Physics Syllabus (JEE Main)
Q. What happens to the gravitational potential energy of a satellite as it moves further away from the Earth?
A.
It increases
B.
It decreases
C.
It remains constant
D.
It becomes zero
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Solution
As a satellite moves further away from the Earth, its gravitational potential energy increases because it is moving to a higher potential.
Correct Answer: A — It increases
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Q. What happens to the gravitational potential energy of a satellite as it moves to a higher orbit?
A.
It increases
B.
It decreases
C.
It remains constant
D.
It becomes zero
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Solution
As a satellite moves to a higher orbit, its gravitational potential energy increases due to the increase in distance from the Earth.
Correct Answer: A — It increases
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Q. What happens to the gravitational potential energy of an object as it moves away from the Earth?
A.
It increases.
B.
It decreases.
C.
It remains constant.
D.
It becomes zero.
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Solution
As an object moves away from the Earth, its gravitational potential energy increases.
Correct Answer: A — It increases.
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Q. What happens to the gravitational potential energy of an object as it moves away from a planet?
A.
It increases.
B.
It decreases.
C.
It remains constant.
D.
It becomes zero.
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Solution
As an object moves away from a planet, its gravitational potential energy increases (becomes less negative).
Correct Answer: A — It increases.
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Q. What happens to the image distance when the object is moved closer to a convex lens beyond its focal point?
A.
Increases
B.
Decreases
C.
Remains the same
D.
Becomes negative
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Solution
As the object moves closer, the image distance increases.
Correct Answer: A — Increases
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Q. What happens to the image formed by a concave lens when the object is placed at infinity?
A.
Real and inverted
B.
Virtual and upright
C.
Real and upright
D.
No image formed
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Solution
When an object is placed at infinity, a concave lens forms a virtual image at its focal point, which is upright.
Correct Answer: B — Virtual and upright
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Q. What happens to the image formed by a concave mirror when the object is placed at the center of curvature?
A.
The image is virtual and upright.
B.
The image is real and inverted.
C.
The image is real and upright.
D.
The image is virtual and inverted.
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Solution
When the object is at the center of curvature, the image formed is real, inverted, and of the same size.
Correct Answer: B — The image is real and inverted.
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Q. What happens to the image formed by a concave mirror when the object is placed between the focal point and the mirror?
A.
The image is real and inverted.
B.
The image is virtual and upright.
C.
The image is real and upright.
D.
No image is formed.
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Solution
When the object is placed between the focal point and the mirror, the image formed is virtual and upright.
Correct Answer: B — The image is virtual and upright.
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Q. What happens to the image formed by a convex lens when the object is moved closer to the lens than its focal length?
A.
Image disappears
B.
Image becomes real
C.
Image becomes virtual
D.
Image becomes inverted
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Solution
When the object is within the focal length of a convex lens, the image formed is virtual and upright.
Correct Answer: C — Image becomes virtual
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Q. What happens to the image when the object is moved closer to a convex lens than its focal length?
A.
Image disappears
B.
Image becomes real
C.
Image becomes virtual
D.
Image becomes inverted
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Solution
When the object is within the focal length of a convex lens, the image formed is virtual.
Correct Answer: C — Image becomes virtual
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Q. What happens to the induced current in a closed loop if the magnetic field through the loop is increasing?
A.
The induced current flows in a direction to oppose the increase
B.
The induced current flows in the same direction as the increase
C.
The induced current becomes zero
D.
The induced current fluctuates
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Solution
According to Lenz's law, the induced current will flow in a direction that opposes the increase in magnetic flux.
Correct Answer: A — The induced current flows in a direction to oppose the increase
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Q. What happens to the induced current in a coil if the magnetic field is suddenly removed?
A.
Induced current continues to flow
B.
Induced current stops immediately
C.
Induced current increases
D.
Induced current decreases gradually
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Solution
If the magnetic field is suddenly removed, the change in magnetic flux becomes zero, and thus the induced current stops immediately.
Correct Answer: B — Induced current stops immediately
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Q. What happens to the induced current when the magnetic field is removed from a closed loop?
A.
It continues to flow indefinitely
B.
It stops immediately
C.
It flows in the opposite direction
D.
It decreases gradually
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Solution
When the magnetic field is removed from a closed loop, the induced current stops immediately as there is no longer a changing magnetic flux.
Correct Answer: B — It stops immediately
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Q. What happens to the induced current when the magnetic field through a loop is increased?
A.
The induced current flows in a direction to oppose the increase
B.
The induced current flows in the same direction as the increase
C.
The induced current becomes zero
D.
The induced current fluctuates
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Solution
According to Lenz's law, the induced current will flow in a direction that opposes the increase in magnetic flux.
Correct Answer: A — The induced current flows in a direction to oppose the increase
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Q. What happens to the induced EMF if the area of the coil is increased while the magnetic field strength remains constant?
A.
It increases
B.
It decreases
C.
It remains the same
D.
It becomes zero
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Solution
Increasing the area of the coil while keeping the magnetic field strength constant increases the magnetic flux through the coil, which according to Faraday's law increases the induced EMF.
