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In a potentiometer experiment, if the balance point is found at 4 m with a 6 V b
In a potentiometer experiment, if the balance point is found at 4 m with a 6 V battery, what is the voltage across a 2 m length of the wire?
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Q1
In a potentiometer experiment, if the balance point is found at 4 m with a 6 V battery, what is the voltage across a 2 m length of the wire?
2 V
3 V
4 V
1 V
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The potential gradient is 6 V / 4 m = 1.5 V/m. Therefore, across 2 m, the voltage is 1.5 V/m * 2 m = 3 V.
Questions & Step-by-step Solutions
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Q
Q: In a potentiometer experiment, if the balance point is found at 4 m with a 6 V battery, what is the voltage across a 2 m length of the wire?
Solution:
The potential gradient is 6 V / 4 m = 1.5 V/m. Therefore, across 2 m, the voltage is 1.5 V/m * 2 m = 3 V.
Steps: 5
Show Steps
Step 1: Identify the total voltage provided by the battery, which is 6 V.
Step 2: Identify the length of the wire where the balance point is found, which is 4 m.
Step 3: Calculate the potential gradient (voltage per meter) by dividing the total voltage by the length of the wire: 6 V / 4 m = 1.5 V/m.
Step 4: Determine the length of the wire segment for which you want to find the voltage, which is 2 m.
Step 5: Calculate the voltage across the 2 m length by multiplying the potential gradient by the length: 1.5 V/m * 2 m = 3 V.
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