A stone is thrown vertically upwards with a speed of 20 m/s. How long will it take to reach the maximum height? (Assume g = 10 m/s²)

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Q: A stone is thrown vertically upwards with a speed of 20 m/s. How long will it take to reach the maximum height? (Assume g = 10 m/s²)

Solution: Using the formula: time = (final velocity - initial velocity) / g. At maximum height, final velocity = 0. Time = (0 - 20) / -10 = 2 s.

Steps: 8

Step 1: Understand that when the stone is thrown upwards, it will eventually stop rising at its maximum height.
Step 2: At maximum height, the final velocity of the stone is 0 m/s because it stops moving up before it starts to fall down.
Step 3: Identify the initial velocity of the stone, which is given as 20 m/s (the speed it was thrown upwards).
Step 4: Use the formula for time taken to reach maximum height: time = (final velocity - initial velocity) / acceleration due to gravity (g).
Step 5: Substitute the values into the formula: final velocity = 0 m/s, initial velocity = 20 m/s, and g = 10 m/s².
Step 6: Calculate the time: time = (0 - 20) / -10.
Step 7: Simplify the calculation: time = -20 / -10 = 2 seconds.
Step 8: Conclude that it takes 2 seconds for the stone to reach its maximum height.