Q. For a solenoid of length L, radius R, and carrying current I, what is the magnetic field inside the solenoid?
A.
μ₀nI
B.
μ₀I/L
C.
μ₀I/2L
D.
μ₀I/4L
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Solution
Using Ampere's Law, B = μ₀nI where n is the number of turns per unit length.
Correct Answer: A — μ₀nI
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Q. For a solid disk of mass M and radius R, what is the moment of inertia about an axis perpendicular to the disk and passing through its center?
A.
1/2 MR^2
B.
1/4 MR^2
C.
MR^2
D.
3/4 MR^2
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Solution
The moment of inertia of a solid disk about an axis through its center is I = 1/2 MR^2.
Correct Answer: A — 1/2 MR^2
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Q. For a solid disk of mass M and radius R, what is the moment of inertia about an axis through its center and perpendicular to its plane?
A.
1/2 MR^2
B.
1/4 MR^2
C.
MR^2
D.
3/4 MR^2
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Solution
The moment of inertia of a solid disk about an axis through its center is I = 1/2 MR^2.
Correct Answer: A — 1/2 MR^2
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Q. For a solution containing 2 components A and B, if the mole fraction of A is 0.6, what is the vapor pressure of the solution if the vapor pressure of pure A is 100 mmHg?
A.
60 mmHg
B.
100 mmHg
C.
40 mmHg
D.
80 mmHg
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Solution
According to Raoult's Law, the vapor pressure of the solution is P_A = X_A * P_A^0 = 0.6 * 100 mmHg = 60 mmHg.
Correct Answer: D — 80 mmHg
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Q. For a solution to obey Raoult's Law, the interactions between solute and solvent must be:
A.
Stronger than those in the pure components.
B.
Weaker than those in the pure components.
C.
Similar to those in the pure components.
D.
Non-existent.
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Solution
For a solution to obey Raoult's Law, the interactions between solute and solvent must be similar to those in the pure components.
Correct Answer: C — Similar to those in the pure components.
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Q. For a spherical Gaussian surface of radius R enclosing a charge Q, what is the electric field at a distance 2R from the center?
A.
Q/4πε₀(2R)²
B.
Q/4πε₀R²
C.
Q/4πε₀(2R)³
D.
0
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Solution
The electric field outside a spherical charge distribution behaves as if all the charge were concentrated at the center, so E = Q/4πε₀r².
Correct Answer: A — Q/4πε₀(2R)²
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Q. For a spontaneous process, the change in entropy of the universe must be:
A.
Zero
B.
Positive
C.
Negative
D.
Undefined
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Solution
For a spontaneous process, the total entropy change of the universe (system + surroundings) must be positive.
Correct Answer: B — Positive
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Q. For a spontaneous process, the change in Gibbs free energy (ΔG) is related to entropy (ΔS) by which of the following equations?
A.
ΔG = ΔH + TΔS
B.
ΔG = ΔH - TΔS
C.
ΔG = TΔS - ΔH
D.
ΔG = ΔS - ΔH
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Solution
The correct relationship is ΔG = ΔH - TΔS, where ΔG must be negative for a spontaneous process.
Correct Answer: B — ΔG = ΔH - TΔS
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Q. For a spontaneous process, the change in Gibbs free energy (ΔG) is related to entropy (ΔS) how?
A.
ΔG = ΔH - TΔS
B.
ΔG = TΔS - ΔH
C.
ΔG = ΔS - ΔH
D.
ΔG = ΔH + TΔS
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Solution
The relationship is given by ΔG = ΔH - TΔS, where ΔG must be negative for a spontaneous process.
Correct Answer: A — ΔG = ΔH - TΔS
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Q. For a spontaneous process, the change in Gibbs free energy (ΔG) is:
A.
Positive
B.
Negative
C.
Zero
D.
Undefined
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Solution
For a process to be spontaneous, the change in Gibbs free energy (ΔG) must be negative.
Correct Answer: B — Negative
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Q. For a system of particles, how is the moment of inertia calculated?
A.
Sum of individual moments
B.
Product of mass and distance squared
C.
Sum of mass times distance squared
D.
Average of all moments
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Solution
The moment of inertia for a system of particles is calculated as I = Σ(m_i * r_i^2), where m_i is the mass and r_i is the distance from the axis.
Correct Answer: C — Sum of mass times distance squared
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Q. For a system of particles, the moment of inertia is calculated as the sum of the products of mass and the square of the distance from the axis of rotation. This is known as:
A.
Parallel Axis Theorem
B.
Perpendicular Axis Theorem
C.
Rotational Dynamics
D.
Angular Momentum
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Solution
This is known as the Parallel Axis Theorem, which states that I = Σ(m_i * r_i^2).
Correct Answer: A — Parallel Axis Theorem
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Q. For a system of particles, the moment of inertia is calculated by summing which of the following?
A.
Masses only
B.
Distances only
C.
Mass times distance squared
D.
Mass times distance
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Solution
The moment of inertia is calculated by summing the products of mass and the square of the distance from the axis of rotation.
Correct Answer: C — Mass times distance squared
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Q. For a system of particles, the total moment of inertia is calculated by which of the following methods?
A.
Adding individual moments of inertia
B.
Multiplying total mass by average distance
C.
Using the parallel axis theorem
D.
Using the perpendicular axis theorem
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Solution
The total moment of inertia for a system of particles is calculated by adding the individual moments of inertia.
