Q. What is the maximum displacement of a simple harmonic oscillator called? (2022)
A.
Amplitude
B.
Frequency
C.
Wavelength
D.
Period
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Solution
The maximum displacement from the mean position in simple harmonic motion is called amplitude.
Correct Answer: A — Amplitude
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Q. What is the maximum height of the projectile modeled by h(t) = -16t^2 + 32t + 48? (2023)
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Solution
The maximum height occurs at t = -b/(2a) = 1. h(1) = 64.
Correct Answer: B — 64
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Q. What is the maximum height of the projectile modeled by h(t) = -16t^2 + 64t + 48? (2021)
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Solution
The maximum height occurs at t = -b/(2a) = -64/(2*-16) = 2. h(2) = -16(2^2) + 64(2) + 48 = 80.
Correct Answer: B — 64
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Q. What is the maximum intensity ratio in interference of two waves of equal amplitude?
A.
1:1
B.
2:1
C.
4:1
D.
3:1
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Solution
Maximum intensity (I_max) = 4I_0 for two waves of equal amplitude (I_0). Thus, the ratio is 4:1.
Correct Answer: C — 4:1
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Q. What is the maximum kinetic energy of photoelectrons emitted if the incident light has a frequency of 8 x 10^14 Hz and the work function is 3 eV?
A.
1 eV
B.
3 eV
C.
5 eV
D.
7 eV
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Solution
Maximum kinetic energy (K.E.) = hf - Φ = (6.626 x 10^-34 J·s)(8 x 10^14 Hz) - 3 eV = 5 eV.
Correct Answer: C — 5 eV
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Q. What is the maximum kinetic energy of photoelectrons emitted when light of frequency 8 x 10^14 Hz is incident on a metal with work function 3 eV?
A.
1 eV
B.
3 eV
C.
5 eV
D.
7 eV
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Solution
Maximum kinetic energy (K.E.) = hν - Φ = (4.14 x 10^-15 eV·s)(8 x 10^14 Hz) - 3 eV = 5 eV.
Correct Answer: C — 5 eV
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Q. What is the maximum kinetic energy of photoelectrons if the incident light has a frequency of 8 x 10^14 Hz and the work function is 3 eV?
A.
1 eV
B.
3 eV
C.
5 eV
D.
7 eV
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Solution
Maximum kinetic energy (K.E.) = hν - Φ = (4.14 x 10^-15 eV·s)(8 x 10^14 Hz) - 3 eV = 5 eV.
Correct Answer: C — 5 eV
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Q. What is the maximum number of bright fringes observed in a double-slit experiment if the wavelength of light is 500 nm and the distance between the slits is 0.1 mm? (2020)
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Solution
The maximum number of bright fringes is given by the formula n = d/λ. Here, n = 0.1 mm / 500 nm = 200, which means 20 bright fringes can be observed on either side of the central maximum.
Correct Answer: C — 20
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Q. What is the maximum number of bright fringes that can be observed in a double-slit experiment with a given wavelength? (2023)
A.
Depends on the slit width
B.
Depends on the distance to the screen
C.
Depends on the wavelength and slit separation
D.
Always infinite
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Solution
The maximum number of bright fringes depends on the wavelength and the slit separation, as it determines how many integer multiples of the wavelength fit within the observable range.
Correct Answer: C — Depends on the wavelength and slit separation
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Q. What is the maximum number of diffraction maxima that can be observed for a double-slit experiment with a slit separation of 0.1 mm and light of wavelength 500 nm?
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Solution
The maximum number of observable maxima is given by d/λ, where d = 0.1 mm and λ = 500 nm. This gives approximately 10 maxima.
Correct Answer: B — 10
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Q. What is the maximum number of electrons in the d subshell? (2022) 2022
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Solution
The d subshell can hold a maximum of 10 electrons.
Correct Answer: C — 10
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Q. What is the maximum number of electrons in the d-subshell?
