Q. What is the mass of 0.5 moles of CaCO3?
-
A.
50 g
-
B.
25 g
-
C.
100 g
-
D.
75 g
Solution
Molar mass of CaCO3 = 40 + 12 + 16*3 = 100 g/mol. Mass = moles x molar mass = 0.5 moles x 100 g/mol = 50 g.
Correct Answer: B — 25 g
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Q. What is the mass of 0.5 moles of NaCl?
-
A.
29 g
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B.
58 g
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C.
14 g
-
D.
0.5 g
Solution
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol. Mass = moles x molar mass = 0.5 moles x 58.5 g/mol = 29.25 g.
Correct Answer: A — 29 g
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Q. What is the mass of 0.5 moles of sodium chloride (NaCl)?
-
A.
29 g
-
B.
35 g
-
C.
58 g
-
D.
70 g
Solution
The molar mass of NaCl is 58 g/mol. Therefore, 0.5 moles of NaCl = 0.5 x 58 g = 29 g.
Correct Answer: C — 58 g
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Q. What is the mass of 0.75 moles of sulfuric acid (H2SO4)?
-
A.
75 g
-
B.
98 g
-
C.
147 g
-
D.
50 g
Solution
Molar mass of H2SO4 = 2*1 + 32 + 4*16 = 98 g/mol. Mass = moles x molar mass = 0.75 moles x 98 g/mol = 73.5 g.
Correct Answer: B — 98 g
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Q. What is the mass of 1 mole of water (H2O)?
-
A.
18 g
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B.
16 g
-
C.
20 g
-
D.
22 g
Solution
The molar mass of water (H2O) is 18 g/mol (2*1 for H + 16 for O).
Correct Answer: A — 18 g
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Q. What is the mass of 2 moles of carbon dioxide (CO2)?
-
A.
44 g
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B.
22 g
-
C.
88 g
-
D.
66 g
Solution
The molar mass of CO2 is 12 g/mol (C) + 16 g/mol x 2 (O) = 44 g/mol. Therefore, 2 moles of CO2 weigh 2 x 44 g = 88 g.
Correct Answer: A — 44 g
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Q. What is the mass of 2 moles of sulfuric acid (H2SO4)?
-
A.
98 g
-
B.
196 g
-
C.
294 g
-
D.
392 g
Solution
Molar mass of H2SO4 = 2*1 + 32 + 4*16 = 98 g/mol. Mass = 2 moles x 98 g/mol = 196 g.
Correct Answer: B — 196 g
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Q. What is the mass of 3 moles of carbon dioxide (CO2)?
-
A.
44 g
-
B.
66 g
-
C.
132 g
-
D.
22 g
Solution
The molar mass of CO2 is 12 g/mol (C) + 16 g/mol x 2 (O) = 44 g/mol. Therefore, 3 moles of CO2 weigh 3 x 44 g = 132 g.
Correct Answer: A — 44 g
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Q. What is the mass of 3 moles of NaCl?
-
A.
87 g
-
B.
58.5 g
-
C.
174 g
-
D.
3 g
Solution
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol. Mass = moles x molar mass = 3 moles x 58.5 g/mol = 174 g.
Correct Answer: C — 174 g
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Q. What is the mass of 3 moles of NaCl? (2020) 2020
-
A.
87 g
-
B.
58.5 g
-
C.
174 g
-
D.
3 g
Solution
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol. Mass = moles x molar mass = 3 moles x 58.5 g/mol = 174 g.
Correct Answer: C — 174 g
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Q. What is the mass of 3 moles of sodium chloride (NaCl)? (2023)
-
A.
58.5 g
-
B.
117 g
-
C.
175.5 g
-
D.
29.25 g
Solution
The molar mass of NaCl is 58.5 g/mol. Therefore, 3 moles of NaCl weigh 3 x 58.5 g = 175.5 g.
Correct Answer: B — 117 g
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Q. What is the mass of 3 moles of sulfuric acid (H2SO4)?
-
A.
98 g
-
B.
196 g
-
C.
294 g
-
D.
392 g
Solution
Molar mass of H2SO4 = 2*1 + 32 + 4*16 = 98 g/mol. Mass = 3 moles x 98 g/mol = 294 g.
Correct Answer: B — 196 g
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Q. What is the mass of KCl produced when 10 g of K reacts with excess Cl2?
-
A.
74.5 g
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B.
10 g
-
C.
20 g
-
D.
30 g
Solution
10 g of K = 0.25 moles. K + Cl2 → KCl, so 0.25 moles of KCl = 0.25 * 74.5 g = 18.625 g.
Correct Answer: A — 74.5 g
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Q. What is the mass of NaOH required to prepare 0.5 L of a 1 M solution? (2023)
-
A.
20 g
-
B.
40 g
-
C.
10 g
-
D.
30 g
Solution
Molar mass of NaOH = 40 g/mol; grams = moles × molar mass = (1 mole/L × 0.5 L) × 40 g/mol = 20 g
Correct Answer: B — 40 g
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Q. What is the mass of solute in grams in a 3 M solution of NaCl in 1 L of solution? (2023)
-
A.