Correct Answer: A — Adding individual moments of inertia
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Q. For a system of particles, the total moment of inertia is calculated by which of the following?
A.
Sum of individual moments
B.
Product of mass and distance
C.
Sum of mass times distance squared
D.
Average of individual moments
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Solution
The total moment of inertia for a system of particles is the sum of each particle's moment of inertia, I_total = Σ(m_i * r_i^2).
Correct Answer: C — Sum of mass times distance squared
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Q. For a thin circular ring of mass M and radius R, what is the moment of inertia about an axis perpendicular to its plane through its center?
A.
MR^2
B.
1/2 MR^2
C.
2/3 MR^2
D.
1/3 MR^2
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Solution
The moment of inertia of a thin circular ring about an axis through its center and perpendicular to its plane is I = MR^2.
Correct Answer: A — MR^2
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Q. For a toroidal solenoid with N turns and radius R carrying current I, what is the magnetic field inside the toroid?
A.
μ₀NI/2πR
B.
μ₀NI/R
C.
μ₀NI/4πR
D.
μ₀NI/2R
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Solution
The magnetic field inside a toroid is given by B = μ₀NI/2πR.
Correct Answer: B — μ₀NI/R
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Q. For a uniformly charged sphere of radius R and total charge Q, what is the electric field at a distance r from the center where r > R?
A.
Q/(4πε₀r²)
B.
0
C.
Q/(4πε₀R²)
D.
Q/(4πε₀r)
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Solution
For r > R, the electric field behaves as if all the charge were concentrated at the center, given by E = Q/(4πε₀r²).
Correct Answer: A — Q/(4πε₀r²)
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Q. For a zero-order reaction, how does the rate change with concentration?
A.
Increases linearly
B.
Decreases linearly
C.
Remains constant
D.
Increases exponentially
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Solution
In a zero-order reaction, the rate is constant and does not depend on the concentration of reactants.
Correct Answer: C — Remains constant
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Q. For a zero-order reaction, how does the rate change with respect to concentration?
A.
Increases linearly
B.
Decreases linearly
C.
Remains constant
D.
Increases exponentially
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Solution
In a zero-order reaction, the rate is constant and does not depend on the concentration of the reactants.
Correct Answer: C — Remains constant
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Q. For an electron in a 3d orbital, what are the possible values of l?
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Solution
For d orbitals, the azimuthal quantum number l = 2.
Correct Answer: C — 2
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Q. For an electron in a 3d orbital, what are the possible values of m_l?
A.
-2, -1, 0, 1, 2
B.
-1, 0, 1
C.
0, 1
D.
0, 1, 2
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Solution
For l=2 (d orbital), m_l can take values from -l to +l, which are -2, -1, 0, 1, 2.
Correct Answer: A — -2, -1, 0, 1, 2
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Q. For an electron in a 3p orbital, what are the possible values of m_l?
A.
-1, 0, +1
B.
0, +1, +2
C.
-2, -1, 0
D.
0, -1, -2
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Solution
For a p orbital, l=1, so m_l can take values -1, 0, +1.
Correct Answer: A — -1, 0, +1
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Q. For an electron in a 3p orbital, what are the possible values of m_s?
A.
-1/2, +1/2
B.
0, +1
C.
1, 2
D.
-1, 0, +1
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Solution
The spin quantum number (m_s) can take values of -1/2 and +1/2.
Correct Answer: A — -1/2, +1/2
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Q. For an electron in a 3p orbital, what are the possible values of the magnetic quantum number (m_l)?
A.
-1, 0, +1
B.
0, +1, +2
C.
-2, -1, 0
D.
1, 2, 3
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Solution
For a p orbital (l=1), m_l can take values -1, 0, +1.
Correct Answer: A — -1, 0, +1
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Q. For an electron in a 5d orbital, what are the possible values of m_l?
A.
-2, -1, 0, 1, 2
B.
-3, -2, -1, 0, 1, 2, 3
C.
0, 1, 2
D.
-1, 0, 1
Show solution
Solution
For l=2 (d orbital), m_l can take values from -2 to +2, which are -2, -1, 0, 1, 2.
Correct Answer: A — -2, -1, 0, 1, 2
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Q. For an ideal gas, if the temperature is increased, what happens to the RMS speed?
A.
Increases
B.
Decreases
C.
Remains constant
D.
Depends on the gas
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Solution
The RMS speed increases with temperature as v_rms = sqrt(3RT/M) shows that it is directly proportional to the square root of temperature T.
Correct Answer: A — Increases
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Q. For an ideal gas, if the volume is halved while keeping the temperature constant, what happens to the pressure?
A.
It remains the same
B.
It doubles
C.
It halves
D.
It quadruples
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Solution
According to Boyle's law, for a given mass of gas at constant temperature, the pressure is inversely proportional to the volume. Halving the volume will double the pressure.
Correct Answer: B — It doubles
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Q. For an ideal gas, the equation of state is given by:
A.
PV = nRT
B.
PV = NkT
C.
PV = mRT
D.
PV = kT
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Solution
The equation of state for an ideal gas is given by PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature.
Correct Answer: A — PV = nRT
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Q. For an ideal gas, which equation relates pressure, volume, and temperature?
A.
PV = nRT
B.
PV = nR
C.
PV = RT
D.
PV = nT
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Solution
The ideal gas law is given by the equation PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature.
Correct Answer: A — PV = nRT
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