Q. What is the bandwidth of a signal that has a frequency range from 300 Hz to 3 kHz?
A.
2.7 kHz
B.
3.3 kHz
C.
2.4 kHz
D.
3.0 kHz
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Solution
Bandwidth = f_max - f_min = 3000 Hz - 300 Hz = 2700 Hz or 2.7 kHz.
Correct Answer: A — 2.7 kHz
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Q. What is the bandwidth of a signal that occupies a frequency range from 1 kHz to 3 kHz?
A.
1 kHz
B.
2 kHz
C.
3 kHz
D.
4 kHz
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Solution
Bandwidth = f_max - f_min = 3 kHz - 1 kHz = 2 kHz.
Correct Answer: B — 2 kHz
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Q. What is the bandwidth of a signal that occupies a frequency range from 300 Hz to 3 kHz?
A.
2.7 kHz
B.
3.3 kHz
C.
2.4 kHz
D.
3.0 kHz
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Solution
Bandwidth = f_max - f_min = 3000 Hz - 300 Hz = 2700 Hz = 2.7 kHz.
Correct Answer: A — 2.7 kHz
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Q. What is the binding energy of a nucleus?
A.
Energy required to remove a nucleon
B.
Energy released during nuclear fusion
C.
Energy required to split the nucleus
D.
Energy required to form the nucleus from its constituents
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Solution
The binding energy of a nucleus is the energy required to form the nucleus from its constituent protons and neutrons.
Correct Answer: D — Energy required to form the nucleus from its constituents
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Q. What is the binding energy per nucleon for a stable nucleus?
A.
Less than 1 MeV
B.
About 8 MeV
C.
More than 10 MeV
D.
Zero
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Solution
Stable nuclei typically have a binding energy per nucleon around 8 MeV.
Correct Answer: B — About 8 MeV
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Q. What is the Brewster's angle for a medium with a refractive index of 1.5?
A.
30 degrees
B.
45 degrees
C.
60 degrees
D.
53 degrees
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Solution
Brewster's angle can be calculated using the formula tan(θ_B) = n, where n is the refractive index. For n = 1.5, θ_B = arctan(1.5) ≈ 53 degrees.
Correct Answer: D — 53 degrees
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Q. What is the Brewster's angle for light entering a medium with a refractive index of 1.5?
A.
30 degrees
B.
45 degrees
C.
60 degrees
D.
53 degrees
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Solution
Brewster's angle can be calculated using the formula tan(θ_B) = n, where n is the refractive index. For n = 1.5, θ_B = arctan(1.5) ≈ 53 degrees.
Correct Answer: D — 53 degrees
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Q. What is the Brewster's angle for light in air (n=1) reflecting off glass (n=1.5)?
A.
30 degrees
B.
45 degrees
C.
60 degrees
D.
53 degrees
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Solution
Brewster's angle can be calculated using the formula tan(θ_B) = n2/n1, which gives approximately 53 degrees.
Correct Answer: D — 53 degrees
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Q. What is the Brewster's angle for light traveling from air (n1 = 1) to glass (n2 = 1.5)?
A.
30 degrees
B.
45 degrees
C.
60 degrees
D.
53 degrees
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Solution
Brewster's angle θ_B can be calculated using θ_B = arctan(n2/n1) = arctan(1.5) ≈ 56.31 degrees.
Correct Answer: D — 53 degrees
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Q. What is the Brewster's angle?
A.
The angle at which light is completely absorbed
B.
The angle at which light is reflected with maximum polarization
C.
The angle at which light refracts without any reflection
D.
The angle at which light intensity is halved
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Solution
Brewster's angle is the angle of incidence at which light is reflected with maximum polarization.
Correct Answer: B — The angle at which light is reflected with maximum polarization
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Q. What is the bulk modulus of a material?
A.
Resistance to shear deformation
B.
Resistance to volume change
C.
Resistance to bending
D.
