Increasing the stopping potential increases the maximum kinetic energy of the emitted electrons, as the stopping potential is directly related to the kinetic energy of the electrons.

Relative uncertainty = (absolute uncertainty / measured value) = 1 / 50 = 0.02.

Kinetic energy = 0.5 * m * v²; maximum error = m * v * uncertainty in v = m * 20.0 * 0.4 = 8 J (assuming m = 1 kg).

In a plane mirror, the image is formed at the same distance behind the mirror as the object is in front, so the image is at 10 cm.

The potential gradient is V/L = 1.5V/0.5m = 3 V/m, but since the total length is 1m, the gradient is 1.5 V/m.

The potential gradient is defined as the potential difference per unit length. If the length is doubled while keeping the potential difference constant, the potential gradient halves.

Doubling the length of the wire doubles the potential difference across it, as the potential gradient remains constant.

The potential gradient is defined as the potential difference per unit length. If the length is doubled with the same potential difference, the gradient halves.

The emf can be calculated using the formula: emf = potential gradient × length. Here, emf = 2 V/m × 4 m = 8 V.

Using the potential gradient, the voltage across 2 m is (12 V / 4 m) * 2 m = 6 V.

Using the potential gradient, EMF = (Length of wire at balance point / Total length) * Total voltage = (4 m / 10 m) * 12 V = 4.8 V.

The EMF of the cell is equal to the potential gradient multiplied by the length to the balance point. Here, it is 2 V.

The potential gradient is 6 V / 4 m = 1.5 V/m. Therefore, across 2 m, the voltage is 1.5 V/m * 2 m = 3 V.

Using the potential gradient, the EMF of the cell can be calculated as (6 V / 10 m) * 4 m = 2.4 V.

Using the potential gradient, we can find the voltage across the cell. The potential gradient is 6 V / 10 m = 0.6 V/m. At 4 m, the voltage is 0.6 V/m * 4 m = 2.4 V, which rounds to 2 V.

Using the formula V1/L1 = V2/L2, we have 12 V / 4 m = V2 / 6 m. Solving gives V2 = 18 V.

A shift in the balance point indicates that the load connected affects the total resistance in the circuit, altering the potential difference across the potentiometer wire.

EMF = Potential Gradient × Balancing Length = 3 V/m × 4 m = 12 V.

The potential gradient is V/L = 1.5V/0.5m = 3 V/m.

Increasing the known voltage will cause the balance point to move towards the positive terminal, as a higher voltage requires a longer length of wire to achieve balance.

Increasing the known voltage will cause the balance point to move towards the positive terminal, as a higher voltage requires a longer length of wire to balance.

If the known voltage is increased, the balance length will also increase, as a higher voltage will require a longer length of wire to achieve balance.

The potential gradient is inversely proportional to the length of the wire; doubling the length halves the potential gradient.

The potential gradient is V/L = 1.5V/0.75m = 2 V/m.

If the wire is made of a material with higher resistivity, the potential gradient will decrease because the resistance increases, leading to a lower current for the same voltage.

Higher resistivity increases the resistance of the wire, which can decrease the potential gradient for a given voltage.

The potential difference per cm is calculated as 12V / 50 cm = 0.24 V/cm.

The potential gradient is V/L = 6V/0.3m = 20 V/m, but since the total length is 1.2m, the gradient is 5 V/m.

If the known voltage is increased, the balance point will move towards the positive terminal, as a higher voltage will require a longer length of wire to achieve balance.

If the known voltage is increased, a longer length of wire will be required to balance the unknown voltage, as the potential gradient remains constant.