What is the maximum number of diffraction maxima that can be observed for a double-slit experiment with a slit separation of 0.1 mm and light of wavelength 500 nm?
Practice Questions
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Q1
What is the maximum number of diffraction maxima that can be observed for a double-slit experiment with a slit separation of 0.1 mm and light of wavelength 500 nm?
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The maximum number of observable maxima is given by d/λ, where d = 0.1 mm and λ = 500 nm. This gives approximately 10 maxima.
Questions & Step-by-step Solutions
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Q
Q: What is the maximum number of diffraction maxima that can be observed for a double-slit experiment with a slit separation of 0.1 mm and light of wavelength 500 nm?
Solution: The maximum number of observable maxima is given by d/λ, where d = 0.1 mm and λ = 500 nm. This gives approximately 10 maxima.
Steps: 6
Step 1: Identify the given values. The slit separation (d) is 0.1 mm and the wavelength of light (λ) is 500 nm.
Step 2: Convert the units to be the same. Convert 0.1 mm to nanometers: 0.1 mm = 100,000 nm.
Step 3: Use the formula for the maximum number of observable maxima, which is d/λ.
Step 4: Substitute the values into the formula: 100,000 nm / 500 nm.
Step 5: Calculate the result: 100,000 / 500 = 200.
Step 6: The maximum number of observable maxima is 200.