Resistance to tensile stress
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Solution
The bulk modulus measures a material's resistance to uniform compression, indicating how much it resists volume change.
Correct Answer: B — Resistance to volume change
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Q. What is the capacitance of a parallel plate capacitor with an area of 0.01 m² and a separation of 0.001 m, filled with a dielectric of relative permittivity 5?
A.
5.5 × 10^-11 F
B.
5.5 × 10^-10 F
C.
5.5 × 10^-9 F
D.
5.5 × 10^-8 F
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Solution
C = ε₀ * ε_r * A / d = (8.85 × 10^-12 F/m) * 5 * (0.01 m²) / (0.001 m) = 4.425 × 10^-10 F.
Correct Answer: B — 5.5 × 10^-10 F
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Q. What is the capacitance of a parallel plate capacitor with area 0.1 m² and separation 0.01 m filled with air (ε₀ = 8.85 × 10^-12 F/m)?
A.
8.85 × 10^-12 F
B.
8.85 × 10^-10 F
C.
8.85 × 10^-9 F
D.
8.85 × 10^-8 F
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Solution
Capacitance C = ε₀ * A / d = (8.85 × 10^-12 F/m) * (0.1 m²) / (0.01 m) = 8.85 × 10^-10 F.
Correct Answer: B — 8.85 × 10^-10 F
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Q. What is the capacitance of a parallel plate capacitor with area A and separation d?
A.
ε₀ * A / d
B.
A / (ε₀ * d)
C.
d / (ε₀ * A)
D.
ε₀ * d / A
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Solution
The capacitance C of a parallel plate capacitor is given by the formula C = ε₀ * A / d, where ε₀ is the permittivity of free space.
Correct Answer: A — ε₀ * A / d
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Q. What is the capacitance of a parallel plate capacitor with plate area A and separation d?
A.
ε₀A/d
B.
d/ε₀A
C.
A/ε₀d
D.
ε₀d/A
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Solution
The capacitance C of a parallel plate capacitor is given by the formula C = ε₀A/d, where ε₀ is the permittivity of free space.
Correct Answer: A — ε₀A/d
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Q. What is the change in internal energy (ΔU) for an ideal gas in an isochoric process?
A.
ΔU = Q
B.
ΔU = W
C.
ΔU = 0
D.
ΔU = Q - W
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Solution
In an isochoric process, the change in internal energy is equal to the heat added to the system, ΔU = Q.
Correct Answer: A — ΔU = Q
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Q. What is the change in internal energy for an ideal gas during an isochoric process?
A.
Zero
B.
nRΔT
C.
Q
D.
W
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Solution
In an isochoric process, the change in internal energy is equal to the heat added to the system, ΔU = Q.
Correct Answer: C — Q
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Q. What is the change in internal energy for an ideal gas undergoing an isochoric process?
A.
Zero
B.
Equal to the heat added
C.
Equal to the work done
D.
Equal to the change in temperature
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Solution
In an isochoric process, the volume remains constant, and the change in internal energy is equal to the heat added to the system.
Correct Answer: B — Equal to the heat added
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Q. What is the change in internal energy of an ideal gas during an isochoric process?
A.
Increases
B.
Decreases
C.
Remains constant
D.
Depends on the amount of gas
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Solution
In an isochoric process, the volume remains constant, and any heat added to the system increases the internal energy of the gas.
Correct Answer: A — Increases
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Q. What is the coefficient of static friction if a block on a horizontal surface begins to slide at a force of 20 N and the normal force is 50 N?
A.
0.2
B.
0.4
C.
0.5
D.
0.6
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Solution
The coefficient of static friction (μs) is given by μs = F/N, where F is the force and N is the normal force. Here, μs = 20 N / 50 N = 0.4.
Correct Answer: B — 0.4
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Q. What is the combined gas law equation?
A.
PV = nRT
B.
P1V1/T1 = P2V2/T2
C.
