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A student measures a length as 30.2 m, but the actual length is 30 m. What is th
A student measures a length as 30.2 m, but the actual length is 30 m. What is the error in measurement?
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A student measures a length as 30.2 m, but the actual length is 30 m. What is the error in measurement?
0.2 m
0.1 m
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Error = Measured value - True value = 30.2 m - 30 m = 0.2 m.
Questions & Step-by-step Solutions
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Q
Q: A student measures a length as 30.2 m, but the actual length is 30 m. What is the error in measurement?
Solution:
Error = Measured value - True value = 30.2 m - 30 m = 0.2 m.
Steps: 5
Show Steps
Step 1: Identify the measured value. In this case, it is 30.2 m.
Step 2: Identify the true value. Here, it is 30 m.
Step 3: Use the formula for error in measurement: Error = Measured value - True value.
Step 4: Substitute the values into the formula: Error = 30.2 m - 30 m.
Step 5: Calculate the error: 30.2 m - 30 m = 0.2 m.
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