photon with a frequency of 5 x 10^14 Hz?
-
A.
6 x 10^-7 m
-
B.
3 x 10^-7 m
-
C.
1 x 10^-6 m
-
D.
4 x 10^-7 m
Solution
Using the formula λ = c/f, where c = 3 x 10^8 m/s, λ = 3 x 10^8 / (5 x 10^14) = 6 x 10^-7 m.
Correct Answer: A — 6 x 10^-7 m
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Q. What is the wavelength of a photon with a frequency of 6 x 10^14 Hz?
-
A.
5 x 10^-7 m
-
B.
3 x 10^-7 m
-
C.
6 x 10^-7 m
-
D.
1 x 10^-6 m
Solution
Wavelength λ = c/f = (3 x 10^8 m/s) / (6 x 10^14 Hz) = 5 x 10^-7 m.
Correct Answer: A — 5 x 10^-7 m
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Q. What is the wavelength of an electron accelerated through a potential difference of 100 V? (mass of electron = 9.11 x 10^-31 kg)
-
A.
1.22 x 10^-10 m
-
B.
1.23 x 10^-9 m
-
C.
1.24 x 10^-11 m
-
D.
1.25 x 10^-12 m
Solution
The wavelength λ = h/p = h/sqrt(2meV) = (6.63 x 10^-34)/sqrt(2 * 9.11 x 10^-31 * 100) = 1.22 x 10^-10 m.
Correct Answer: A — 1.22 x 10^-10 m
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