Physics Syllabus (JEE Main)

Current Electricity Electrostatics Gravitation Kinematics Kinetic Theory of Gases Laws of Motion Magnetism & EMI Modern Physics Optics Oscillations & Waves Properties of Matter Rotational Motion Thermodynamics Units & Measurement Work, Energy & Power

Q. A stone is thrown downward with an initial velocity of 5 m/s from a height of 45 m. How long will it take to hit the ground? (Assume g = 10 m/s²)

A. 3 s
B. 4 s
C. 5 s
D. 6 s

Solution

Using the equation of motion: h = ut + 0.5gt². 45 = 5t + 0.5 * 10 * t². Solving the quadratic gives t = 3 s.

Correct Answer: B — 4 s

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Q. A stone is thrown horizontally from the top of a cliff 80 m high. How far from the base of the cliff will it land?

A. 20 m
B. 40 m
C. 60 m
D. 80 m

Solution

Time to fall = √(2h/g) = √(2*80/9.8) ≈ 4.04 s. Horizontal distance = horizontal speed * time. Assuming horizontal speed = 10 m/s, distance = 10 m/s * 4.04 s = 40.4 m.

Correct Answer: B — 40 m

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Q. A stone is thrown horizontally from the top of a cliff 80 m high. How far from the base of the cliff will the stone land if it is thrown with a speed of 10 m/s?

A. 20 m
B. 40 m
C. 60 m
D. 80 m

Solution

Time to fall = √(2h/g) = √(2*80/9.8) ≈ 4.04 s. Horizontal distance = speed * time = 10 m/s * 4.04 s ≈ 40 m.

Correct Answer: B — 40 m

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Q. A stone is thrown in a circular path with a radius of 3 m. If the stone completes 4 revolutions in 8 seconds, what is the angular speed?

A. π/2 rad/s
B. π rad/s
C. 2π rad/s
D. 4π rad/s

Solution

Angular speed (ω) = Total angle / Time = (4 * 2π) / 8 = π rad/s.

Correct Answer: B — π rad/s

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Q. A stone is thrown vertically upward with a speed of 20 m/s. How high will it rise before coming to rest?

A. 10 m
B. 20 m
C. 30 m
D. 40 m

Solution

Maximum height (H) = (u²)/(2g) = (20²)/(2*9.8) ≈ 20.4 m.

Correct Answer: C — 30 m

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Q. A stone is thrown vertically upward with a speed of 20 m/s. How long will it take to reach the maximum height? (g = 10 m/s²)

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Using the formula: v = u - gt. At maximum height, v = 0. So, 0 = 20 - 10t. Solving gives t = 2 s.

Correct Answer: B — 2 s

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Q. A stone is thrown vertically upward with a speed of 20 m/s. How long will it take to reach the maximum height?

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Time to reach maximum height = initial velocity / g = 20 / 10 = 2 s.

Correct Answer: B — 2 s

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Q. A stone is thrown vertically upward with a speed of 20 m/s. How long will it take to reach the maximum height? (Assume g = 10 m/s²)

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Time to reach maximum height = initial velocity / g = 20 / 10 = 2 s.

Correct Answer: B — 2 s

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Q. A stone is thrown vertically upwards with a speed of 20 m/s. How long will it take to reach the maximum height? (Assume g = 10 m/s²)

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Using the formula: time = (final velocity - initial velocity) / g. At maximum height, final velocity = 0. Time = (0 - 20) / -10 = 2 s.

Correct Answer: B — 2 s

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Q. A stone is thrown vertically upwards with a speed of 20 m/s. How long will it take to reach the maximum height? (g = 10 m/s²)

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Using the formula: v = u - gt. At maximum height, v = 0. So, 0 = 20 - 10t. Solving gives t = 2 s.

Correct Answer: B — 2 s

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Q. A stone is tied to a string and swung in a vertical circle. At the highest point, the tension in the string is 5 N and the weight of the stone is 10 N. What is the speed of the stone at the highest point if the radius of the circle is 2 m?

