Major Competitive Exams
Q. What is the one-word substitution for 'a person who travels to unknown places'? (2023)
A.
Explorer
B.
Adventurer
C.
Voyager
D.
Navigator
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Solution
An explorer is someone who travels to discover new places.
Correct Answer: A — Explorer
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Q. What is the one-word substitution for 'a person who writes music'? (2023)
A.
Composer
B.
Lyricist
C.
Conductor
D.
Musician
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Solution
A composer is someone who creates and writes music.
Correct Answer: A — Composer
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Q. What is the one-word substitution for 'a person who writes plays'? (2020)
A.
Poet
B.
Novelist
C.
Dramatist
D.
Essayist
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Solution
A dramatist is a playwright, someone who writes plays.
Correct Answer: C — Dramatist
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Q. What is the opposite of 'benevolent'? (2023)
A.
malevolent
B.
kind
C.
generous
D.
charitable
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Solution
'Benevolent' means well-meaning and kindly, while 'malevolent' means having a wish to do evil.
Correct Answer: A — malevolent
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Q. What is the opposite of 'diligent'? (2023)
A.
lazy
B.
hardworking
C.
careful
D.
attentive
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Solution
'Diligent' means hardworking, so the opposite is 'lazy'.
Correct Answer: A — lazy
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Q. What is the opposite of 'optimistic'? (2023)
A.
pessimistic
B.
hopeful
C.
cheerful
D.
confident
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Solution
'Optimistic' means hopeful about the future, while 'pessimistic' means expecting the worst.
Correct Answer: A — pessimistic
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Q. What is the opposite of 'transparent'? (2023)
A.
Clear
B.
Opaque
C.
Visible
D.
Lucid
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Solution
'Transparent' means allowing light to pass through, while 'opaque' means not able to be seen through.
Correct Answer: B — Opaque
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Q. What is the orbital speed of a satellite in a circular orbit at a height h above the Earth's surface?
A.
sqrt(GM/R^2)
B.
sqrt(GM/(R+h)^2)
C.
sqrt(GM/(R-h)^2)
D.
sqrt(GM/R)
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Solution
The orbital speed v of a satellite in a circular orbit is given by v = sqrt(GM/(R+h)^2), where G is the gravitational constant, M is the mass of the Earth, R is the radius of the Earth, and h is the height of the satellite above the Earth's surface.
Correct Answer: B — sqrt(GM/(R+h)^2)
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Q. What is the orbital speed of a satellite in a low Earth orbit (LEO) approximately 2000 km above the Earth's surface? (2000)
A.
7.9 km/s
B.
11.2 km/s
C.
5.0 km/s
D.
3.0 km/s
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Solution
The orbital speed of a satellite in low Earth orbit is approximately 7.9 km/s.
Correct Answer: A — 7.9 km/s
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Q. What is the order of a matrix with 3 rows and 4 columns? (2021)
A.
3x4
B.
4x3
C.
3x3
D.
4x4
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Solution
The order of a matrix is given by the number of rows followed by the number of columns. Therefore, a matrix with 3 rows and 4 columns is of order 3x4.
Correct Answer: A — 3x4
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Q. What is the order of the first bright fringe in a single-slit diffraction pattern?
A.
m = 0
B.
m = 1
C.
m = 2
D.
m = 3
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Solution
In single-slit diffraction, the central maximum corresponds to m = 0, which is the first bright fringe.
Correct Answer: A — m = 0
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Q. What is the order of the reaction if the rate constant has the unit L/mol·s?
A.
Zero order
B.
First order
C.
Second order
D.
Third order
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Solution
If the rate constant has the unit L/mol·s, the reaction is second order.
Correct Answer: C — Second order
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Q. What is the osmotic pressure of a 0.2 M NaCl solution at 25 °C? (R = 0.0821 L atm/(K mol))
A.
4.92 atm
B.
2.46 atm
C.
1.23 atm
D.
0.61 atm
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Solution
Osmotic pressure = iCRT = 2 * 0.2 * 0.0821 * 298 = 4.92 atm (i = 2 for NaCl)
Correct Answer: A — 4.92 atm
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Q. What is the osmotic pressure of a solution containing 0.1 moles of glucose in 1 liter of solution at 25 °C? (R = 0.0821 L atm/K mol) (2020)
A.
2.06 atm
B.
0.82 atm
C.
1.01 atm
D.
0.25 atm
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Solution
Osmotic pressure (π) = nRT/V = (0.1 mol)(0.0821 L atm/K mol)(298 K) = 2.06 atm.
Correct Answer: A — 2.06 atm
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Q. What is the osmotic pressure of a solution containing 0.2 moles of solute in 1 liter of solution at 25 °C? (R = 0.0821 L·atm/(K·mol))
A.
4.92 atm
B.
1.64 atm
C.
0.82 atm
D.
2.46 atm
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Solution
Osmotic pressure = (n/V)RT = (0.2/1) * 0.0821 * 298 = 4.92 atm.
Correct Answer: A — 4.92 atm
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Q. What is the osmotic pressure of a solution containing 0.5 moles of glucose in 1 liter of solution at 25 °C? (R = 0.0821 L·atm/(K·mol))
A.
12.3 atm
B.
0.5 atm
C.
1.0 atm
D.
2.5 atm
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Solution
Osmotic pressure (π) = nRT/V = (0.5 mol)(0.0821 L·atm/(K·mol))(298 K) = 12.3 atm.
