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What is the maximum height of the projectile modeled by h(t) = -16t^2 + 32t + 48? (2023)

Practice Questions

1 question
Q1
What is the maximum height of the projectile modeled by h(t) = -16t^2 + 32t + 48? (2023)
  1. 48
  2. 64
  3. 80
  4. 32

Questions & Step-by-step Solutions

1 item
Q
Q: What is the maximum height of the projectile modeled by h(t) = -16t^2 + 32t + 48? (2023)
Solution: The maximum height occurs at t = -b/(2a) = 1. h(1) = 64.
Steps: 0

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