A stone is thrown horizontally from the top of a cliff 80 m high. How far from the base of the cliff will it land?
Practice Questions
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Q1
A stone is thrown horizontally from the top of a cliff 80 m high. How far from the base of the cliff will it land?
20 m
40 m
60 m
80 m
Time to fall = √(2h/g) = √(2*80/9.8) ≈ 4.04 s. Horizontal distance = horizontal speed * time. Assuming horizontal speed = 10 m/s, distance = 10 m/s * 4.04 s = 40.4 m.
Questions & Step-by-step Solutions
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Q
Q: A stone is thrown horizontally from the top of a cliff 80 m high. How far from the base of the cliff will it land?
Solution: Time to fall = √(2h/g) = √(2*80/9.8) ≈ 4.04 s. Horizontal distance = horizontal speed * time. Assuming horizontal speed = 10 m/s, distance = 10 m/s * 4.04 s = 40.4 m.
Steps: 10
Step 1: Identify the height of the cliff, which is 80 meters.
Step 2: Use the formula to calculate the time it takes for the stone to fall: Time = √(2h/g), where h is the height (80 m) and g is the acceleration due to gravity (approximately 9.8 m/s²).
Step 3: Plug in the values: Time = √(2 * 80 / 9.8).
Step 4: Calculate the value inside the square root: 2 * 80 = 160, then 160 / 9.8 ≈ 16.33.
Step 5: Take the square root of 16.33 to find the time: Time ≈ √16.33 ≈ 4.04 seconds.
Step 6: Determine the horizontal speed of the stone. In this case, it is assumed to be 10 m/s.
Step 7: Use the formula for horizontal distance: Distance = horizontal speed * time.
Step 8: Plug in the values: Distance = 10 m/s * 4.04 s.
