What is the osmotic pressure of a solution containing 0.5 moles of glucose in 2 liters of solution? (R = 0.0821 L·atm/(K·mol), T = 298 K)

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Q: What is the osmotic pressure of a solution containing 0.5 moles of glucose in 2 liters of solution? (R = 0.0821 L·atm/(K·mol), T = 298 K)

Solution: Osmotic pressure (π) = (n/V)RT = (0.5/2) * 0.0821 * 298 = 6.14 atm.

Steps: 6

Step 1: Identify the formula for osmotic pressure, which is π = (n/V)RT.
Step 2: Determine the values needed for the formula: n (number of moles) = 0.5, V (volume in liters) = 2, R (gas constant) = 0.0821 L·atm/(K·mol), and T (temperature in Kelvin) = 298.
Step 3: Calculate the concentration (n/V) by dividing the number of moles (0.5) by the volume (2): 0.5 / 2 = 0.25 moles/L.
Step 4: Multiply the concentration (0.25) by R (0.0821) and T (298): 0.25 * 0.0821 * 298.
Step 5: Perform the multiplication: 0.25 * 0.0821 = 0.020525, then 0.020525 * 298 = 6.14.
Step 6: The final result is the osmotic pressure, which is 6.14 atm.