In a potentiometer experiment, if the balancing length is found to be 4m for a cell of unknown EMF, what is the EMF if the potential gradient is 3 V/m?
Practice Questions
1 question
Q1
In a potentiometer experiment, if the balancing length is found to be 4m for a cell of unknown EMF, what is the EMF if the potential gradient is 3 V/m?
6 V
8 V
12 V
15 V
EMF = Potential Gradient × Balancing Length = 3 V/m × 4 m = 12 V.
Questions & Step-by-step Solutions
1 item
Q
Q: In a potentiometer experiment, if the balancing length is found to be 4m for a cell of unknown EMF, what is the EMF if the potential gradient is 3 V/m?
Solution: EMF = Potential Gradient × Balancing Length = 3 V/m × 4 m = 12 V.
Steps: 5
Step 1: Understand that the EMF (Electromotive Force) of a cell can be calculated using the formula: EMF = Potential Gradient × Balancing Length.
Step 2: Identify the values given in the problem. The potential gradient is 3 V/m and the balancing length is 4 m.
Step 3: Substitute the values into the formula: EMF = 3 V/m × 4 m.
Step 4: Perform the multiplication: 3 V/m × 4 m = 12 V.
Step 5: Conclude that the EMF of the cell is 12 V.
