Q. For a charged spherical conductor, what happens to the electric field inside the conductor when it is charged?
A.
Increases
B.
Decreases
C.
Remains constant
D.
Becomes zero
Show solution
Solution
The electric field inside a charged conductor in electrostatic equilibrium is zero.
Correct Answer: D — Becomes zero
Learn More →
Q. For a circular loop of radius R carrying a current I, what is the magnetic field at the center of the loop?
A.
B = μ₀I/(2R)
B.
B = μ₀I/(4R)
C.
B = μ₀I/(πR)
D.
B = μ₀I/(2πR)
Show solution
Solution
The magnetic field at the center of a circular loop of radius R carrying current I is given by B = μ₀I/(2πR).
Correct Answer: D — B = μ₀I/(2πR)
Learn More →
Q. For a closed loop of wire carrying current, what does the line integral of the magnetic field equal?
A.
Zero
B.
The product of current and resistance
C.
μ₀ times the total current enclosed
D.
The electric field times the area
Show solution
Solution
According to Ampere's Law, the line integral of the magnetic field around a closed loop equals μ₀ times the total current enclosed by the loop.
Correct Answer: C — μ₀ times the total current enclosed
Learn More →
Q. For a closed surface enclosing multiple charges, how is the total electric flux related to the enclosed charges?
A.
It is proportional to the sum of the charges
B.
It is inversely proportional to the sum of the charges
C.
It is independent of the charges
D.
It is proportional to the square of the charges
Show solution
Solution
According to Gauss's law, the total electric flux through a closed surface is proportional to the total charge enclosed.
Correct Answer: A — It is proportional to the sum of the charges
Learn More →
Q. For a closed surface enclosing multiple charges, how is the total electric flux calculated?
A.
Sum of individual fluxes
B.
Product of charges
C.
Sum of enclosed charges divided by ε₀
D.
Average of charges
Show solution
Solution
The total electric flux through a closed surface is given by Φ = ΣQ_enc/ε₀, where Q_enc is the total charge enclosed.
Correct Answer: C — Sum of enclosed charges divided by ε₀
Learn More →
Q. For a composite body made of a solid cylinder and a solid sphere, how do you calculate the total moment of inertia about the same axis?
A.
Add the individual moments
B.
Multiply the individual moments
C.
Subtract the individual moments
D.
Divide the individual moments
Show solution
Solution
The total moment of inertia of a composite body about the same axis is the sum of the individual moments of inertia.
Correct Answer: A — Add the individual moments
Learn More →
Q. For a composite body made of two solid cylinders of mass M1 and M2 and radius R, what is the total moment of inertia about the same axis?
A.
I1 + I2
B.
I1 - I2
C.
I1 * I2
D.
I1 / I2
Show solution
Solution
The total moment of inertia of a composite body is the sum of the individual moments of inertia: I_total = I1 + I2.
Correct Answer: A — I1 + I2
Learn More →
Q. For a current-carrying loop, what is the magnetic field at the center if the radius is halved?
A.
It remains the same
B.
It doubles
C.
It quadruples
D.
It halves
Show solution
Solution
The magnetic field at the center of a loop is inversely proportional to the radius. If the radius is halved, the magnetic field quadruples.
Correct Answer: C — It quadruples
Learn More →
Q. For a cylindrical conductor of radius R carrying current I, what is the magnetic field at a point outside the cylinder?
A.
0
B.
μ₀I/2πr
C.
μ₀I/4πr
D.
μ₀I/πr
Show solution
Solution
For points outside the cylinder, B = μ₀I/2πr.
Correct Answer: B — μ₀I/2πr
Learn More →
Q. For a cylindrical conductor of radius R carrying current I, what is the magnetic field at a point outside the conductor?
A.
0
B.
μ₀I/2πR
C.
μ₀I/4πR
D.
μ₀I/πR
Show solution
Solution
Using Ampere's Law, B = μ₀I/2πR for points outside the cylindrical conductor.
Correct Answer: B — μ₀I/2πR
Learn More →
Q. For a damped oscillator, what is the relationship between the natural frequency and the damped frequency?
A.
Damped frequency is greater
B.
