What is the work done by an ideal gas during an isobaric expansion if the pressure is 5 atm and the volume changes from 2 L to 5 L? (2019)

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Q: What is the work done by an ideal gas during an isobaric expansion if the pressure is 5 atm and the volume changes from 2 L to 5 L? (2019)

Solution: Work done (W) = PΔV = P(V_final - V_initial) = 5 atm * (5 L - 2 L) = 15 L·atm.

Steps: 8

Step 1: Identify the pressure (P) of the gas, which is given as 5 atm.
Step 2: Identify the initial volume (V_initial), which is given as 2 L.
Step 3: Identify the final volume (V_final), which is given as 5 L.
Step 4: Calculate the change in volume (ΔV) by subtracting the initial volume from the final volume: ΔV = V_final - V_initial = 5 L - 2 L.
Step 5: Calculate ΔV, which equals 3 L.
Step 6: Use the formula for work done (W) during isobaric expansion: W = P * ΔV.
Step 7: Substitute the values into the formula: W = 5 atm * 3 L.
Step 8: Calculate the work done: W = 15 L·atm.