Correct Answer: A — 12.3 atm
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Q. What is the osmotic pressure of a solution containing 0.5 moles of glucose in 1 L of solution at 25 °C? (R = 0.0821 L·atm/(K·mol))
A.
12.3 atm
B.
10.2 atm
C.
8.2 atm
D.
6.1 atm
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Solution
Osmotic pressure (π) = nRT/V = (0.5 moles)(0.0821 L·atm/(K·mol))(298 K) = 12.3 atm.
Correct Answer: A — 12.3 atm
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Q. What is the osmotic pressure of a solution containing 0.5 moles of glucose in 1 liter of water at 25 °C?
A.
12.3 atm
B.
24.6 atm
C.
6.1 atm
D.
3.1 atm
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Solution
Osmotic pressure (π) = iCRT = 1 * 0.5 * 0.0821 * 298 = 12.3 atm.
Correct Answer: A — 12.3 atm
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Q. What is the osmotic pressure of a solution containing 0.5 moles of glucose in 1 L of water at 25 °C? (R = 0.0821 L·atm/(K·mol))
A.
12.3 atm
B.
1.23 atm
C.
0.5 atm
D.
2.5 atm
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Solution
Osmotic pressure (π) = nRT/V = (0.5 moles * 0.0821 * 298) / 1 = 12.3 atm.
Correct Answer: B — 1.23 atm
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Q. What is the osmotic pressure of a solution containing 0.5 moles of glucose in 2 liters of solution at 25 °C? (R = 0.0821 L·atm/(K·mol))
A.
6.13 atm
B.
12.26 atm
C.
3.07 atm
D.
1.54 atm
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Solution
Osmotic pressure (π) = nRT/V = (0.5 moles)(0.0821 L·atm/(K·mol))(298 K) / 2 L = 6.13 atm.
Correct Answer: A — 6.13 atm
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Q. What is the osmotic pressure of a solution containing 0.5 moles of glucose in 2 liters of solution? (R = 0.0821 L·atm/(K·mol), T = 298 K)
A.
6.14 atm
B.
12.28 atm
C.
3.07 atm
D.
1.54 atm
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Solution
Osmotic pressure (π) = (n/V)RT = (0.5/2) * 0.0821 * 298 = 6.14 atm.
Correct Answer: A — 6.14 atm
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Q. What is the osmotic pressure of a solution containing 0.5 moles of solute in 1 liter of solution at 25 °C? (R = 0.0821 L·atm/(K·mol)) (2021)
A.
12.3 atm
B.
10.2 atm
C.
8.2 atm
D.
6.1 atm
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Solution
Osmotic pressure (π) = nRT/V = (0.5 moles * 0.0821 L·atm/(K·mol) * 298 K) / 1 L = 12.3 atm.
Correct Answer: B — 10.2 atm
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Q. What is the osmotic pressure of a solution containing 0.5 moles of solute in 2 liters of solution at 25 °C? (R = 0.0821 L·atm/(K·mol))
A.
10.25 atm
B.
5.12 atm
C.
2.03 atm
D.
1.23 atm
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Solution
Osmotic pressure (π) = nRT/V = (0.5 moles * 0.0821 * 298) / 2 = 12.21 atm.
Correct Answer: B — 5.12 atm
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Q. What is the osmotic pressure of a solution containing 1 mole of glucose in 2 liters of solution at 25 °C? (R = 0.0821 L·atm/(K·mol))
A.
0.41 atm
B.
0.82 atm
C.
1.23 atm
D.
1.64 atm
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Solution
Osmotic pressure (π) = nRT/V = (1 mol)(0.0821 L·atm/(K·mol))(298 K) / 2 L = 0.82 atm.
Correct Answer: B — 0.82 atm
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Q. What is the osmotic pressure of a solution containing 2 moles of glucose in 1 liter of solution at 25 °C? (2021)
A.
0.0821 atm
B.
1.0 atm
C.
2.0 atm
D.
4.0 atm
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Solution
Osmotic pressure (π) = iCRT = 1 * 2 * 0.0821 * 298 = 4.0 atm (i = 1 for glucose).
Correct Answer: C — 2.0 atm
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Q. What is the osmotic pressure of a solution directly proportional to?
A.
Temperature
B.
Concentration of solute
C.
Volume of solvent
D.
Both A and B
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Solution
Osmotic pressure is directly proportional to both the temperature and the concentration of solute.
Correct Answer: D — Both A and B
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Q. What is the outermost layer of a plant stem called? (2022)
A.
Cortex
B.
Epidermis
C.
Phloem
D.
Xylem
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Solution
The outermost layer of a plant stem is called the epidermis, which protects the plant from environmental damage.
Correct Answer: B — Epidermis
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Q. What is the outermost whorl of a flower called? (2023)
A.
Calyx
B.
Corolla
C.
Androecium
D.
Gynoecium
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Solution
The outermost whorl of a flower is called the calyx, which is made up of sepals.
Correct Answer: A — Calyx
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Q. What is the output of a NAND gate when both inputs are high?
A.
0
B.
1
C.
Undefined
D.
Depends on the circuit
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Solution
A NAND gate outputs 0 only when both inputs are 1. Therefore, if both inputs are high (1), the output is 0.
Correct Answer: A — 0
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Q. What is the output of a NAND gate when both inputs are true?
A.
True
B.
False
C.
Undefined
D.
Depends on the circuit
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Solution
A NAND gate outputs false when both inputs are true.
Correct Answer: B — False
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