58.44 g
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B.
174.32 g
-
C.
29.22 g
-
D.
87.16 g
Solution
Molar mass of NaCl = 58.44 g/mol; mass = moles × molar mass = 3 moles × 58.44 g/mol = 175.32 g
Correct Answer: B — 174.32 g
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Q. What is the mass of solute in grams required to make 1 L of a 0.1 M solution of NaCl? (Molar mass of NaCl = 58.5 g/mol) (2021)
-
A.
5.85 g
-
B.
10 g
-
C.
1 g
-
D.
2 g
Solution
Mass = moles × molar mass = (0.1 moles/L × 1 L) × 58.5 g/mol = 5.85 g.
Correct Answer: A — 5.85 g
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Q. What is the mass of solute in grams required to make 1 L of a 0.5 M NaOH solution? (2021)
-
A.
20 g
-
B.
40 g
-
C.
10 g
-
D.
30 g
Solution
Molar mass of NaOH = 40 g/mol. Mass = moles × molar mass = 0.5 moles × 40 g/mol = 20 g.
Correct Answer: B — 40 g
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Q. What is the mass of water produced when 2 moles of hydrogen react with 1 mole of oxygen?
-
A.
18 g
-
B.
36 g
-
C.
54 g
-
D.
9 g
Solution
2 moles of H2 produce 2 moles of H2O. Mass of H2O = 2 moles * 18 g/mole = 36 g.
Correct Answer: A — 18 g
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Q. What is the mass percent of a solution containing 10 g of solute in 90 g of solvent?
-
A.
10%
-
B.
90%
-
C.
50%
-
D.
20%
Solution
Mass percent = (mass of solute / total mass of solution) x 100 = (10 g / (10 g + 90 g)) x 100 = 10%
Correct Answer: A — 10%
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Q. What is the mass percent of a solution containing 20 g of NaCl in 180 g of water?
-
A.
10%
-
B.
20%
-
C.
25%
-
D.
15%
Solution
Mass percent = (mass of solute / total mass) x 100 = (20 g / (20 g + 180 g)) x 100 = 10%.
Correct Answer: A — 10%
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Q. What is the mass percent of a solution containing 20 g of solute in 180 g of solution?
-
A.
10%
-
B.
20%
-
C.
25%
-
D.
15%
Solution
Mass percent = (mass of solute / mass of solution) x 100 = (20 g / 200 g) x 100 = 10%.
Correct Answer: B — 20%
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Q. What is the mass percent of a solution containing 20 g of solute in 200 g of solution?
-
A.
10%
-
B.
20%
-
C.
5%
-
D.
15%
Solution
Mass percent = (mass of solute / mass of solution) × 100 = (20 g / 200 g) × 100 = 10%.
Correct Answer: B — 20%
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Q. What is the mass-energy equivalence formula proposed by Einstein? (2019)
-
A.
E = mc^2
-
B.
E = mv^2
-
C.
E = mgh
-
D.
E = hf
Solution
The mass-energy equivalence formula is E = mc^2, which states that energy (E) is equal to mass (m) times the speed of light (c) squared.
Correct Answer: A — E = mc^2
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Q. What is the maximum area of a triangle with a base of 10 cm and height as a function of x? (2020)
Solution
Area = 1/2 * base * height = 1/2 * 10 * x. Max area occurs when x = 10, giving Area = 50.
Correct Answer: B — 50
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Q. What is the maximum area of a triangle with a base of 10 cm and height varying with x? (2021)
Solution
Area = 1/2 * base * height. Max area occurs when height is maximized, thus Area = 1/2 * 10 * 10 = 50.
Correct Answer: B — 50
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Q. What is the maximum area of a triangle with a base of 10 m and height as a function of x? (2021)
-
A.
25 m²
-
B.
50 m²
-
C.
30 m²
-
D.
20 m²
Solution
Area = 1/2 * base * height = 1/2 * 10 * x. Max area occurs at x = 10, giving 50 m².
Correct Answer: B — 50 m²
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Q. What is the maximum area of a triangle with a base of 10 units and height as a function of x? (2020)
Solution
Area = 1/2 * base * height = 5h. Max area occurs when h = 10, giving area = 50.
Correct Answer: B — 50
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Q. What is the maximum area of a triangle with a base of 10 units and height as a function of the base? (2021)
Solution
Area = 0.5 * base * height. Max area occurs when height is 10, giving Area = 0.5 * 10 * 10 = 50.
Correct Answer: B — 50
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Q. What is the maximum displacement from the mean position in simple harmonic motion called? (2022)
-
A.
Amplitude
-
B.
Frequency
-
C.
Period
-
D.
Wavelength
Solution
The maximum displacement from the mean position in simple harmonic motion is called the amplitude.
Correct Answer: A — Amplitude
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Q. What is the maximum displacement of a mass-spring system oscillating with an amplitude of 0.3 m? (2023)
-
A.
0.1 m
-
B.
0.2 m
-
C.
0.3 m
-
D.
0.4 m
Solution
The maximum displacement in a mass-spring system is defined as the amplitude, which is given as 0.3 m.
Correct Answer: C — 0.3 m
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