Q. For a given mass, which of the following configurations will have the smallest moment of inertia?
A.
All mass at the center
B.
Mass distributed evenly
C.
Mass at the edge
D.
Mass concentrated at one end
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Solution
The moment of inertia is smallest when all mass is concentrated at the center, as it minimizes the distance from the axis of rotation.
Correct Answer: A — All mass at the center
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Q. For a hollow sphere of mass M and radius R, what is the moment of inertia about an axis through its center?
A.
2/5 MR^2
B.
3/5 MR^2
C.
2/3 MR^2
D.
MR^2
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Solution
The moment of inertia of a hollow sphere about an axis through its center is I = 2/5 MR^2.
Correct Answer: B — 3/5 MR^2
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Q. For a monoatomic ideal gas, the RMS speed is given by which of the following expressions?
A.
sqrt((3kT)/m)
B.
sqrt((3RT)/M)
C.
Both of the above
D.
None of the above
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Solution
Both expressions are valid for calculating the RMS speed of a monoatomic ideal gas.
Correct Answer: C — Both of the above
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Q. For a point charge, the electric field varies with distance r as?
A.
1/r
B.
1/r²
C.
1/r³
D.
1/r⁴
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Solution
The electric field due to a point charge varies as E = kQ/r², where k is a constant.
Correct Answer: B — 1/r²
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Q. For a process to be reversible, it must be:
A.
Fast
B.
Quasi-static
C.
Adiabatic
D.
Isochoric
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Solution
A reversible process must be quasi-static, meaning it occurs infinitely slowly.
Correct Answer: B — Quasi-static
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Q. For a process with ΔH = 200 kJ and ΔS = 0.5 kJ/K, what is ΔG at 400 K?
A.
200 kJ
B.
180 kJ
C.
220 kJ
D.
160 kJ
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Solution
ΔG = ΔH - TΔS = 200 kJ - 400 K * 0.5 kJ/K = 200 kJ - 200 kJ = 0 kJ.
Correct Answer: B — 180 kJ
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Q. For a reaction A → B, if the rate of formation of B is 0.5 mol/L/s, what is the rate of disappearance of A?
A.
0.5 mol/L/s
B.
1.0 mol/L/s
C.
0.25 mol/L/s
D.
2.0 mol/L/s
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Solution
The rate of disappearance of A is equal to the rate of formation of B, multiplied by the stoichiometric coefficients. Here, it is 1.0 mol/L/s.
Correct Answer: B — 1.0 mol/L/s
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Q. For a reaction A → B, if the rate of reaction doubles when the concentration of A is doubled, what is the order of the reaction with respect to A?
A.
Zero order
B.
First order
C.
Second order
D.
Third order
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Solution
If doubling the concentration of A doubles the rate, the reaction is first order with respect to A.
Correct Answer: B — First order
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Q. For a reaction at constant temperature and pressure, which of the following is true?
A.
ΔG = ΔH + TΔS
B.
ΔG = ΔH - TΔS
C.
ΔG = TΔS - ΔH
D.
ΔG = ΔS - ΔH
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Solution
The correct relationship at constant temperature and pressure is ΔG = ΔH - TΔS.
Correct Answer: B — ΔG = ΔH - TΔS
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Q. For a reaction at equilibrium, if the concentration of products increases, what will happen to the equilibrium position?
A.
Shift to the left
B.
Shift to the right
C.
No change
D.
Depends on temperature
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Solution
According to Le Chatelier's principle, if the concentration of products increases, the equilibrium will shift to the left.
Correct Answer: A — Shift to the left
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Q. For a reaction at equilibrium, the change in Gibbs free energy (ΔG) is equal to:
A.
ΔH - TΔS
B.
0
C.
ΔS - TΔH
D.
ΔH + TΔS
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Solution
At equilibrium, the change in Gibbs free energy (ΔG) is zero, indicating that the system is at maximum entropy.
