In a potentiometer circuit, if the balancing length is 50 cm for a cell of emf 1.5V, what is the potential gradient if the total length of the wire is 100 cm?
Practice Questions
1 question
Q1
In a potentiometer circuit, if the balancing length is 50 cm for a cell of emf 1.5V, what is the potential gradient if the total length of the wire is 100 cm?
3 V/m
1.5 V/m
0.75 V/m
2 V/m
The potential gradient is V/L = 1.5V/0.5m = 3 V/m, but since the total length is 1m, the gradient is 1.5 V/m.
Questions & Step-by-step Solutions
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Q
Q: In a potentiometer circuit, if the balancing length is 50 cm for a cell of emf 1.5V, what is the potential gradient if the total length of the wire is 100 cm?
Solution: The potential gradient is V/L = 1.5V/0.5m = 3 V/m, but since the total length is 1m, the gradient is 1.5 V/m.
Steps: 6
Step 1: Understand that the balancing length of 50 cm means that the potential difference across this length is equal to the emf of the cell, which is 1.5V.
Step 2: Convert the balancing length from cm to meters. 50 cm is equal to 0.5 m.
Step 3: Calculate the potential gradient using the formula: Potential Gradient = Voltage / Length. Here, Voltage = 1.5V and Length = 0.5m.
Step 4: Substitute the values into the formula: Potential Gradient = 1.5V / 0.5m = 3 V/m.
Step 5: Note that the total length of the wire is 1m. Since the potential gradient is uniform, we need to find the potential gradient for the entire length of the wire.
Step 6: Since the total length is 1m, the potential gradient remains the same, but we express it as the total voltage over the total length: 1.5V / 1m = 1.5 V/m.