Correct Answer: A — It increases
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Q. What happens to the induced EMF if the area of the loop in a uniform magnetic field is doubled while keeping the magnetic field constant?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It becomes zero
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Solution
If the area of the loop is doubled, the induced EMF will also double, as it is directly proportional to the area.
Correct Answer: A — It doubles
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Q. What happens to the induced EMF if the rate of change of magnetic flux is doubled?
A.
It remains the same
B.
It doubles
C.
It halves
D.
It quadruples
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Solution
According to Faraday's law, the induced EMF is directly proportional to the rate of change of magnetic flux. Therefore, if the rate is doubled, the induced EMF also doubles.
Correct Answer: B — It doubles
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Q. What happens to the induced EMF if the speed of a conductor moving through a magnetic field is doubled?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
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Solution
If the speed of the conductor is doubled, the rate of change of magnetic flux increases, thus the induced EMF also doubles.
Correct Answer: A — It doubles
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Q. What happens to the induced EMF when the area of a loop in a changing magnetic field is increased?
A.
Increases
B.
Decreases
C.
Remains constant
D.
Becomes zero
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Solution
According to Faraday's law, if the area of the loop is increased in a changing magnetic field, the induced EMF increases.
Correct Answer: A — Increases
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Q. What happens to the induced EMF when the area of a loop in a magnetic field is increased?
A.
Increases
B.
Decreases
C.
Remains constant
D.
Depends on the field strength
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Solution
According to Faraday's law, if the area of the loop is increased in a magnetic field, the induced EMF increases.
Correct Answer: A — Increases
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Q. What happens to the intensity of light when it passes through two polarizers aligned at 90 degrees to each other?
A.
It doubles
B.
It halves
C.
It becomes zero
D.
It remains the same
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Solution
When light passes through two polarizers at 90 degrees to each other, the intensity becomes zero because no light can pass through.
Correct Answer: C — It becomes zero
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Q. What happens to the intensity of light when it passes through two polarizers at an angle of 45 degrees?
A.
It is halved
B.
It is quartered
C.
It remains the same
D.
It doubles
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Solution
The intensity of light passing through two polarizers at an angle of 45 degrees is quartered.
Correct Answer: B — It is quartered
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Q. What happens to the interference pattern if one of the slits in a double-slit experiment is covered?
A.
Interference pattern disappears
B.
Pattern becomes brighter
C.
Pattern becomes dimmer
D.
Pattern becomes sharper
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Solution
Covering one slit eliminates the condition for interference, resulting in a single-slit diffraction pattern instead of an interference pattern.
Correct Answer: A — Interference pattern disappears
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Q. What happens to the interference pattern if the two slits in a double-slit experiment are no longer coherent?
A.
The pattern becomes sharper
B.
The pattern disappears
C.
The pattern becomes brighter
D.
The pattern remains unchanged
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Solution
If the two slits are not coherent, the interference pattern will disappear as the waves will not maintain a constant phase relationship.
Correct Answer: B — The pattern disappears
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Q. What happens to the interference pattern if the wavelength of light is increased?
A.
Fringe width decreases
B.
Fringe width increases
C.
Fringe pattern disappears
D.
Fringe width remains the same
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Solution
Increasing the wavelength increases the fringe width, as fringe width is directly proportional to the wavelength.
Correct Answer: B — Fringe width increases
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Q. What happens to the internal energy of a gas when it is allowed to expand freely into a vacuum?
A.
Increases
B.
Decreases
C.
Remains constant
D.
Depends on the initial temperature
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Solution
In free expansion, no work is done and no heat is exchanged, so the internal energy remains constant.
Correct Answer: C — Remains constant
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Q. What happens to the internal energy of an ideal gas during an isochoric process?
A.
It increases
B.
It decreases
C.
It remains constant
D.
It can either increase or decrease
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Solution
In an isochoric process, the volume remains constant, and any heat added to the system increases the internal energy of the gas.
Correct Answer: A — It increases
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Q. What happens to the internal energy of an ideal gas when it is compressed adiabatically?
A.
It increases
B.
It decreases
C.
It remains constant
D.
It depends on the initial temperature
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Solution
In an adiabatic compression, work is done on the gas, which increases its internal energy.
Correct Answer: A — It increases
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Q. What happens to the kinetic energy of emitted electrons if the frequency of incident light is increased beyond the threshold frequency?
A.
It decreases
B.
It remains constant
C.
It increases linearly with frequency
D.
It becomes zero
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Solution
The kinetic energy of emitted electrons increases linearly with the increase in frequency beyond the threshold frequency.
Correct Answer: C — It increases linearly with frequency
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Q. What happens to the light intensity when it passes through a polarizer at an angle of 60 degrees?
A.
It is halved
B.
It is reduced to one quarter
C.
It remains the same
D.
It is doubled
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Solution
The transmitted intensity is given by I = I_0 * cos²(θ), which results in one quarter of the original intensity at 60 degrees.
Correct Answer: B — It is reduced to one quarter
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