What is the capacitance of a parallel plate capacitor with an area of 0.01 m² and a separation of 0.001 m, filled with a dielectric of relative permittivity 5?
Practice Questions
1 question
Q1
What is the capacitance of a parallel plate capacitor with an area of 0.01 m² and a separation of 0.001 m, filled with a dielectric of relative permittivity 5?
5.5 × 10^-11 F
5.5 × 10^-10 F
5.5 × 10^-9 F
5.5 × 10^-8 F
C = ε₀ * ε_r * A / d = (8.85 × 10^-12 F/m) * 5 * (0.01 m²) / (0.001 m) = 4.425 × 10^-10 F.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the capacitance of a parallel plate capacitor with an area of 0.01 m² and a separation of 0.001 m, filled with a dielectric of relative permittivity 5?
Solution: C = ε₀ * ε_r * A / d = (8.85 × 10^-12 F/m) * 5 * (0.01 m²) / (0.001 m) = 4.425 × 10^-10 F.
Steps: 6
Step 1: Identify the formula for the capacitance (C) of a parallel plate capacitor: C = ε₀ * ε_r * A / d.
Step 2: Determine the values needed for the formula: ε₀ (the permittivity of free space) is approximately 8.85 × 10^-12 F/m, ε_r (the relative permittivity of the dielectric) is 5, A (the area of the plates) is 0.01 m², and d (the separation between the plates) is 0.001 m.
Step 3: Substitute the values into the formula: C = (8.85 × 10^-12 F/m) * 5 * (0.01 m²) / (0.001 m).