Damped frequency is equal
C.
Damped frequency is less
D.
No relationship
Show solution
Solution
The damped frequency is less than the natural frequency due to the effect of damping.
Correct Answer: C — Damped frequency is less
Learn More →
Q. For a diffraction grating with 500 lines per mm, what is the angle of the first order maximum for light of wavelength 600 nm?
A.
30 degrees
B.
45 degrees
C.
60 degrees
D.
15 degrees
Show solution
Solution
Using the grating equation d sin θ = nλ, where d = 1/500000 m, n = 1, and λ = 600 x 10^-9 m, we find θ ≈ 30 degrees.
Correct Answer: A — 30 degrees
Learn More →
Q. For a diffraction pattern produced by a single slit, how does the width of the central maximum change if the slit width is halved?
A.
Increases
B.
Decreases
C.
Remains the same
D.
Becomes zero
Show solution
Solution
If the slit width is halved, the width of the central maximum increases because the angle for the first minimum increases.
Correct Answer: A — Increases
Learn More →
Q. For a diffraction pattern produced by a single slit, how does the width of the central maximum compare to the other maxima?
A.
Wider than all other maxima
B.
Narrower than all other maxima
C.
Equal to all other maxima
D.
None of the above
Show solution
Solution
The central maximum in a single-slit diffraction pattern is wider than all other maxima.
Correct Answer: A — Wider than all other maxima
Learn More →
Q. For a first-order reaction, if the half-life is 10 minutes, what will be the half-life if the initial concentration is doubled?
A.
10 minutes
B.
5 minutes
C.
20 minutes
D.
15 minutes
Show solution
Solution
For a first-order reaction, the half-life is independent of the initial concentration. Therefore, it remains 10 minutes.
Correct Answer: A — 10 minutes
Learn More →
Q. For a first-order reaction, the half-life is independent of the initial concentration. What is the expression for half-life?
A.
t1/2 = 0.693/k
B.
t1/2 = k/0.693
C.
t1/2 = 1/k
D.
t1/2 = k/2
Show solution
Solution
For a first-order reaction, the half-life is given by the expression t1/2 = 0.693/k.
Correct Answer: A — t1/2 = 0.693/k
Learn More →
Q. For a first-order reaction, the half-life is independent of which of the following?
A.
Initial concentration
B.
Rate constant
C.
Temperature
D.
All of the above
Show solution
Solution
For a first-order reaction, the half-life is independent of the initial concentration.
Correct Answer: A — Initial concentration
Learn More →
Q. For a gas at 300 K, if the RMS speed is 500 m/s, what will be the RMS speed at 600 K?
A.
500 m/s
B.
707 m/s
C.
1000 m/s
D.
250 m/s
Show solution
Solution
RMS speed is proportional to the square root of temperature, so v_rms at 600 K = 500 * sqrt(600/300) = 707 m/s.
Correct Answer: B — 707 m/s
Learn More →
Q. For a gas at 300 K, what is the RMS speed if the molar mass is 0.028 kg/mol?
A.
500 m/s
B.
600 m/s
C.
700 m/s
D.
800 m/s
Show solution
Solution
Using v_rms = sqrt(3RT/M), we calculate v_rms = sqrt(3 * 8.314 * 300 / 0.028) which gives approximately 600 m/s.
Correct Answer: B — 600 m/s
Learn More →
Q. For a gas at a certain temperature, if the molar mass is halved, what happens to the RMS speed?
A.
Increases by a factor of 2
B.
Increases by a factor of sqrt(2)
C.
Decreases by a factor of 2
D.
Remains the same
Show solution
Solution
RMS speed is inversely proportional to the square root of molar mass. Halving the molar mass increases the RMS speed by a factor of sqrt(2).
Correct Answer: B — Increases by a factor of sqrt(2)
Learn More →
Q. For a gas at a constant temperature, if the molar mass is halved, what happens to the RMS speed?
A.
Increases by a factor of sqrt(2)
B.
Increases by a factor of 2
C.
Decreases by a factor of 2
D.