A. 2 m/s
B. 3 m/s
C. 4 m/s
D. 5 m/s

Solution

At the highest point, T + mg = mv²/r. 5 + 10 = (m*v²)/2. Solving gives v = 4 m/s.

Correct Answer: C — 4 m/s

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Q. A stone is tied to a string and whirled in a horizontal circle. If the radius of the circle is doubled, what happens to the centripetal force required to maintain the stone's circular motion at the same speed?

A. It doubles
B. It remains the same
C. It halves
D. It quadruples

Solution

Centripetal force (F_c) = mv²/r. If r is doubled, F_c is halved for constant speed.

Correct Answer: C — It halves

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Q. A stone is tied to a string and whirled in a horizontal circle. If the radius of the circle is doubled, what happens to the centripetal force required to maintain the circular motion at the same speed?

A. It doubles
B. It remains the same
C. It halves
D. It quadruples

Solution

Centripetal force (F_c) = mv²/r. If r is doubled, F_c is halved for constant speed.

Correct Answer: C — It halves

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Q. A stone is tied to a string and whirled in a horizontal circle. If the radius of the circle is doubled, what happens to the centripetal force required to keep the stone moving in a circle at the same speed?

A. It doubles
B. It remains the same
C. It halves
D. It quadruples

Solution

Centripetal force (F_c) = mv²/r. If r is doubled, F_c is halved for the same speed.

Correct Answer: C — It halves

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Q. A stone is tied to a string and whirled in a vertical circle of radius 1 m. What is the minimum speed at the top of the circle to keep the stone in circular motion?

A. 1 m/s
B. 2 m/s
C. 3 m/s
D. 4 m/s

Solution

At the top, centripetal force = weight. mv²/r = mg. v² = rg. v = √(1*9.8) ≈ 3.13 m/s.

Correct Answer: B — 2 m/s

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Q. A student calculates the density of a substance as 8.0 g/cm³ with an uncertainty of ±0.1 g/cm³. What is the density range?

A. 7.9 g/cm³ to 8.1 g/cm³
B. 8.0 g/cm³ to 8.2 g/cm³
C. 8.0 g/cm³ to 8.1 g/cm³
D. 7.5 g/cm³ to 8.5 g/cm³

Solution

Density range = 8.0 ± 0.1 = 7.9 g/cm³ to 8.1 g/cm³.

Correct Answer: A — 7.9 g/cm³ to 8.1 g/cm³

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Q. A student measures a length as 30.2 m, but the actual length is 30 m. What is the error in measurement?

A. 0.2 m
B. 0.1 m
C. 0.3 m
D. 0.5 m

Solution

Error = Measured value - True value = 30.2 m - 30 m = 0.2 m.

Correct Answer: A — 0.2 m

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Q. A student measures the length of a rod as 15.3 cm. If the true length is 15 cm, what is the error in measurement?

A. 0.3 cm
B. 0.2 cm
C. 0.1 cm
D. 0.5 cm

Solution

Error in measurement = Measured value - True value = 15.3 - 15 = 0.3 cm.

Correct Answer: A — 0.3 cm

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Q. A student measures the length of a rod as 150 cm with a possible error of 2 cm. What is the range of the true length?

A. 148 cm to 152 cm
B. 149 cm to 151 cm
C. 150 cm to 152 cm
D. 150 cm to 154 cm

Solution

True length can vary from 150 - 2 to 150 + 2, which is 148 cm to 152 cm.

Correct Answer: A — 148 cm to 152 cm

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Q. A student measures the length of a rod multiple times and records the values: 10.1 cm, 10.2 cm, 10.0 cm, 10.3 cm. What is the average length of the rod?

A. 10.0 cm
B. 10.1 cm
C. 10.2 cm
D. 10.3 cm

Solution

Average length = (10.1 + 10.2 + 10.0 + 10.3) / 4 = 10.15 cm.

