In a potentiometer experiment, if the balance point is found at 4 m with a 12 V battery, what is the EMF of the cell being measured?

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Q: In a potentiometer experiment, if the balance point is found at 4 m with a 12 V battery, what is the EMF of the cell being measured?

Solution: Using the potential gradient, EMF = (Length of wire at balance point / Total length) * Total voltage = (4 m / 10 m) * 12 V = 4.8 V.

Steps: 9

Step 1: Understand that a potentiometer is used to measure the EMF (Electromotive Force) of a cell.
Step 2: Identify the balance point, which is given as 4 meters.
Step 3: Note the total length of the wire used in the potentiometer, which is 10 meters.
Step 4: Recognize that the total voltage from the battery is 12 volts.
Step 5: Use the formula for EMF: EMF = (Length of wire at balance point / Total length) * Total voltage.
Step 6: Plug in the values: EMF = (4 m / 10 m) * 12 V.
Step 7: Calculate the fraction: 4 m / 10 m = 0.4.
Step 8: Multiply this fraction by the total voltage: 0.4 * 12 V = 4.8 V.
Step 9: Conclude that the EMF of the cell being measured is 4.8 V.