Remains the same
Show solution
Solution
The RMS speed is inversely proportional to the square root of the molar mass. If the molar mass is halved, the RMS speed increases by a factor of sqrt(2), which is approximately 1.414, but in terms of doubling the speed, it is considered to increase by a factor of 2.
Correct Answer: B — Increases by a factor of 2
Learn More →
Q. For a gas at constant pressure, if the volume is doubled, what happens to the temperature?
A.
It remains the same
B.
It doubles
C.
It halves
D.
It triples
Show solution
Solution
According to Charles's law, for a gas at constant pressure, if the volume is doubled, the temperature also doubles.
Correct Answer: B — It doubles
Learn More →
Q. For a gas at constant pressure, if the volume is halved, what happens to the temperature?
A.
It remains the same
B.
It doubles
C.
It is halved
D.
It is quartered
Show solution
Solution
According to Charles's law, for a gas at constant pressure, if the volume is halved, the temperature must also be halved.
Correct Answer: C — It is halved
Learn More →
Q. For a gas mixture, how is the RMS speed calculated?
A.
Using the average molar mass of the mixture
B.
Using the molar mass of the heaviest gas
C.
Using the molar mass of the lightest gas
D.
Using the molar mass of the most abundant gas
Show solution
Solution
The RMS speed for a gas mixture is calculated using the average molar mass of the mixture.
Correct Answer: A — Using the average molar mass of the mixture
Learn More →
Q. For a gas with a molar mass of 32 g/mol at 273 K, what is the RMS speed?
A.
300 m/s
B.
400 m/s
C.
500 m/s
D.
600 m/s
Show solution
Solution
Using v_rms = sqrt(3RT/M), we find v_rms = sqrt(3 * 8.314 * 273 / 0.032) = 300 m/s.
Correct Answer: A — 300 m/s
Learn More →
Q. For a gas with a molar mass of 32 g/mol at a temperature of 300 K, what is the RMS speed?
A.
273 m/s
B.
400 m/s
C.
500 m/s
D.
600 m/s
Show solution
Solution
Using the formula v_rms = sqrt((3RT)/M), where R = 8.314 J/(mol·K), M = 0.032 kg/mol, and T = 300 K, we find v_rms ≈ 400 m/s.
Correct Answer: B — 400 m/s
Learn More →
Q. For a gas with molar mass M at temperature T, what is the relationship between RMS speed and molar mass?
A.
v_rms is directly proportional to M
B.
v_rms is inversely proportional to M
C.
v_rms is independent of M
D.
v_rms is proportional to M^2
Show solution
Solution
The RMS speed is given by v_rms = sqrt((3RT)/M). This shows that v_rms is inversely proportional to the square root of the molar mass M.
Correct Answer: B — v_rms is inversely proportional to M
Learn More →
Q. For a gas with molar mass M, what is the relationship between RMS speed and molar mass?
A.
v_rms is directly proportional to M
B.
v_rms is inversely proportional to M
C.
v_rms is independent of M
D.
v_rms is proportional to M^2
Show solution
Solution
The RMS speed is inversely proportional to the square root of the molar mass (v_rms = sqrt((3RT)/M)). Thus, as molar mass increases, RMS speed decreases.
Correct Answer: B — v_rms is inversely proportional to M
Learn More →
Q. For a gas with molar mass M, what is the relationship between RMS speed and molecular mass?
A.
v_rms is directly proportional to M
B.
v_rms is inversely proportional to M
C.
v_rms is independent of M
D.
v_rms is proportional to M^2
Show solution
Solution
The RMS speed is inversely proportional to the square root of the molar mass (v_rms = sqrt((3RT)/M)). Thus, as molar mass increases, RMS speed decreases.
Correct Answer: B — v_rms is inversely proportional to M
Learn More →
Q. For a gas with molar mass M, what is the RMS speed at 300 K?
A.
sqrt(3RT/M)
B.
sqrt(2RT/M)
C.
RT/M
D.
3RT/M
Show solution
Solution
The RMS speed is calculated using v_rms = sqrt(3RT/M). At 300 K, you can substitute R and M to find the specific value.
Correct Answer: A — sqrt(3RT/M)
Learn More →
Showing 2221 to 2250 of 10700 (357 Pages)