Correct Answer: B — 10.1 cm

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Q. A student measures the length of a rod multiple times and records values of 10.1 cm, 10.2 cm, and 10.0 cm. What is the average length of the rod?

A. 10.0 cm
B. 10.1 cm
C. 10.2 cm
D. 10.3 cm

Solution

Average length = (10.1 + 10.2 + 10.0) / 3 = 10.1 cm.

Correct Answer: B — 10.1 cm

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Q. A student measures the mass of an object as 200 g with an uncertainty of ±2 g. What is the relative uncertainty?

A. 1%
B. 0.5%
C. 2%
D. 0.1%

Solution

Relative uncertainty = (Uncertainty / Measured value) * 100 = (2 / 200) * 100 = 1%.

Correct Answer: B — 0.5%

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Q. A student measures the speed of a car as 60 km/h with an uncertainty of ±2 km/h. What is the percentage uncertainty?

A. 3.33%
B. 2.5%
C. 4.0%
D. 5.0%

Solution

Percentage uncertainty = (Uncertainty / Measured value) * 100 = (2 / 60) * 100 = 3.33%.

Correct Answer: A — 3.33%

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Q. A student measures the speed of a car as 60 km/h with an uncertainty of ±2 km/h. What is the percentage error in the speed measurement?

A. 3.33%
B. 2.0%
C. 1.5%
D. 4.0%

Solution

Percentage error = (Uncertainty / Measured value) * 100 = (2 / 60) * 100 = 3.33%.

Correct Answer: A — 3.33%

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Q. A student measures the speed of a car as 60.0 km/h with an uncertainty of ±2.0 km/h. What is the percentage uncertainty in the speed measurement?

A. 3.33%
B. 2.0%
C. 1.67%
D. 5.0%

Solution

Percentage uncertainty = (absolute uncertainty / measured value) * 100 = (2.0 / 60.0) * 100 = 3.33%.

Correct Answer: A — 3.33%

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Q. A student measures the temperature of water as 25°C with an uncertainty of ±0.5°C. What is the minimum temperature?

A. 24.5°C
B. 25.0°C
C. 25.5°C
D. 26.0°C

Solution

Minimum temperature = Measured value - Uncertainty = 25.0 - 0.5 = 24.5°C.

Correct Answer: A — 24.5°C

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Q. A student measures the time period of a pendulum as 2.0 s with an uncertainty of ±0.1 s. What is the fractional error in the time period?

A. 0.05
B. 0.1
C. 0.02
D. 0.1

Solution

Fractional error = (absolute error / measured value) = 0.1 / 2.0 = 0.05.

Correct Answer: A — 0.05

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Q. A student measures the time period of a pendulum as 2.0 s with an uncertainty of ±0.1 s. What is the percentage uncertainty in the time period?

A. 5%
B. 10%
C. 2.5%
D. 1%

Solution

Percentage uncertainty = (Uncertainty / Measured value) * 100 = (0.1 / 2.0) * 100 = 5%.

Correct Answer: C — 2.5%

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Q. A student measures the time period of a pendulum as 2.0 s with an uncertainty of ±0.1 s. What is the absolute error in the time period?

A. 0.1 s
B. 0.05 s
C. 0.2 s
D. 0.01 s

Solution

The absolute error is given directly as ±0.1 s.

Correct Answer: A — 0.1 s

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Q. A student measures the width of a table as 1.2 m with a possible error of 0.02 m. What is the range of the true width?

A. 1.18 m to 1.22 m
B. 1.20 m to 1.22 m
C. 1.20 m to 1.24 m
D. 1.18 m to 1.20 m

Solution

True width = Measured value ± Absolute error = 1.2 ± 0.02 gives the range 1.18 m to 1.22 m.

Correct Answer: A — 1.18 m to 1.22 m

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Physics Syllabus (JEE Main)

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