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Solution
The d-subshell can hold a maximum of 10 electrons.
Correct Answer: C — 10
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Q. What is the maximum number of electrons in the f-subshell? (2022)
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Solution
The f-subshell can hold a maximum of 14 electrons.
Correct Answer: C — 14
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Q. What is the maximum number of electrons in the n=2 shell?
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Solution
The maximum number of electrons in the n=2 shell is 2(2^2) = 8.
Correct Answer: B — 4
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Q. What is the maximum number of electrons that can be accommodated in a shell with principal quantum number n=5?
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Solution
The maximum number of electrons in a shell is given by 2n^2. For n=5, it is 2(5^2) = 50.
Correct Answer: C — 32
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Q. What is the maximum number of electrons that can be accommodated in a shell with n=3?
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Solution
The maximum number of electrons in a shell is given by 2n^2. For n=3, it is 2(3^2) = 18.
Correct Answer: B — 18
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Q. What is the maximum number of electrons that can be accommodated in a shell with quantum number n=4?
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Solution
The maximum number of electrons in a shell is given by 2n^2. For n=4, it is 2(4^2) = 32.
Correct Answer: C — 32
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Q. What is the maximum number of electrons that can be accommodated in a subshell with the quantum number l = 2?
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Solution
The maximum number of electrons in a subshell is given by the formula 2(2l + 1). For l = 2, it is 2(2*2 + 1) = 10.
Correct Answer: C — 10
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Q. What is the maximum number of electrons that can be accommodated in the d subshell? (2019)
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Solution
The d subshell can hold a maximum of 10 electrons.
Correct Answer: C — 10
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Q. What is the maximum number of electrons that can be accommodated in the n=2 shell?
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Solution
The maximum number of electrons in a shell is given by 2n^2. For n=2, this is 2(2^2) = 8.
Correct Answer: B — 4
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Q. What is the maximum number of electrons that can be accommodated in the n=5 shell?
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Solution
The maximum number of electrons in a shell is given by 2n^2. For n=5, it is 2(5^2) = 50.
Correct Answer: C — 32
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Q. What is the maximum number of electrons that can be accommodated in the p subshell? (2023)
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Solution
The p subshell can hold a maximum of 6 electrons.
Correct Answer: B — 6
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Q. What is the maximum number of electrons that can occupy a p subshell?
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Solution
A p subshell can hold a maximum of 6 electrons.
Correct Answer: B — 6
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Q. What is the maximum number of electrons that can occupy a single orbital?
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Solution
A single orbital can hold a maximum of 2 electrons, with opposite spins.
Correct Answer: B — 2
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Q. What is the maximum number of electrons that can occupy a single p subshell?
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Solution
A p subshell can hold a maximum of 6 electrons, as it has three orbitals each capable of holding 2 electrons.
Correct Answer: B — 6
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Q. What is the maximum number of electrons that can occupy a single p-orbital?
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Solution
A single p-orbital can hold a maximum of 2 electrons.
Correct Answer: A — 2
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Q. What is the maximum number of electrons that can occupy a subshell with the quantum numbers n=3 and l=2?
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Solution
The maximum number of electrons in a subshell is given by the formula 2(2l + 1). For l=2, this gives 2(2*2 + 1) = 10.
Correct Answer: C — 10
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Q. What is the maximum number of electrons that can occupy a subshell with the quantum number l = 2?
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Solution
The maximum number of electrons in a subshell is given by the formula 2(2l + 1). For l = 2, this gives 2(2*2 + 1) = 10.
Correct Answer: C — 10
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Q. What is the maximum number of electrons that can occupy the 3rd energy level?
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Solution
The maximum number of electrons in an energy level is given by the formula 2n^2. For n=3, it is 2(3^2) = 18.
Correct Answer: C — 18
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Q. What is the maximum number of electrons that can occupy the d subshell?
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Solution
The d subshell can hold a maximum of 10 electrons.
Correct Answer: C — 10
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