Correct Answer: B — 0
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Q. For a reaction at standard conditions, if ΔG° is negative, what can be said about the equilibrium constant (K)?
A.
K < 1
B.
K = 1
C.
K > 1
D.
K is undefined
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Solution
If ΔG° is negative, the equilibrium constant K is greater than 1.
Correct Answer: C — K > 1
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Q. For a reaction at standard conditions, if ΔG° is positive, what can be said about the reaction?
A.
The reaction is spontaneous in the forward direction.
B.
The reaction is spontaneous in the reverse direction.
C.
The reaction is at equilibrium.
D.
The reaction is impossible.
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Solution
A positive ΔG° indicates that the reaction is non-spontaneous in the forward direction, thus spontaneous in the reverse.
Correct Answer: B — The reaction is spontaneous in the reverse direction.
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Q. For a reaction at standard conditions, if ΔG° is positive, what does it imply?
A.
The reaction is spontaneous in the forward direction.
B.
The reaction is at equilibrium.
C.
The reaction is non-spontaneous in the forward direction.
D.
The reaction will proceed rapidly.
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Solution
A positive ΔG° indicates that the reaction is non-spontaneous in the forward direction under standard conditions.
Correct Answer: C — The reaction is non-spontaneous in the forward direction.
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Q. For a reaction at standard conditions, if ΔG° is positive, what does it indicate?
A.
The reaction is spontaneous in the forward direction.
B.
The reaction is non-spontaneous in the forward direction.
C.
The reaction is at equilibrium.
D.
The reaction is spontaneous in the reverse direction.
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Solution
A positive ΔG° indicates that the reaction is non-spontaneous in the forward direction.
Correct Answer: B — The reaction is non-spontaneous in the forward direction.
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Q. For a reaction with a rate constant k, what is the relationship between the rate of reaction and the concentration of reactants for a first-order reaction?
A.
Rate = k[A]^2
B.
Rate = k[A]
C.
Rate = k[A]^3
D.
Rate = k[A]^0
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Solution
For a first-order reaction, the rate of reaction is directly proportional to the concentration of the reactant, given by Rate = k[A].
Correct Answer: B — Rate = k[A]
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Q. For a reaction with ΔH = 100 kJ and ΔS = 200 J/K, at what temperature will the reaction become spontaneous?
A.
500 K
B.
250 K
C.
200 K
D.
100 K
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Solution
To find the temperature at which the reaction becomes spontaneous, set ΔG = 0: 0 = ΔH - TΔS. Thus, T = ΔH/ΔS = (100,000 J)/(200 J/K) = 500 K.
Correct Answer: A — 500 K
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Q. For a reaction with ΔH = 100 kJ/mol and ΔS = 200 J/mol·K, at what temperature will the reaction become spontaneous?
A.
500 K
B.
250 K
C.
200 K
D.
100 K
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Solution
To find the temperature at which the reaction becomes spontaneous, set ΔG = 0: 0 = ΔH - TΔS, thus T = ΔH/ΔS = 100,000 J / 200 J/K = 500 K.
Correct Answer: A — 500 K
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Q. For a reaction with ΔH = 50 kJ/mol and ΔS = 100 J/mol·K, at what temperature will the reaction become spontaneous?
A.
500 K
B.
250 K
C.
1000 K
D.
200 K
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Solution
To find the temperature at which the reaction becomes spontaneous, set ΔG = 0: 0 = ΔH - TΔS, thus T = ΔH/ΔS = (50,000 J/mol) / (100 J/mol·K) = 500 K.
Correct Answer: A — 500 K
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Q. For a rectangular plate of mass M and dimensions a x b, what is the moment of inertia about an axis through its center and parallel to side a?
A.
1/12 Mb^2
B.
1/3 Mb^2
C.
1/4 Mb^2
D.
1/6 Mb^2
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Solution
The moment of inertia of a rectangular plate about an axis through its center parallel to side a is I = 1/12 Mb^2.