P1V1 = P2V2
D.
V1/T1 = V2/T2
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Solution
The combined gas law is represented by the equation P1V1/T1 = P2V2/T2, which combines Boyle's, Charles's, and Gay-Lussac's laws.
Correct Answer: B — P1V1/T1 = P2V2/T2
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Q. What is the condition for a system to be critically damped?
A.
Damping coefficient equals zero
B.
Damping coefficient is less than the natural frequency
C.
Damping coefficient equals the square root of the product of mass and spring constant
D.
Damping coefficient is greater than the natural frequency
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Solution
A system is critically damped when the damping coefficient equals the square root of the product of mass and spring constant.
Correct Answer: C — Damping coefficient equals the square root of the product of mass and spring constant
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Q. What is the condition for a Wheatstone bridge to be balanced?
A.
R1/R2 = R3/R4
B.
R1 + R2 = R3 + R4
C.
R1 - R2 = R3 - R4
D.
R1 * R2 = R3 * R4
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Solution
The condition for a Wheatstone bridge to be balanced is R1/R2 = R3/R4.
Correct Answer: A — R1/R2 = R3/R4
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Q. What is the condition for a Wheatstone bridge to be in a balanced state?
A.
R1/R2 = R3/R4
B.
R1 + R2 = R3 + R4
C.
R1 - R2 = R3 - R4
D.
R1 * R4 = R2 * R3
Show solution
Solution
The condition for balance is R1/R2 = R3/R4.
Correct Answer: A — R1/R2 = R3/R4
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Q. What is the condition for a Wheatstone bridge to be in equilibrium?
A.
R1/R2 = R3/R4
B.
R1 + R2 = R3 + R4
C.
R1 - R2 = R3 - R4
D.
R1 * R3 = R2 * R4
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Solution
In a Wheatstone bridge, the bridge is in equilibrium when the ratio of the resistances in one branch is equal to the ratio in the other branch, i.e., R1/R2 = R3/R4.
Correct Answer: A — R1/R2 = R3/R4
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Q. What is the condition for an object to be in rotational equilibrium?
A.
Net force is zero
B.
Net torque is zero
C.
Both net force and net torque are zero
D.
None of the above
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Solution
For rotational equilibrium, the net torque acting on the object must be zero.
Correct Answer: B — Net torque is zero
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Q. What is the condition for constructive interference in a double-slit experiment?
A.
Path difference is an odd multiple of lambda/2
B.
Path difference is an even multiple of lambda
C.
Path difference is an odd multiple of lambda
D.
Path difference is zero
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Solution
Constructive interference occurs when the path difference between the two waves is an even multiple of the wavelength (nλ, where n is an integer).
Correct Answer: B — Path difference is an even multiple of lambda
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Q. What is the condition for constructive interference in a thin film?
A.
2t = (m + 1/2)λ
B.
2t = mλ
C.
t = mλ/2
D.
t = (m + 1/2)λ/2
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Solution
For constructive interference, the condition is 2t = mλ, where t is the thickness of the film and m is an integer.
Correct Answer: B — 2t = mλ
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Q. What is the condition for constructive interference in two waves?
A.
Path difference = (n + 1/2)λ
B.
Path difference = nλ
C.
Path difference = (n - 1/2)λ
D.
Path difference = 0
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Solution
Constructive interference occurs when the path difference is nλ, where n is an integer.
Correct Answer: B — Path difference = nλ
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Q. What is the condition for critical damping in a damped harmonic oscillator?
A.
Damping coefficient equals zero
B.
Damping coefficient equals mass times natural frequency
C.
Damping coefficient equals twice the mass times natural frequency
D.
Damping coefficient is less than mass times natural frequency
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Solution
Critical damping occurs when the damping coefficient equals twice the mass times the natural frequency of the system.
Correct Answer: C — Damping coefficient equals twice the mass times natural frequency
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