Correct Answer: A — 1/12 Mb^2
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Q. For a reversible process, the change in entropy is given by which of the following?
A.
ΔS = Q/T
B.
ΔS = W/T
C.
ΔS = Q + W
D.
ΔS = 0
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Solution
For a reversible process, the change in entropy is given by ΔS = Q/T, where Q is the heat exchanged and T is the temperature.
Correct Answer: A — ΔS = Q/T
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Q. For a reversible process, the change in entropy of the system is equal to the heat absorbed divided by the temperature. What is the formula?
A.
ΔS = Q/T
B.
ΔS = T/Q
C.
ΔS = Q*T
D.
ΔS = Q + T
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Solution
The change in entropy (ΔS) for a reversible process is given by ΔS = Q/T, where Q is the heat absorbed and T is the temperature.
Correct Answer: A — ΔS = Q/T
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Q. For a reversible process, the change in entropy of the system is equal to the heat absorbed divided by the temperature. This is expressed as:
A.
ΔS = Q/T
B.
ΔS = T/Q
C.
ΔS = Q + T
D.
ΔS = Q - T
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Solution
For a reversible process, the change in entropy (ΔS) is given by ΔS = Q/T, where Q is the heat absorbed and T is the temperature.
Correct Answer: A — ΔS = Q/T
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Q. For a reversible process, the change in entropy of the universe is:
A.
Zero
B.
Positive
C.
Negative
D.
Undefined
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Solution
For a reversible process, the change in entropy of the universe is zero, as the system and surroundings are in equilibrium.
Correct Answer: A — Zero
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Q. For a reversible process, the efficiency of a Carnot engine is given by which formula?
A.
1 - (T2/T1)
B.
T1/T2
C.
T2/T1
D.
1 - (T1/T2)
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Solution
The efficiency of a Carnot engine is given by η = 1 - (T2/T1), where T1 is the temperature of the hot reservoir and T2 is the temperature of the cold reservoir.
Correct Answer: A — 1 - (T2/T1)
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Q. For a satellite in a circular orbit, which of the following is true about its kinetic and potential energy?
A.
K.E. = P.E.
B.
K.E. > P.E.
C.
K.E. < P.E.
D.
K.E. = 0
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Solution
For a satellite in a circular orbit, the kinetic energy is less than the potential energy, as K.E. = -1/2 P.E.
Correct Answer: C — K.E. < P.E.
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Q. For a satellite in a low Earth orbit, what is the approximate altitude range? (2000)
A.
200-2000 km
B.
500-10000 km
C.
1000-20000 km
D.
30000-40000 km
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Solution
Low Earth orbit satellites typically operate at altitudes ranging from about 200 km to 2000 km above the Earth's surface.
Correct Answer: A — 200-2000 km
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Q. For a satellite in a stable orbit, what must be true about the centripetal force and gravitational force?
A.
Centripetal force is greater than gravitational force
B.
Centripetal force is less than gravitational force
C.
Centripetal force equals gravitational force
D.
Centripetal force is independent of gravitational force
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Solution
For a satellite in a stable orbit, the centripetal force required for circular motion equals the gravitational force acting on the satellite.
Correct Answer: C — Centripetal force equals gravitational force
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Q. For a single slit of width 'a', what is the angular position of the first minimum?
A.
λ/a
B.
a/λ
C.
sin θ = λ/a
D.
tan θ = λ/a
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Solution
The angular position of the first minimum is given by sin θ = λ/a.
Correct Answer: C — sin θ = λ/a
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Q. For a solenoid of length L and n turns per unit length carrying current I, what is the magnetic field inside the solenoid?
A.
μ₀nI
B.
μ₀I/n
C.
μ₀I/L
D.
μ₀nI/L
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Solution
The magnetic field inside a solenoid is given by B = μ₀nI.
Correct Answer: A — μ₀nI
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